Acceleration (CIE IGCSE Physics)

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Acceleration

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  • Acceleration is defined as the rate of change of velocity
    • In other words, it describes how much an object's velocity changes every second

  • The equation below is used to calculate the average acceleration of an object:

 acceleration space equals space fraction numerator change space in space velocity over denominator change space in space time end fraction

a space equals space fraction numerator increment v over denominator increment t end fraction

  • Where:
    • a = acceleration in metres per second squared (m/s2)
    • Δv = change in velocity in metres per second (m/s)
    • Δt = time taken in seconds (s)

  • The change in velocity is found by the difference between the initial and final velocity, as written below:

change in velocity = final velocity − initial velocity

Δv = vu

  • Where:
    • v = final velocity in metres per second (m/s)
    • u = initial velocity in metres per second (m/s)

  • The equation for acceleration can be rearranged with the help of a formula triangle as shown:

1-2-2-acceleration-triangle-cie-igcse-23-rn

Speeding Up & Slowing Down

  • An object that speeds up is accelerating
  • An object that slows down is decelerating
  • The acceleration of an object can be positive or negative, depending on whether the object is speeding up or slowing down
    • If an object is speeding up, its acceleration is positive
    • If an object is slowing down, its acceleration is negative (sometimes called deceleration)

Acceleration Examples, downloadable IGCSE & GCSE Physics revision notes

A rocket speeding up (accelerating) and a car slowing down (decelerating)

Worked example

A Japanese bullet train decelerates at a constant rate in a straight line. The velocity of the train decreases from 50 m/s to 42 m/s in 30 seconds.

(a) Calculate the change in velocity of the train.

(b) Calculate the deceleration of the train, and explain how your answer shows the train is slowing down.

Part (a)

Step 1: List the known quantities

    • Initial velocity = 50 m/s
    • Final velocity = 42 m/s

Step 2: Write the relevant equation

change in velocity = final velocity − initial velocity

Step 3: Substitute values for final and initial velocity

change in velocity = 42 − 50 = −8 m/s

Part (b)

Step 1: List the known quantities

    • Change in velocity, Δv = − 8 m/s
    • Time taken, t = 30 s

Step 2: Write the relevant equation

 a space equals space fraction numerator increment v over denominator increment t end fraction

Step 3: Substitute the values for change in velocity and time

a = −8 ÷ 30 = −0.27 m/s

Step 4: Interpret the value for deceleration

    • The answer is negative, which indicates the train is slowing down

Exam Tip

Remember the units for acceleration are metres per second squared, m/s2. In other words, acceleration measures how much the velocity (in m/s) changes every second, m/s/s.

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Leander

Author: Leander

Leander graduated with First-class honours in Science and Education from Sheffield Hallam University. She won the prestigious Lord Robert Winston Solomon Lipson Prize in recognition of her dedication to science and teaching excellence. After teaching and tutoring both science and maths students, Leander now brings this passion for helping young people reach their potential to her work at SME.