A LevelChemistryCIETopic Questions19. Nitrogen Compounds19.1 Primary Amines

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First teaching 2023

First exams 2025

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Primary Amines (CIE A Level Chemistry)

Topic Questions

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11 mark

Which of the following is the displayed formula for ethylamine?

  • 3-7-e-1a

  • 3-7-e-1b

  • 3-7-e-1c

  • 3-7-e-1d

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21 mark

What type of reaction makes ethylamine from bromoethane?

  • Oxidation

  • Reduction

  • Nucleophilic substitution

  • Electrophilic substitution

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31 mark

When 1-bromoethane reacts with an equal amount of X. What would X be and what is the product of this reaction?

 

X

Product

A

Ammonia

Amine

B

Methylamine

Amide

C

Water

Weak acid

D

Methanol

Ethyl methanoate

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11 mark

What is the correct set of reagents and conditions for the two reactions shown?

 

(CH3)2CO rightwards arrow (CH3)2CHCN

CH3CHClCH3 rightwards arrow CH3CH(NH2)CH3

A

Sn / conc. H2SO4

Dilute ethanolic NH3

B

Sn / conc. HCl

Excess ethanolic NH3

C

NH3

Nitric acid / 50 °C

D

KCN, H2SO4

Excess ethanolic NH3

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21 mark

Which amine could not be produced by the reduction of a nitrile?

  • butylamine

  • methylpropylamine

  • 2methylpropylamine

  • 22dimethylpropylamine

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31 mark

What is the systematic name of the amine shown?7-5-h-q5-aqa-al-chemistry-mcq

  • Dimethyldiethyl ammonium chloride 

  • Diethylmethyl ammonium chloride 

  • Diethyldimethyl ammonium chloride 

  • Methylethyl ammonium chloride 

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11 mark

Methyl iodide can be heated with ammonia. Which of the options describes the products of this reaction?

  • Methylamine

  • Dimethylamine

  • Trimethylamine

  • All of the above

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21 mark

1-chloropropane can be used to make propylamine.

Which row shows the correct reagents and type of reaction?

  Reagents Type of reaction
A Aqueous ammonia Electrophilic addition
B Aqueous ammonia Nucleophilic substitution
C Ethanolic ammonia Nucleophilic substitution
D Ethanolic ammonia Electrophilic addition

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31 mark

CH3CH2Cl reacts with an excess of ethanolic NH3.

Which compound is the main organic product?

  • (CH3CH2)3N

  • (CH3CH2)2NH

  • CH3CH2NH2

  • (CH3CH2)4N+

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