Photoelectric Effect (College Board AP Chemistry)

Revision Note

Martín

Author

Martín

Expertise

Chemistry Content Creator

Photons

  • One of the main characteristics of light is its wave-particle duality
  • This means that light can behave as a wave, but also as a particle
  • As seen in previous sections, a light wave has frequency, wavelength and energy
  • However, the discovery of the photoelectric effect suggested that light can also behaves as a particle
  • The photoelectric effect was observed when some metals emit electrons when they were shined with light
    • The results of this experiment suggested that light must come into particles
  • A light particle is called a photon

Absorption and Emission of photons

  • Electrons move around the nucleus of the atoms in energy shells
  • Atoms and molecules can absorb photons, and the electrons will jump to higher energy shells
    • When this occurs, the energy of the atom or molecule increases by an amount equal to the energy of the photon
  • A moment later, a photon will be emitted, and the electrons will return to their original shell which is also called the ground state
    • When this occurs, the energy of the atom or molecule will decrease by an amount equal to the energy of the photon

Absorption and Emission diagram

Diagram to show absorption and emission in the ground state and excited state

The difference between absorption and emission depends on whether electrons are jumping from lower to higher energy levels or the other way around

The Hydrogen Emission Spectrum

  • Niels Bohr constructed the hydrogen emission spectrum where he showed the energy released when electrons jump from higher shells to lower shells
  • Bohr suggested that electrons can only exist in fixed energy shells
    • This means that electronic transitions can only occur when photons with an specific amount of energy are absorbed or released
  • Each electronic transition has to do with photons from specific regions of the electromagnetic spectrum

Regions of the electromagnetic spectrum

 Diagram to show the electron jumps in the hydrogen atom

Electron jumps in the hydrogen spectrum

  • The jumps can be summarized in table below:

Electron transitions summary

Jumps

Region

Energy

n∞→ n3

Infrared

Low

n∞ → n2

Visible

n∞ → n1

Ultraviolet

High

 

Energy of Photons

Frequency, Wavelength and Energy

  • As it was shown in the electromagnetic spectrum, the shorter the frequency of an electromagnetic wave, the longer its wavelength
    • Frequency (ν) and wavelength (λ) are inversely proportional
    • The equation that links them is:

 c equals lambda v

    • In this equation c is the speed of light which is 2.998 x 108 ms-1
  • The spectrum also shows that, the shorter the frequency, the lower the energy of the radiation
    • Frequency (ν) and energy (E) are directly proportional
    • The equation that links the energy emitted or absorbed by a photon and its frequency is:
                                                      E equals h v
    • In this equation h is the Planck’s constant, which is 6.626 x 10-34 J s
  • These two equations can be used to calculate frequency, wavelength or energy when one of them is given

Exam Tip

Both equations and constants can be found in the AP Chemistry Constants and Equations section in your examination

Worked example

Calculate the wavelength of the photon emitted when an electron transition has released 1.632 x 10 -18 J

Answer:

Step 1: Calculate the frequency of the photon by using the Planck’s equation

E equals h v

v equals E over h

straight v equals fraction numerator 1.632 cross times 10 to the power of negative 18 space end exponent straight J over denominator 6.626 cross times 10 to the power of negative 34 end exponent space straight J space straight s end fraction

v = 2.463 × 1015 s-1 

Step 2: Use the frequency calculated in Step 1 to calculate the wavelength of the photon

c equals lambda v

lambda equals c over v

begin mathsize 14px style straight lambda equals fraction numerator 2.998 cross times 10 to the power of 8 space straight m space straight s to the power of negative 1 end exponent over denominator 2.463 space cross times 10 to the power of 15 space straight s to the power of negative 1 end exponent end fraction end style

λ = 1.217 × 10-7 m 

You've read 0 of your 0 free revision notes

Get unlimited access

to absolutely everything:

  • Downloadable PDFs
  • Unlimited Revision Notes
  • Topic Questions
  • Past Papers
  • Model Answers
  • Videos (Maths and Science)

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Martín

Author: Martín

Martín, a dedicated chemistry teacher and tutor, excels in guiding students through IB, AP, and IGCSE Chemistry. As an IB Chemistry student, he came from hands-on preparation, focusing on practical exam techniques and rigorous practice. While at Universidad San Francisco de Quito, his academic journey sparked a passion for computational and physical chemistry. Martín specializes in chemistry, and he knows that SaveMyExams is the right place if he wants to have a positive impact all around the world.