Electric Field Strength
- An electric field is a region of space in which an electric charge “feels” a force
- The electric field strength at a point is defined as:
The electrostatic force per unit positive charge acting on the charge at that point
- The electric field strength can be calculated using the equation:
- Where:
- E = electric field strength (N C−1)
- F = electrostatic force on the charge (N)
- Q = charge (C)
- It is important to use a positive test charge in this definition, as this determines the direction of the electric field
- The electric field strength is a vector quantity, it is always directed:
- Away from a positive charge
- Towards a negative charge
Worked Example
A charged particle is in an electric field with electric field strength 3.5 × 104 N C−1 where it experiences a force of 0.3 N.
Calculate the charge of the particle.
Electric Field Strength in a Uniform Field
- The magnitude of the electric field strength in a uniform field between two charged parallel plates is defined as:
- Where:
- E = electric field strength (V m−1)
- V = potential difference between the plates (V)
- d = separation between the plates (m)
- Note: the electric field strength is now also defined by the units V m−1
- The equation shows:
- The greater the voltage between the plates, the stronger the field
- The greater the separation between the plates, the weaker the field
- This equation cannot be used to find the electric field strength around a point charge (since this would be a radial field)
- The direction of the electric field is from the plate connected to the positive terminal of the cell to the plate connected to the negative terminal
The E field strength between two charged parallel plates is the ratio of the potential difference and separation of the plates
- Note: if one of the parallel plates is earthed, it has a voltage of 0 V
Derivation of Electric Field Strength Between Plates
- When two points in an electric field have a different potential, there is a potential difference between them
- To move a charge across that potential difference, work needs to be done
- Two parallel plates with a potential difference ΔV across them create a uniform electric field
The work done on the charge depends on the electric force and the distance between the plates
- Potential difference is defined as the energy, W, transferred per unit charge, Q, this can also be written as:
- Therefore, the work done in transferring the charge is equal to:
- When a charge Q moves from one plate to the other, its work done is:
- Where:
- W = work done (J)
- F = force (N)
- d = distance (m)
- Equate the expressions for work done:
- Rearranging the fractions by dividing by Q and d on both sides gives:
- Since
the electric field strength between the plates can be written as:
Worked Example
Two parallel metal plates are separated by 3.5 cm and have a potential difference of 7.9 kV.
Calculate the magnitude of the electric force acting on a stationary charged particle between the plates that has a charge of 2.6 × 10-15 C.
-
- Potential difference, V = 7.9 kV = 7.9 × 103 V
- Distance between plates, d = 3.5 cm = 3.5 × 10−2 m
- Charge, Q = 2.6 × 10−15 C
Step 4: Substitute the values into the electric force equation
Step 5: State the final answer
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The magnitude of the electric force acting on this charged particle is 5.9 × 10−10 N
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Exam Tip
Remember the equation for electric field strength with V and d is only used for parallel plates, and not for point charges (where you would use )