DP IB Physics: HL

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First teaching 2014

Last exams 2024

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12.2.3 Deviations from Rutherford Scattering

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Deviations from Rutherford Scattering

  • Rutherford's alpha scattering experiment originally assumed that the alpha particles are only interacting through electrostatic repulsion
    • However, if the energy of the alpha particles exceeds 27.5 - 28 MeV, then they will be close enough to interact with the nucleus via the strong nuclear force
  • The Rutherford formula describes this as it states that as the angle of scattering angle increases, the number of alpha particles scattered at that angle sharply decreases

N space alpha space fraction numerator 1 over denominator sin to the power of 4 space left parenthesis theta over 2 right parenthesis end fraction

  • Where:
    • N = number of alpha particles
    • θ = angle of scattering
  • Rearranging this equation shows that it should be the case that:

N sin to the power of 4 open parentheses theta over 2 close parentheses equals k

  • Where:
    •  k = a constant
  • Experimental data bears this out, suggesting that the Rutherford formula is correct
  • A number of assumptions are made in deriving this formula, with the main one being that the only force we need to consider is the electric force
  • Deviations from Rutherford scattering are evidence of the strong nuclear force 

12-2-3-rutherford-scattering-deviation-ib-hl

The observed back-scattering from alpha particles strongly deviates from the predicted relationship based only on electromagnetic repulsion at 27.5 MeV

Worked example

Alpha particles undergo scattering after being fired at a thin gold begin mathsize 16px style Au presubscript 79 presuperscript 197 end style foil. The gold is then replaced to make a comparison.

Describe the predicted difference in the scattering pattern when the foil is replaced with aluminium begin mathsize 16px style Al presubscript 13 presuperscript 30 end style foil of the same thickness.

Step 1: Compare the relative charges of the nuclei

    • Gold has 79 protons, aluminium has 13 protons.
    • The electric force between the nuclei is proportional to the charge, since,

begin mathsize 14px style E equals k fraction numerator q Q over denominator r squared end fraction end style

    • Therefore the alpha particle will approach the aluminium nucleus at a much closer distance

Step 2: Consider what causes deviation from Rutherford scattering

    • Deviations from Rutherford scattering occur when forces apart from the electric force between the nuclei are at play
    • At much smaller distances the effect of the strong nuclear force will be felt

Step 3: Deduce the solution

    • The alpha particles get closer to the aluminium nucleus, at a distance the strong nuclear force begins to act
    • More deviation will be seen with aluminium foil than with gold foil

Exam Tip

The greatest deviations from Rutherford scattering occur when the energy of the alpha particles is high and the radius of the target nuclei is small (meaning it has a small nucleon number)

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Katie M

Author: Katie M

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.