Redox Equilibria (Edexcel International A Level Chemistry)

Topic Questions

1a
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8 marks

This question is about manganese compounds. Some data are given below.

  Electrode reaction bold italic E to the power of bold ⦵/ V
1

MnO subscript 4 superscript minus space plus space straight e to the power of minus space⇌ Mnstraight O subscript 4 superscript 2 minus end superscript

+0.56
2 MnO subscript 4 superscript 2 minus end superscript space + 2H2O + 2e ⇌ MnO2 + 4OH +0.59
3 Fe3+ + e⇌ Fe2+ +0.77
4 MnO2 + 4H+ + 2e ⇌ Mn2+ + 2H2O +1.23
5

MnO subscript 4 superscript minus+ 8H+ + 5e ⇌ Mn2+ + 4H2O

+1.51
6 MnO subscript 4 superscript minus + 4H+ + 3e ⇌ MnO2 + 2H2O +1.70
7 MnO subscript 4 superscript 2 minus end superscript+ 4H+ + 2e ⇌ MnO2 + 2H2O +2.26

i)
Write the ionic equation for the disproportionation of manganate(VI) ions, begin mathsize 14px style Mn O subscript 4 to the power of 2 minus sign end style, in acidic conditions, using relevant half-equations from the table.
State symbols are not required.
(2)

ii)
Calculate E subscript cell superscript ⦵ for the disproportionation of manganate(VI) ions in acidic conditions, stating whether or not the reaction is thermodynamically feasible.
(2)

iii)
Using the standard electrode potentials in the table, assess the thermodynamic feasibility of preparing manganate(VI) by reacting manganate(VII) and manganese(IV) oxide in alkaline conditions.
(4)
1b
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9 marks

Steel is an alloy of iron and carbon. A group of students determined the iron content of a sample of steel wire by a titration method.

A known mass of the wire was dissolved in dilute sulfuric acid and the resulting solution made up to 250.0 cm3 with more dilute sulfuric acid and mixed thoroughly.

Fe + H2SO4 → FeSO4 + H2

25.0 cm3 samples of the resulting solution were titrated with 0.0195 mol dm−3 potassium manganate(VII) solution.

i)
State the colour change at the end-point of the titration.
(1)

ii)
One student used 1.53 g of the wire (weighed directly on the balance pan) and obtained a mean titre of 27.35 cm3 .
Using half-equations 3 and 5 from the table, calculate the percentage of iron in the steel wire. Give your answer to three significant figures.
(5)

iii)
A second student carried out the same experiment but used distilled water to make up the solution in the volumetric flask.
A brown suspension formed during the titration.
Explain how, if at all, the titre value would be affected by this student’s error.
(3)

1c
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4 marks

The uncertainties of the apparatus used in the experiment in (b) are shown.

Apparatus Value measured Uncertainty on each
reading
Percentage uncertainty on
value measured / %
  Balance 1.53 g ±0.005 g 0.65
  Burette 27.35 cm3 ±0.05 cm3  
  Pipette 25.0 cm3 ±0.06 cm3  
  Volumetric flask 250.0 cm3 ±0.3 cm3  


i)
Complete the table.
(2)
ii)
A third student obtained a value of 95.863% for the proportion of iron in the wire.
State whether or not this student has given their answer to an appropriate number of significant figures. Justify your answer in terms of the total percentage uncertainty of the experiment.
(2)

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2a1 mark

This question is about titanium(III) chloride, TiCl3 .

Titanium(III) chloride is used as a catalyst in the production of poly(propene).

State the property of transition metals, such as titanium, that makes their compounds effective catalysts.

2b3 marks

When dissolved in tetrahydrofuran (THF), titanium(III) chloride forms a blue solution containing complex Y.

q20b-paper-5-oct-2021-edexcel-ial-chemistry
i)
THF acts as a monodentate ligand in complex Y.
State the meaning of the terms monodentate and ligand.

(2)

ii)

Complex Z is a stereoisomer of complex Y.
Complete the diagram to show the arrangement of the ligands in complex Z.

(1)

q20b-ii-paper-5-oct-2021-edexcel-ial-chemistry

2c
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16 marks

A student determines the change in oxidation number of nitrogen when a solution of magnesium nitrate, Mg(NO3)2 , is titrated with aqueous titanium(III) chloride.

Procedure

Step 1

Using a volumetric flask, prepare 100.0 cm3 of an aqueous solution containing 0.750 g of solid Mg(NO3)2•6H2O.

Step 2

Pipette 10.0 cm3 of the solution from Step 1 into a conical flask and add a few drops of alizarin indicator.
Add 2 cm3 of concentrated hydrochloric acid and heat the mixture.

Step 3 Fill a burette with 0.0850 mol dm–3 aqueous titanium(III) chloride and titrate the contents of the conical flask from Step 2 while continuing to heat the mixture.


During the titration, Ti3+ ions are oxidised to TiO2+ ions

Ti3+ + H2O → TiO2+ + 2H++ e

Alizarin indicator is green in the presence of aqueous Ti3+ and yellow in the presence of aqueous TiO2+.
The end‐point of the titration is reached on the addition of 20.70 cm3 of aqueous titanium(III) chloride.

i)

State the colour change that would be observed at the end‐point of the titration.

(1)

From .............................. to .............................. 

ii)
Use the results to determine the final oxidation state of nitrogen in the titration.
You must show your working.

[Mr value: Mg(NO3)2∙6H2O = 256.3]
(5)
iii)
Write the overall ionic equation for the titration reaction using your answer to (c)(ii) and the relevant half‐equations from the list below.

(2)

TiO2+ + 2H++ e  ⇌  Ti3+ + H2O   Eθ = +0.10V

NO3– + 2H++ e    ⇌  NO2 + H2O   Eθ = +0.80V

NO3 + 3H++ 2e–  ⇌ HNO2 + H2O   Eθ  = +0.94V

NO3+ 4H++ 3e  ⇌  NO + 2H2O   Eθ = +0.96V

iv)

Use the electrode potential data provided to calculate Eθcell for the overall titration reaction.

(1)

v)

Suggest why the contents of the conical flask are heated.

(1)

vi)

The student’s teacher said,
“As TiCl3 is blue and TiO2+ ions are colourless in aqueous solution, the titration can be carried out without an alizarin indicator.”

Assess the teacher’s statement.
In your answer you should

  • identify, by name or formula, a coloured complex ion expected to be present when TiCl3 dissolves in water
  • explain how the colour of this complex ion arises
  • suggest why the titration may be more accurate with an alizarin indicator.

(6)

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1a
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2 marks

A yellow crystalline solid E dissolved in distilled water to give a yellow solution.

Addition of dilute sulfuric acid to this solution produced an orange solution F.

Warming F with ethanol resulted in a green solution G, and the formation of ethanol.

A standard cell was set up using solutions of F and G for the right-hand electrode and ethanol and ethanal for the left-hand electrode.

Eθcell was found to be +1.94 V.

CH3CHO (aq) + 2H+ (aq) + 2e rightwards harpoon over leftwards harpoon C2H5OH (aq)   Eθ = –0.61 V

Deduce the formulae of the ions responsible for the colours of F and G, using the standard electrode potential and Eθ given, and the values in the Data Booklet.

1b2 marks

Write the overall equation for the reaction in the cell.
State symbols are not required.

1c1 mark

Write the ionic equation for the reaction of the aqueous solution of E with dilute sulfuric acid. State symbols are not required.

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