AQA A Level Physics

Revision Notes

12.3.8 Relativistic Mass

Equivalence of Mass & Energy

  • Einstein showed in a1905 paper that matter can be considered a form of energy and hence, he proposed:
    • Mass can be converted into energy
    • Energy can be converted into mass
  • This is known as mass-energy equivalence, and can be summarised by the equation:

E space equals space m c squared

  • Where:
    • E = energy (J)
    • m = mass (kg)
    • c = the speed of light (m s-1)
  • Scenarios where mass is converted to energy or energy to mass include:
    • The fusion of hydrogen into helium in the centre of the Sun
    • The fission of uranium in nuclear power plants
    • Nuclear weapons
    • High-energy particle collisions in particle accelerators

Relativistic Mass

  • An object's proper mass (that is, its mass measured by an observer at rest relative to the object) is also called its rest massm0
  • An observer in an inertial reference frame moving at speed relative to the object measures the object's mass as m, which is given by:

m space equals space fraction numerator m subscript 0 over denominator square root of 1 space minus space v squared over c squared end root end fraction

  • This can also be written as:

m space equals space gamma m subscript 0

  • Because γ > 1, when an object is moving relative to your frame of reference, you measure its mass as larger than it's rest mass
    • The derivation for this relativistic mass is a good deal more complex than the derivation for relativistic time and length and is not examinable so it is omitted from this revision note
  • One interesting outcome of this relativistic mass is the speed limit imposed on objects
    • As an object's speed nears the speed of light, it's mass gets larger and larger
    • Very close to the speed of light, an object's mass tends towards an infinite mass

Graph showing how relativistic mass changes with velocity

12-3-8-mass-vs-speed

The effect of speed, as a fraction of c, on an object's mass, in multiples of rest mass. Mass increases rapidly as the object's speed approaches c.

Relativistic Energy

  • Let's reconsider Einstein's famous equation, taking relativistic effects into account:

E space equals space open parentheses gamma m subscript 0 close parentheses c squared

E space equals space fraction numerator m subscript 0 c squared over denominator square root of 1 space minus space v squared over c squared end root end fraction

  • The mass of a stationary object is its rest massm0, so it has a rest energy of m0c2

Worked example

A particle in a particle accelerator has a rest mass of M0 and is accelerated to a maximum speed of 0.998c.

Calculate the total energy of the particle at its maximum speed, as a multiple of its proper energy, from the reference frame of an observer who is stationary relative to the accelerator.

Answer:

Step 1: List the known quantities:

  • Maximum speed, v = 0.998c

Step 2: Write down the relevant equations:

  • Rest energy, E0 m0c2
  • Relativistic energy, E = γm0c2
  • Write the equation with the gamma term out in full

E space equals space fraction numerator m subscript 0 c squared over denominator square root of 1 space minus space v squared over c squared end root end fraction

Step 3: Substitute the known quantities:

  • The relativistic energy in terms of rest mass M0 is

E space equals space fraction numerator M subscript 0 c squared over denominator square root of 1 space minus space open parentheses 0.998 c close parentheses squared over c squared end root end fraction space equals space fraction numerator M subscript 0 c squared over denominator square root of 1 space minus space 0.998 squared end root end fraction space equals space 15.8 M subscript 0 c squared

Step 4: Give the answer as a multiple of proper energy:

  • Proper energy is another way of saying rest energy, which is M0c2
  • The particle's energy is 15.8 times larger than the rest energy, according to the observer

Exam Tip

When you see a speed and a mass, it's tempting to go into auto-pilot and stick everything into the equation Ek = ½mv2, but this would gain you no marks in this worked example! The trick is to look at how large the speed is, if it is close to the speed of light, the relativistic effects are significant and you need to account for them. The context of the question can also provide clues, such as mentioning frames of reference or rest mass.

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Dan MG

Author: Dan MG

Dan graduated with a First-class Masters degree in Physics at Durham University, specialising in cell membrane biophysics. After being awarded an Institute of Physics Teacher Training Scholarship, Dan taught physics in secondary schools in the North of England before moving to SME. Here, he carries on his passion for writing enjoyable physics questions and helping young people to love physics.