- We can make a thermodynamically unfavorable reaction favorable by coupling it to a favorable reaction via an intermediate
- The sum of the two reactions will result in a reaction that overall has a negative ΔG° value.
- For example:
- The decomposition of copper(I) sulfide to produce copper as the desired product and sulfur is thermodynamically unfavorable
Cu2S (s) 2Cu (s) + S (s) ΔG° = +85.1 kJ mol-1 K < 1
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- The equilibrium constant is less than 1 which means there are more reactants than products at equilibrium so not much copper would be produced
- This reaction can be coupled to a thermodynamically favorable reaction such as the reaction between sulfur and oxygen to give sulfur dioxide
S (s) + O2 (g) SO2 (g) ΔG° = –301.4 kJ mol-1 K > 1
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- At equilibrium, the equilibrium constant is greater than 1 so there will be more products than reactants
- Coupling these two reactions will allow us to make a significant amount of copper because they share the common intermediate, sulfur
- Even if only a small amount, sulfur will still be produced in reaction 1 when copper(I) sulfide decomposes
- This will then be used up in reaction 2 by reacting with oxygen to produce sulfur dioxide
- Removing the sulfur from reaction 1 causes the equilibrium to shift to the right therefore producing more copper
- The thermodynamically favorable second reaction is driving the thermodynamically unfavorable reaction
- Adding the two reactions together, the sulfur will cancel out to give:
Cu2S (s) + O2 (g) 2Cu (s) + SO2 (g)
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- Adding the two ΔG°values together:
- +85.1 +(-301.4) = –216.3 kJmol-1
- A negative value shows now this overall reaction is thermodynamically favorable
- It will have an equilibrium constant of above 1
- Copper will be produced
- Coupling reactions are also used in the conversion of ATP to ADP in the body which helps drive protein synthesis
- Amino acids alanine and glycine will produce alanylglycine (a dipeptide) and water:
alanine + glycine alanylglycine + H2O ΔG° = +31 kJ mol-1
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- This is thermodynamically unfavorable due to the positive ΔG°
- The hydrolysis of ATP is thermodynamically favorable:
ATP + H2O ADP + Pi ΔG° = –33 kJmol-1
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- The reactions are coupled
- The water cancels out to give:
alanine + glycine + ATP alanylglycine + ADP + Pi
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- Adding the two ΔG° values together gives an overall ΔG° = –2 kJ mol-1
- The reaction is now thermodynamically favored