Expanding & Factorising (AQA GCSE Further Maths)

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Maths

Basic Expanding & Factorising

How do I expand brackets?

  • Expanding brackets means multiplying all the terms inside a bracket by the term outside of the bracket
  • For GCSE Mathematics you will have learnt how to expand a single bracket
    • Multiply each term inside the bracket by the term outside the bracket

table row cell 2 x open parentheses 3 x minus 4 y plus 5 close parentheses end cell equals cell 2 x cross times 3 x minus 2 x cross times 4 y plus 2 x cross times 5 end cell row blank equals cell 6 x squared minus 8 x y plus 10 x end cell end table

  • You will also have learnt how to expand double brackets
    • You can turn this into two single brackets by multiplying each term inside one bracket by the other bracket
    • For Level 2 Further Mathematics you might get more than two terms in a bracket
      • Therefore using a grid or turning the expression into single brackets will be more helpful than using FOIL

table row cell open parentheses 2 x plus 5 close parentheses open parentheses 3 x minus 4 y plus 5 close parentheses end cell equals cell 2 x open parentheses 3 x minus 4 y plus 5 close parentheses plus 5 open parentheses 3 x minus 4 y plus 5 close parentheses end cell row blank equals cell 6 x squared minus 8 y x plus 10 x plus 15 x minus 20 y plus 25 end cell row blank equals cell 6 x squared plus negative 8 x y plus 25 x minus 20 y plus 25 end cell end table

  • A bracket that is raised to the power of 2 can also be written as a double bracket
    • open parentheses x plus y plus z close parentheses squared equals open parentheses x plus y plus z close parentheses open parentheses x plus y plus z close parentheses
    • Write as a double bracket and then expand
      • Do not just square each term inside the bracket
  • Be very careful when working with negatives
  • Remember to simplify expressions where possible

How do I factorise out a term from an expression?

  • Factorising is the opposite of expanding
  • Firstly find the highest common factor of each term in the expression and put this outside a bracket
    • The highest common factor could be a single number or a variable or both 
      • 12 x plus 8 equals 4 open parentheses... plus... close parentheses
      • 2 x squared minus 5 x equals x open parentheses... negative... close parentheses
      • 6 x squared plus 8 x y plus 4 x equals 2 x open parentheses... plus... plus... close parentheses
    • If the terms involve the same variable(s) to different powers then the highest common factor will include the variable(s) with the smallest power
      • 4 x to the power of 5 plus 5 x to the power of 4 equals x to the power of 4 open parentheses... plus... close parentheses
      • 6 x to the power of 4 y to the power of 7 minus 8 x to the power of 9 y to the power of 5 equals 2 x to the power of 4 y to the power of 5 open parentheses... negative... close parentheses
    • The highest common factor could also contain brackets
      • open parentheses x plus 1 close parentheses squared plus 5 open parentheses x plus 1 close parentheses equals open parentheses x plus 1 close parentheses open parentheses... plus... close parentheses
      • open parentheses x plus 1 close parentheses open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses plus open parentheses x plus 1 close parentheses open parentheses x plus 2 close parentheses open parentheses x plus 4 close parentheses equals open parentheses x plus 1 close parentheses open parentheses x plus 2 close parentheses open parentheses... plus... close parentheses
  • Then find what you need to multiply the highest common factor by to get each term
    • You might need to use the index law: x to the power of a cross times x to the power of b equals x to the power of a plus b end exponent

Worked example

(a)

Expand and simplify open parentheses x plus 4 close parentheses open parentheses x to the power of 4 minus 5 x cubed plus 4 x squared minus 7 x close parentheses.

The second bracket has more than two terms so turn the expression into single bracket expansions

table row cell open parentheses x plus 4 close parentheses open parentheses x to the power of 4 minus 5 x cubed plus 4 x squared minus 7 x close parentheses end cell equals cell x open parentheses x to the power of 4 minus 5 x cubed plus 4 x squared minus 7 x close parentheses plus 4 open parentheses x to the power of 4 minus 5 x cubed plus 4 x squared minus 7 x close parentheses end cell row blank equals cell x to the power of 5 minus 5 x to the power of 4 plus 4 x cubed minus 7 x plus 4 x to the power of 4 minus 20 x cubed plus 16 x squared minus 28 x end cell end table

Collect like terms

bold italic x to the power of bold 5 bold minus bold italic x to the power of bold 4 bold minus bold 16 bold italic x to the power of bold 3 bold plus bold 9 bold italic x to the power of bold 2 bold minus bold 28 bold italic x

(b)

Factorise fully open parentheses x plus 1 close parentheses open parentheses 2 x plus 3 close parentheses plus open parentheses x plus 1 close parentheses open parentheses x minus 2 close parentheses.

