Binary Addition (Edexcel GCSE Computer Science)

Revision Note

Binary Addition

What is binary addition?

  • Binary addition is the process of adding together two binary integers (up to and including 8 bits)

  • To be successful there are 5 golden rules to apply:

Binary Addition

Binary Answer

Working

0 + 0 =

0

1s

 

0

= 0

0 + 1 =

1

1s

 

1

= 1

1 + 0 = 

1

1s

 

1

= 1

1 + 1 =

10

2s

1s

 

1

0

= 2

1 + 1 + 1 =

11

2s

1s

 

1

1

= 3

  • Like denary addition, start from the rightmost digit and move left

  • Carrying over occurs when the sum of a column is greater than 1, passing the excess to the next left column

Example 1

  • Add together the binary values 1001 and 0100

8

4

2

1

+

1

0

0

1

0

1

0

0

 

 

 

 

C

 

 

 

 

 

  • Starting from right to left, add the two binary values together applying the 5 golden rules

  • If your answer has 2 digits, place the rightmost digit in the column and carry the remaining digit to the next column on the left

  • In this example, start with 1+0, 1+0 = 1, so place a 1 in the column

8

4

2

1

+

1

0

0

1

0

1

0

0

 

 

 

 

C

 

 

 

1

 

  • Repeat until all columns have a value

8

4

2

1

+

1

0

0

1

0

1

0

0

 

 

 

 

C

1

1

0

1

 

  • The sum of adding together binary 1001 (9) and 0100 (4) is 1101 (13)

Exam Tip

Make sure any carried digits are clearly visible in your answer, there are marks available for working. Carries can be put above or below in the addition

Example 2

  • Add together the binary values 00011001 and 10000100

128

64

32

16

8

4

2

1

+

0

0

0

1

1

0

0

1

1

0

0

0

1

0

0

1

 

 

 

 

 

 

 

 

C

 

 

 

 

 

 

 

 

 

  • Starting from right to left, add the two binary values together applying the 5 golden rules

  • If your answer has 2 digits, place the rightmost digit in the column and carry the remaining digit to the next column on the left

  • In this example, start with 1+1, 1+1 = 10, so place a 0 in the column and carry the 1 to the next column

128

64

32

16

8

4

2

1

+

0

0

0

1

1

0

0

1

1

0

0

0

1

0

0

1

 

 

 

 

 

 

1

C

 

 

 

 

 

 

0

 

  • Repeat until all columns have a value

128

64

32

16

8

4

2

1

+

0

0

0

1

1

0

0

1

1

0

0

0

1

0

0

1

1

1

1

C

1

0

1

0

0

0

1

0

 

  • The sum of adding together binary 00011001 (25) and 10001001 (137) is 10100010 (162)

Overflows

What is an overflow error?

  • An overflow error occurs when the result of a binary addition exceeds the available bits

  • For example, if you took binary 11111111 (255) and tried to add 00000001 (1) this would cause an overflow error as the result would need a 9th bit to represent the answer (256)

256

128

64

32

16

8

4

2

1

+

 

1

1

1

1

1

1

1

1

 

0

0

0

0

0

0

0

1

1

1

1

1

1

1

1

1

C

0

0

0

0

0

0

0

0

 

Exam Tip

When starting a binary addition question, always look at the question that comes after. If it asks you to name what problem has been caused, you know the binary addition question must cause an overflow error and therefore mean a carried bit that does not fit in to the answer

Binary Shifts

What is a logical binary shift?

  • A logical binary shift is how a computer system performs basic multiplication and division on unsigned binary integers

  • Binary digits are moved left or right a set number of times

  • A left shift multiplies a binary number by 2 (x2)

  • A right shift divides a binary number by 2 (/2)

  • A shift can move more than one place at a time, the principle remains the same

  • A left shift of 2 places would multiply the original binary number by 4 (x4)

How do you perform a logical left shift of 1?

  • Here is the binary representation of the denary number 40

128

64

32

16

8

4

2

1

0

0

1

0

1

0

0

0

  • To perform a left logical binary shift of 1, we move each bit 1 place to the left

  • The digit in the 128 column (MSB) will move left causing an overflow error

  • The 1 column becomes empty so is filled with a 0

128

64

32

16

8

4

2

1

 

0

1

0

1

0

0

0

= 40

0

1

0

1

0

0

0

0

= 80

  • The original binary representation of denary 40 (32+8)  has multiplied by 2 and became 80 (64+16)

How do you perform a logical left shift of 2?

  • Here is the binary representation of the denary number 28

128

64

32

16

8

4

2

1

0

0

0

1

1

1

1

0

  • To perform a left binary shift of 2, we move each bit 2 place to the left

  • The digit in the 128 (MSB) and 64 column will move left causing an overflow error

  • The 1 and 2 column become empty so are filled with a 0

128

64

32

16

8

4

2

1

 

0

1

1

1

0

0

= 28

0

1

1

1

0

0

0

0

= 112

  • The original binary representation of denary 28 (16+8+4)  has multiplied by 4 and became 112 (64+32+16)

How do you perform a logical right shift of 1?

  • Here is the binary representation of the denary number 40

128

64

32

16

8

4

2

1

0

0

1

0

1

0

0

0

  • To perform a right binary shift of 1, we move each bit 1 place to the right

  • The digit in the 1 column (LSB) will  move right causing an underflow error

  • The 128 column becomes empty so is filled with a 0

128

64

32

16

8

4

2

1

 

0

0

1

0

1

0

0

= 40

0

0

0

1

0

1

0

0

= 20

  • The original binary representation of denary 40 (32+8)  has divided by 2 and became 20 (16+4)

How do you perform a logical right shift of 2?

  • Here is the binary representation of the denary number 200

128

64

32

16

8

4

2

1

1

1

0

0

1

0

0

0

  • To perform a right binary shift of 2, we move each bit 2 places to the right

  • The digits in the 1 (LSB) and 2 columns will move right causing an underflow error

  • The 128 and 64 columns become empty so are filled with a 0

128

64

32

16

8

4

2

1

 

1

1

0

0

1

0

= 200

0

0

1

1

0

0

1

0

= 50

  • The original binary representation of denary 200 (128+64+8) has divided by 4 and became 50 (32+16+2)

What is an arithmetic binary shift?

  • An arithmetic binary shift is used to divide signed binary integers by moving bits right

  • Multiplication on signed binary integers by moving bits left can not be completed because the MSB is not preserved

Example

  • Take the 8 bit signed binary integer

-128

64

32

16

8

4

2

1

 

1

0

0

0

0

0

1

1

= -125

  • Using a logical binary shift of 1 place right would mean the MSB moves 1 place right, leaving an empty space to be filled with a 0, changing the value from negative to positive

  • This results in a lack of precision and is why this method cannot be used

  • In order to successfully complete the right shift, an arithmetic binary shift should be used

  • As with a logical binary shift all bits move to the right, except, the MSB after moving is copied back to it's original state

-128

64

32

16

8

4

2

1

 

1

1

0

0

0

0

0

1

= -63

  • In this example an arithmetic binary shift of 1 place right would convert -125 to -63

Worked Example

1. Perform a logical binary shift of 2 places left on the binary number 00001110 [1]

2. Explain the effect of performing a 2 place shift to the left on the binary number 00001110  [2]

Answers

Q1

left-binary-shift
  • Cross out the first 2 digits from the left

  • Write down the binary digits left and add 2 zeros to the end

Q2

  • Multiplies the number by 4

  • Overflow errors can cause loss of precision

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