DP IB Physics: HL

Revision Notes

Syllabus Edition

First teaching 2014

Last exams 2024

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12.1.5 Matter Waves

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Matter Waves

  • De Broglie proposed that electrons travel through space as a wave
    • This would explain why they can exhibit behaviour such as diffraction
  • He therefore suggested that electrons must also hold wave properties, such as wavelength
    • This came to be known as the de Broglie wavelength

  • However, he realised all particles can show wave-like properties, not just electrons
    • He hypothesised that all moving particles have a matter wave associated with them
  • This is known as the de Broglie wavelength, and can be defined as:

The wavelength associated with a moving particle

  • The majority of the time, and for everyday objects travelling at normal speeds, the de Broglie wavelength is far too small for any quantum effects to be observed
    • A typical electron in a metal has a de Broglie wavelength of about 10 nm
  • Therefore, quantum mechanical effects will only be observable when the width of the sample is around that value

Electron Diffraction Experiment

  • The electron diffraction tube can be used to investigate how the wavelength of electrons depends on their speed
    • The smaller the radius of the rings, the smaller the de Broglie wavelength of the electrons

  • As the voltage is increased:
    • The energy of the electrons increases
    • The radius of the diffraction pattern decreases

  • This shows as the speed of the electrons increases, the de Broglie wavelength of the electrons decreases

  • Using ideas based upon the quantum theory and Einstein’s theory of relativity, de Broglie suggested that the momentum (p) of a particle and its associated wavelength (λ) are related by the equation:

begin mathsize 14px style lambda equals h over p end style

  • Since momentum p = mv, the de Broglie wavelength can be related to the speed of a moving particle (v) by the equation:

size 14px lambda size 14px equals fraction numerator size 14px h over denominator size 14px m size 14px v end fraction

Kinetic Energy 

  • Since kinetic energy E = ½ mv2
  • Momentum and kinetic energy can be related by:

begin mathsize 14px style E equals fraction numerator p squared over denominator 2 m end fraction rightwards arrow p equals square root of 2 m E end root end style

  • Combining this with the de Broglie equation gives a form which relates the de Broglie wavelength of a particle to its kinetic energy:

begin mathsize 14px style lambda equals fraction numerator h over denominator square root of 2 m E end root end fraction end style

  • Where:
    • λ = the de Broglie wavelength (m)
    • h = Planck’s constant (J s)
    • p = momentum of the particle (kg m s-1)
    • E = kinetic energy of the particle (J)
    • m = mass of the particle (kg)
    • v = speed of the particle (m s-1)

Worked example

A proton and an electron are each accelerated from rest through the same potential difference.

Determine the ratio: begin mathsize 14px style fraction numerator de space Broglie space wavelength space of space the space proton over denominator de space Broglie space wavelength space of space the space electron end fraction end style

  • Mass of a proton = 1.67 × 10–27 kg
  • Mass of an electron = 9.11 × 10–31 kg

2.5.4 De Broglie Wavelength Worked Example

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Katie M

Author: Katie M

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.