Edexcel A Level Chemistry

Revision Notes

5.4.3 Gibbs Free Energy

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Feasibility of Reactions

Gibbs free energy

  • The feasibility of a reaction is determined by two factors
    • The enthalpy and entropy change
  • The two factors come together in a fundamental thermodynamic concept called the Gibbs free energy (G)
  • The Gibbs equation is:

ΔG = ΔHreaction – TΔSsystem

    • The units of ΔGare in kJ mol1
    • The units of ΔHreactionare in kJ mol1
    • The units of T are in K
    • The units of ΔSsystem are in J K-1 mol1(and must therefore be converted to kJ Kmol1by dividing by 1000)

  • For a reaction to be feasible, ΔG must be equal or less than zero 

Gibbs Free Energy Calculations

Calculating ΔGΘ

  • This can be done by using the Gibbs equation, using enthalpy change, ΔH, and entropy change, ΔS, values

Worked example

ΔGfrom ΔHand ΔSvalues

Calculate the free energy change for the following reaction:

2NaHCO(s) → Na2CO3 (s) + H2O (l) + CO2 (g)

  • ΔHꝋ = +135 kJ mol-1       
  • ΔSꝋ = +344 J K-1 mol-1

Answer:

Step 1: Convert the entropy value in kilojoules

ΔSꝋ = +344 J K-1 mol-1  ÷ 1000 = +0.344 kJ K-1 mol-1 

Step 2: Substitute the terms into the Gibbs Equation

ΔG= ΔHreaction– TΔSsystem

= +135 – (298 x 0.344)

+32.49 kJ mol-1 

The temperature is 298 K since standard values are quoted in the question

  • Rearranging the Gibbs equation allows you to determine the temperature at which a non-spontaneous reaction become feasible

ΔG = ΔHreaction - TΔSsystem

  • Remember, for a reaction to be feasible ΔGΘꝋmust be zero or negative

0 = ΔH - TΔS

ΔH = TΔS

T = ΔH÷ ΔS

Worked example

At what temperature will the reduction of aluminium oxide with carbon become spontaneous?

Al2O3(s) + 3C(s)→ 2Al(s) + 3CO(g)             

ΔH = +1336 kJ mol-1

ΔS = +581 J K-1 mol-1

Answer:

    • If ΔG = 0 then T = ΔH÷ ΔS
    • Covert ΔSto kJ K-1 mol-1 by dividing by 1000
    • T = 1336 ÷ (581/1000)
    • T = 2299 K

Temperature and Gibbs free energy 

  • When ΔG is negative, the reaction is spontaneous / feasible and likely to occur
  • When ΔGis positive, the reaction is not spontaneous / feasible and unlikely to occur
  • We can also look at the the values for enthalpy change, ΔH, and entropy change, ΔS
    • Depending on the value for ΔH and ΔS we can determine whether the reaction is spontaneous at a given temperature (T)

Summary for temperature and Gibbs free energy 

factors-affecting-gibbs-free-energy-1

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