There are two terms in this expression; open parentheses x plus 1 close parentheses open parentheses 2 x plus 3 close parentheses and open parentheses x plus 1 close parentheses open parentheses x minus 2 close parentheses
Both contain the common factor open parentheses x plus 1 close parentheses
As a bracket is a factor, using "big square brackets" can help keep track of what's left

open parentheses x plus 1 close parentheses open parentheses 2 x plus 3 close parentheses plus open parentheses x plus 1 close parentheses open parentheses x minus 2 close parentheses equals open parentheses x plus 1 close parentheses open square brackets table row cell table row cell open parentheses 2 x plus 3 close parentheses end cell plus end table end cell cell open parentheses x minus 2 close parentheses end cell end table close square brackets

Simplify the "big square brackets"

table attributes columnalign right center left columnspacing 0px end attributes row blank equals cell open parentheses x plus 1 close parentheses open parentheses 2 x plus 3 plus x minus 2 close parentheses end cell row blank equals cell open parentheses x plus 1 close parentheses open parentheses 3 x plus 1 close parentheses end cell end table

The whole expression is now fully simplified (but it's always worth checking!)

Expanding Triple Brackets

How do I expand three brackets?

  • Multiply out any two brackets using a standard method and simplify this answer (collect any like terms)
  • Replace the two brackets above with one long bracket containing the expanded result
  • Expand this long bracket with the third (unused) bracket
    • This step often looks like (x + a)(x2 + bx + c)
    • Every term in the first bracket must be multiplied with every term in the second bracket
      • This leads to six terms 
    • A grid can often help to keep track of all six terms, for example (x + 2)(x2 + 3x + 1)
      •   x2 +3x +1
        x x3 3x2

        x

        +2 2x2 6x 2
      • add all the terms inside the grid (diagonals show like terms) to get x3 + 2x2 + 3x2 + 6x + x + 2
      • collect like terms to get the final answer of x3 + 5x2 + 7x + 2
  • Simplify the final answer by collecting like terms (if there are any)
  • It helps to put negative terms in brackets when multiplying

Worked example

Expand  open parentheses 2 x minus 3 close parentheses open parentheses x plus 4 close parentheses open parentheses 3 x minus 1 close parentheses.

Start by expanding the first two sets of brackets and simplify by collecting 'like' terms

table row blank blank cell open parentheses 2 x minus 3 close parentheses open parentheses x plus 4 close parentheses end cell row blank equals cell 2 x cross times x plus 2 x cross times 4 plus open parentheses negative 3 close parentheses cross times x plus open parentheses negative 3 close parentheses cross times 4 end cell row blank equals cell 2 x squared plus 8 x minus 3 x minus 12 end cell row blank equals cell 2 x squared plus 5 x minus 12 end cell end table

Rewrite the original expression with the first two brackets expanded

open parentheses 2 x squared plus 5 x minus 12 close parentheses open parentheses 3 x minus 1 close parentheses

Multiply all of the terms in the first set of brackets by all of the terms in the second set of brackets

2 x squared cross times 3 x plus 5 x cross times 3 x plus open parentheses negative 12 close parentheses cross times 3 x plus 2 x squared cross times open parentheses negative 1 close parentheses plus 5 x cross times open parentheses negative 1 close parentheses plus open parentheses negative 12 close parentheses cross times open parentheses negative 1 close parentheses

Simplify

6 x cubed plus 15 x squared minus 36 x minus 2 x squared minus 5 x plus 12

Collect 'like' terms

bold 6 bold italic x to the power of bold 3 bold plus bold 13 bold italic x to the power of bold 2 bold minus bold 41 bold italic x bold plus bold 12

Factorising by Grouping

How do I factorise expressions with common brackets?

  • To factorise 3x(t + 4) + 2(t + 4), both terms have a common bracket, (t + 4)
    • the whole bracket, (t + 4), can be "taken out" like a common factor
      • (t + 4)(3x + 2)
    • this is like factorising 3xy + 2y to y(3x + 2)
      • y represents (t + 4) above

 

How do I factorise by grouping?

  • Some questions may require you to form the common bracket yourself
    • for example, factorise xy + px + qy + pq
      • "group" the first pair of terms, xy + px, and factorise, x(y + p)
      • "group" the second pair of terms, qy + pq, and factorise, q(y + p),
    • now factorise x(y + p) + q(y + p) as above
      • (y + p)(x + q)
    • This is called factorising by grouping
  • The groupings are not always the first pair of terms and the second pair of terms, but two terms with common factors

Exam Tip

  • As always, once you have factorised something, expand it by hand to check your answer is correct.

Worked example

Factorise ab + 3b + 2a + 6.

 

Method 1
Notice that
ab and 3b have a common factor of b
Notice that 2a and 6 have a common factor of 2

Factorise the first two terms, using b as a common factor

b(a + 3) + 2+ 6 

Factorise the second two terms, using 2 as a common factor 

b(a + 3) + 2(a + 3) 

(+ 3) is a common bracket 
We can factorise using (a + 3) as a factor

(a + 3)(b + 2)

Method 2
Notice that
ab and 2a have a common factor of a
Notice that 3b and 6 have a common factor of 3

Rewrite the expression grouping these terms together 

ab + 2a + 3b + 6 

Factorise the first two terms, using a as a common factor 

a(b + 2) + 3b + 6 

Factorise the second two terms, using 3 as a common factor 

a(b + 2) + 3(b + 2) 

(b + 2) is a common bracket
 
We can factorise using (b + 2) as a factor

(b + 2)(a + 3)

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Dan

Author: Dan

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.