Edexcel International A Level Chemistry

Topic Questions

5.2 Transition Metals & Complexes

11 mark

What is the electronic configuration of a chromium atom?

q3-paper-5-june-2021-edexcel-ial-chemistry

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21 mark

A ligand must be an

  • electron-pair donor

  • electron-pair donor and negatively charged

  • electron-pair acceptor

  • electron-pair acceptor and negatively charged

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31 mark

Nickel is classified as a transition metal. This is because nickel

  • is a d block element

  • has partially filled d orbitals

  • forms stable ions with partially filled d orbitals

  • forms stable compounds in which it has different oxidation states

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41 mark

Cobalt chloride is used as a test for the presence of water.

This test depends on the fact that

  • anhydrous cobalt(II) chloride is blue and hydrated cobalt(II) chloride is pink

  • anhydrous cobalt(II) chloride is pink and hydrated cobalt(II) chloride is blue

  • cobalt(II) chloride is blue and cobalt(III) chloride is pink

  • cobalt(II) chloride is pink and cobalt(III) chloride is blue

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1a1 mark

This question is about transition metal complexes.

a)
The bonding within the complex [Cu(NH3)4(H2O)2]2+ is
  • covalent, dative covalent and ionic

  • covalent and dative covalent only

  • covalent only

  • dative covalent only

1b1 mark
b)
Which complex is tetrahedral?

  • [Pt(NH3)2Cl2]

  •  [Cu(H2O)4(OH)2]

  • [Cu(NH3)4(H2O)2]2+

  • [CoCl4]2−

1c1 mark
c)
Which complex contains a bidentate ligand?
  • [Co(NH2CH2CH2NHCH2CH2NH2)2]3+

  • [Cu(NH3)4(H2O)2]2+

  • [Ni(NH2CH2CH2NH2)3]2+

  • [Mn(EDTA)]2−

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21 mark

In which of the following pairs does the metal have different oxidation numbers?

  • CrO subscript 4 superscript 2 minus end superscript space and space Cr subscript 2 straight O subscript 7 superscript 2 minus end superscript 

  • CrO subscript 4 superscript 2 minus end superscript space and space CrO subscript 3 Cl to the power of minus

  • V2O5 and space VO subscript 4 superscript 3 minus end superscript

  • VO subscript 2 superscript plus and VO2+

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31 mark

Which of the following statements best explains carbon monoxide poisoning?

  • carbon monoxide binds irreversibly to haemoglobin

  • carbon monoxide forms stronger dative covalent bonds with haemoglobin than oxygen does

  • the formation of carboxyhaemoglobin leads to a large increase in the entropy of the system

  • carbon monoxide has a triple bond whereas oxygen has a double bond

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41 mark

Diamminecopper(I) ions are not coloured because

  • the d orbitals in copper(I) cannot be split

  • the energy difference between the split d orbitals is outside the visible region of the spectrum

  • d—d transitions are not possible because the d orbitals are fully occupied

  • copper(I) complexes are readily oxidised

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51 mark

Which of these has the greatest number of unpaired electrons in each of its atoms?

  • chromium

  • iron

  • manganese

  • vanadium

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61 mark

Copper(II) ions form a complex with 1,2-diaminoethane (symbol ‘en’) with the formula Cu(en)3 2+.

What type of ligand is 1,2-diaminoethane, and what is the coordination number of copper(II) in the complex?

    Type of ligand Coordination number
A bidentate 3
B bidentate 6
C tridentate 3
D tridentate 6

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71 mark

Some nickel(II) complex ions are formed by the addition of complexing agents to nickel(II) ions, [Ni(H2O)6]2+, in aqueous solution.

On formation, which of these leads to the most positive increase in ΔSsystem?

  • [NiCl4]2–

  • [Ni(EDTA)]2–

  • [Ni(C2O4)2 ]2–

  • [Ni(H2NCH2CH2NH2)3]2+

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8a1 mark

Platinum forms a complex with the formula Pt(NH3)2Cl2 and chromium forms a complex with the formula CrCl4.

a)
What are the shapes of these complexes?
  • both complexes are square planar

  • both complexes are tetrahedral

  • Pt(NH3)2Cl2 is tetrahedral and CrCl4 is square planar

  • Pt(NH3)2Cl2 is square planar and CrCl4 is tetrahedral

8b1 mark
b)
What is the bonding between the ligands and the central atom in these complexes?
  • the bonding in both complexes is ionic

  • the bonding in both complexes is dative covalent

  • the bonding in Pt(NH3)2Cl2 is dative covalent and in CrCl4 is ionic

  • the bonding in Pt(NH3)2Cl2 is ionic and in CrCl4 is dative covalent

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