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First teaching 2021

Last exams 2024

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nth Term (CIE IGCSE Maths: Core)

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Amber

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Amber

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Maths

Linear Sequences

What is a linear sequence?

  • A linear sequence is one where the terms go up (or down) by the same amount each time
    • eg 1, 4, 7, 10, 13, … (add 3 to get the next term)
    • 15, 10, 5, 0, -5, … (subtract 5 to get the next term)

  • A linear sequence is often referred to as an arithmetic sequence
  • If we look at the differences between the terms, we see that they are constant

What should we be able do with linear sequences?

  • You should be able to recognise and continue a linear sequence
  • You should also be able to find a formula for the nth term of a linear sequence in terms of n
  • This formula will be in the form:

    nth term = dn + b, where;

    • d is the common difference
    • b is a constant that makes the first term “work”

How do I find the nth term of a linear (arithmetic) sequence?

  • Find the common difference between the terms- this is d
  • Put the first term and n = 1 into the formula, then solve to find b

Exam Tip

  • If a sequence is going up by d each time, then its nth term contains dn
    • e.g. 5, 7, 9, 11, is going up by 2 each term so the nth term contains 2n
    • (the complete nth term for this example is 2n + 3)
  • If a sequence is going down by d each time, then its nth term contains −dn
    • e.g. 5, 3, 1, -1, ... is going down by 2 each term then the nth term contains −2n
    • (the complete nth term for this example is −2n + 7)

Worked example

Given the sequence 5, 7, 9, 11, 13, ...

(a)
Find the next three terms.

Looking at the difference between the terms, we see that they are all 2. So this is a linear sequence with common difference 2
So the next three terms are
13 + 2 = 15
15 + 2 = 17
17 + 2 = 19
15, 17, 19
(b)
Find a formula for the nth term.

In part (a) we established that the common difference is 2. So d = 2

nth term = 2n + b

The first term is 5. Substitute this and n = 1 into the formula, and solve for b

5 = 2×1 + b
5 = 2 + b
b = 3
Now we can write the nth term
2n + 3

Quadratic & Cubic Sequences

What is a quadratic sequence?

  • Unlike in a linear sequence, in a quadratic sequence the differences between the terms (the first differences) are not constant
  • However, the differences between the differences (the second differences) are constant
  • Another way to think about this is that in a quadratic sequence, the sequence of first differences is a linear sequence

    eg Sequence:   2, 3, 6, 11, 18, …

    1st Differences:  1  3  5  7 (a Linear Sequence)

    2nd Differences:   2  2  2 (Constant)

  • If the second differences there are constant, we know that the example is a quadratic sequence

What should I be able to do with quadratic sequences?

  • You should be able to recognise and continue a quadratic sequence
  • You should also be able to find a formula for the nth term of a simple quadratic sequence in terms of n
    • This formula will be in one of the forms:

      nth term = an2 
      nth term = (n+b)2 
      nth term = n2 + b
      nth term = an2 + b

  • To find the values of and b, you must remember the terms in the sequence for nand compare them to the given sequence
    • n2 is the sequence 1, 4, 9, 16, 25, 36, 49, ....
    • Usually, each term will be either a little bit more or less than the sequence for n2
      • For example, the sequence 2, 5, 10, 17, 26, 37, 50, ... has the formula n+ 1 as each term is 1 more than the corresponding term in n2
    • Sometimes, each term will be two or three times (or maybe even one half of) the term in the sequence for n2
      • For example, the sequence 2, 8, 18, 32, 50, 72, 98, ... has the formula 2n2  as each term is twice the corresponding term in n2

What is a cubic sequence?

  • In a cubic sequence the differences between the terms (the first differences) are not constant and the differences between the differences (the second differences) are not constant
  • However, the differences between the second differences (the third differences) are constant
  • Another way to think about this is that in a cubic sequence, the sequence of second differences is a linear sequence

    eg Sequence:   1, 5, 21, 55, 113, …

    1st Differences:  4,  16,  34,  58 (a Quadratic Sequence)

    2nd Differences:   12,  18,  24 (a Linear Sequence)
    3rd Differences:  6,  6,  6 (Constant)

  • If the third differences there are constant, we know that the example is a cubic sequence

What should I be able to do with cubic sequences?

  • You should be able to recognise and continue a cubic sequence
  • You should also be able to find a formula for the nth term of a simple cubic sequence in terms of n
    • This formula will be in one of the forms:

      nth term = an3 
      nth term = n3 + b

  • To find the values of and b, you must remember the terms in the sequence for n3 and compare them to the given sequence
    • n3 is the sequence 1, 8, 27, 64, 125, ....
    • Usually, each term will be either a little bit more or less than the sequence for n3
      • For example, the sequence 2, 9, 28, 65, 126, , ... has the formula n3 + 1 as each term is 1 more than the corresponding term in n3
    • Sometimes, each term will be two or three times the term in the sequence for n3
      • For example, the sequence 2, 16, 54, 128, 250, ... has the formula 2n3  as each term is twice the corresponding term in n3

Exam Tip

  • Learning the sequence of the square numbers 1, 4, 9, 16, 25, … and the cube numbers 1, 8, 27, 64, 125,... is essential for recognising and finding nth terms of quadratic and cubic sequences 

Worked example

For the sequence 6, 9, 14, 21, 30, ....

(a)
Find a formula for the nth term.

Start by finding the first and second differences

Sequence:   6,   9,   14,   21,   30
First differences:      3,    5,     7,      9, ...           
Second difference:     2,    2,     2, ...               
The second differences are constant so this must be a quadratic sequence.
 
Compare each term to the terms in the sequence for n2.

           n2. :  1,   4,   9,   16,   25,  ... 
     sequence:  6,   9,  14,   21,  30, ...      
difference: 5,   5,    5,    5,    5,  ...
Each term is 5 more than the terms in n2, so add 5 to the nth term.
nth term = n2 + 5
(b)
Hence find the 20th term of the sequence.

Substitute n = 20 into n2 + 5
(20)2 + 5 = 400 + 5
20th term = 405

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Amber

Author: Amber

Amber gained a first class degree in Mathematics & Meteorology from the University of Reading before training to become a teacher. She is passionate about teaching, having spent 8 years teaching GCSE and A Level Mathematics both in the UK and internationally. Amber loves creating bright and informative resources to help students reach their potential.