Edexcel A Level Chemistry

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1.5.4 Intermolecular Forces & Physical Properties

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Intermolecular Forces & Physical Properties

Branching

  • The larger the surface area of a molecule, the more contact it will have with adjacent molecules
  • The surface area of a molecule is reduced by branching 
  • The greater its ability to induce a dipole in an adjacent molecule, the greater the London (dispersion) forces and the higher the melting and boiling points
  • This point can be illustrated by comparing different isomers containing the same number of electrons:

Chemical Bonding Contact Points, downloadable AS & A Level Chemistry revision notes

Boiling points of molecules with the same numbers of electrons but different surface areas

Number of electrons

  • The greater the number of electrons (or the greater the molecular mass) in a molecule, the greater the likelihood of a distortion and thus the greater the frequency and magnitude of the temporary dipoles
  • The dispersion forces between the molecules are stronger and the enthalpy of vaporisation, melting and boiling points are larger
  • The greater boiling points of the noble gases illustrate this factor:

Chemical Bonding Enthalpy and Boiling Point, downloadable AS & A Level Chemistry revision notes

As the number of electrons increases more energy is needed to overcome the forces of attraction between the noble gases atoms

Alkanes Boiling Point

Graph showing the increase in boiling point as the number of electrons increases

Alcohols

  • Hydrogen bonding occurs between molecules where you have a hydrogen atom attached to one of the very electronegative elements - fluorine, oxygen or nitrogen
  • In an alcohol, there are O-H bonds present in the structure
  • Therefore hydrogen bonds set up between the slightly positive hydrogen atoms (δ+ H) and lone pairs on oxygens in other molecules
  • The hydrogen atoms are slightly positive because the bonding electrons are pulled away from them towards the very electronegative oxygen atoms
  • In alkanes, the only intermolecular forces are temporary induced dipole-dipole forces
  • Hydrogen bonds are much stronger than these and therefore it takes more energy to separate alcohol molecules than it does to separate alkane molecules
  • Therefore, the boiling point of alkanes is lower than the boiling point of the respective alcohols
  • For example, the boiling point of propane is -42 oC and the boiling point of propanol is 97 oC

Hydrogen Halides 

  • The boiling points of the hydrogen halides are as follows

2-2-3-the-boiling-points-of-the-hydrogen-halides

  • The boiling points of the rest of the hydrogen halides increase as the molecules become larger
  • The extra electrons allow greater temporary dipoles and so increase the amount of London dispersion forces between the molecules
  • Hydrogen fluoride also has hydrogen bonding between the HF molecules
  • The bond is very polar so that the hydrogen has a significant amount of positive charge and the fluorine a significant amount of negative charge. In addition, the fluorine has small intense lone pairs
  • Hydrogen bonds can form between the hydrogen on one molecule and a lone pair on the fluorine in its neighbour

Choosing Solvents

Solubility

  • The general principle is that 'like dissolves like' so non-polar substances mostly dissolve in non-polar solvents, like hydrocarbons and they form dispersion forces between the solvent and the solute
  • Polar covalent substances generally dissolve in polar solvents as a result of dipole-dipole interactions or the formation of hydrogen bonds between the solute and the solvent
  • A good example of this is seen in organic molecules such as alcohols and water:

Hydrogen bonds between ethanol and water, downloadable IB Chemistry revision notes

Hydrogen bonds form between ethanol and water

  • As covalent molecules become larger their solubility can decrease as the polar part of the molecule is only a smaller part of the overall structure
    • This effect is seen in alcohols for example where ethanol, C2H5OH, is readily soluble but hexanol, C6H13OH, is not

  • Polar covalent substances are unable to dissolve well in non-polar solvents as their dipole-dipole attractions are unable to interact well with the solvent
  • Giant covalent substances generally don't dissolve in any solvents as the energy needed to overcome the strong covalent bonds in the lattice structures is too great

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Philippa

Author: Philippa

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener.