Introduction to Titration (College Board AP Chemistry)

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Determine the Concentration of an Analyte

  • One of the most important analytical techniques is titration
  • Titrations include
    • Acid-base titrations
    • Redox titrations
  • The most important glass equipment used in a titration is a burette
  • Titrations are used to determine the concentration of a chemical compound in an unknown sample
    • The unknown sample is called the analyte
  • The concentration of analyte is determined using a solution of known concentration that is able to react with the analyte
    • The solution of known concentration is called titrant
  • The burette is filled with the titrant, while the analyte is placed in a conical flask under the burette
  • The endpoint or equivalence point occurs when the moles of titrant have reacted completely with the moles of analyte
    • In most titrations indicator is placed in the analyte solution
    • The indicator is a substance that will change color near the endpoint of the titration

Common titration setup

common-setup-for-a-titration

Titration setup showing the titrant and the analyte. It is a good practice to fill the burette to 0.0 cm3 as shown in the diagram

How to perform a titration?

  1. Measure a known volume of analyte and place it into a conical flask
  2. Fill the burette with titrant. Remember that the titrant must be a solution of known concentration
  3. If necessary, add few drops of indicator in the conical flask
  4. Open the tap on the burette carefully and add the analyte portion by portion to the conical flask
    1. After each portion the conical flask must be swirled
  5. As you start getting near the endpoint, the portions should be added dropwise
  6. Close the burette tap when one drop has caused a permanent color change
  7. Record the volume of titrant used for the equivalence point. This volume will be used to determine the concentration of analyte

Determining the concentration of analyte

  • One of the most assessed calculations in AP Chemistry regarding titrations is determining the amount of analyte
  • The steps for this calculation are summarized in the following diagram

Steps for determining the concentration of analyte

steps-for-determinig-the-concentration-of-analyte

General steps that must be followed to determine the concentration of analyte using the volume recorded from the equivalence point of the titration

Worked example

A 30.0 mL HCl sample of unknown concentration was titrated using NaOH 0.150 M. A permanent color change was reached when adding 25.0 mL of titrant. Determine the concentration of the analyte. The balanced chemical equation is given below

HCl + NaOH → NaCl + H2O

Answer:

Step 1: Analyze the statement and set up the steps that you are going to use to solve the problem. The initial quantity is always given by the statement. Remember to start with the reactant or product that you have the most information about

Since, volume and molarity are given for sodium hydroxide (titrant), it must be the starting point

steps-for-determining-the-concentration-of-analyte-worked-example

Step 2: Calculate the moles of NaOH by transforming the volume of the equivalence point into L and using the molarity equation

25.0 space mL space of space solution space cross times space fraction numerator 1 space straight L over denominator 1000 space mL end fraction space equals space 0.0250 space straight L

straight M space equals space fraction numerator straight n space of space solute over denominator straight V space of space solution space in space liters end fraction

Rearranging the equation,

n of solute = M × V of solution in liters

n of solute = 0.150 M × 0.0250 L

n of solute = 0.00375 mol of NaOH

Step 3: Calculate the moles of HCl that reacted using the ratio from the chemical equation

begin mathsize 14px style 0.00375 space mol space of space NaOH space cross times space fraction numerator 1 space mol space of space HCl over denominator 1 space mol space of space NaOH end fraction space equals space 0.00375 space mol space of space HCl end style

Since the ratio is 1:1 the moles of HCl must be the same

Step 4: Calculate the molarity of the HCl solution using the volume of the sample in L

 30.0 space mL space of space solution space cross times space fraction numerator 1 space straight L over denominator 1000 space mL end fraction space equals space 0.0300 space straight L

begin mathsize 14px style straight M space equals space fraction numerator straight n space of space solute over denominator straight V space of space solution space in space liters end fraction end style

straight M space equals space fraction numerator 0.00375 space mol over denominator 0.0300 space straight L end fraction

M = 0.125 M 

Step 5: Write the answer with the appropriate number of significant figures

Since all the quantities from the statement are given with 3 significant figures. The answer must be written with 3 significant figures

The concentration of the unknown HCl sample is 0.125 M

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Author: Martín

Martín, a dedicated chemistry teacher and tutor, excels in guiding students through IB, AP, and IGCSE Chemistry. As an IB Chemistry student, he came from hands-on preparation, focusing on practical exam techniques and rigorous practice. While at Universidad San Francisco de Quito, his academic journey sparked a passion for computational and physical chemistry. Martín specializes in chemistry, and he knows that SaveMyExams is the right place if he wants to have a positive impact all around the world.