Buffer Capacity
- Buffer capacity tells you how much acid or base can be added to the buffer without the pH changing
- The greater the buffer capacity, the more acid or base that can be added before the pH starts to change
- The buffer capacity depends on the concentrations of both the weak acid and its conjugate base (or weak base and its conjugate acid
- A buffer is formed from ethanoic acid and sodium ethanoate
- If acid, H+, is added the following reaction will occur
CH3COO– (aq) + H+ (aq) CH3COOH (aq)
the equilibrium will shift to the right-hand side as H+ ions are 'mopped' up
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- If a base, OH–, is added the following reaction will occur
CH3COOH (aq) + OH– (aq) CH3COO– (aq) + H2O (l)
the equilibrium will shift to the right-hand side as OH– ions are 'mopped up'
- Using the different concentrations of ethanoic acid and sodium ethanoate we can demonstrate the difference in buffer capacity (the pKa of ethanoic acid is 4.74)
Buffer 1 - higher concentration | Buffer 2 - lower concentration | |
Initial pH of buffer solution |
[CH3COOH] = 0.80 M [CH3COO–] = 0.40 M pH = pKa + log10 pH = pKa + log10 = 5.04 |
[CH3COOH] = 0.080 M [CH3COO–] = 0.040 M pH = pKa + log10 = 5.04 pH = pKa + log10 = 5.04 |
pH on addition of 0.05 M NaOH |
[CH3COOH] = 0.80 M - 0.05 M = 0.75 M [CH3COO–] = 0.40 M + 0.05 M = 0.45 M pH = pKa + log10 pH = 4.74 + log10 = 5.56 |
[CH3COOH] = 0.080 M - 0.05 M = 0.075 M [CH3COO–] = 0.040 M + 0.05 M = 0.045 M pH = pKa + log10 pH = 4.74 + log10 = 6.18 |
- Buffer 1 has a higher capacity than buffer 2
Worked example
Two different buffer solutions are formed. Buffer 1 contains 50 mL of 0.100 M NaOH and 100 mL of 0.100 M HNO2 (aq) and buffer 2 contains 0.100 mol NaNO2 (s) and 100 mL of 1.00 M HNO2.
Which buffer is more resistant to changes in pH? Justify your answer.
Answer:
- Buffer 2
Justification:
- Buffer 2 contains a higher concentration of HNO2 AND NO2– to react with added H+ and OH– ions.