Floyd's Algorithm (Edexcel A Level Further Maths: Decision Maths 1)

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Floyd's Algorithm

What is Floyd's Algorithm?

  • Floyd's algorithm finds the shortest distance and the shortest route between any pair of nodes in a network
  • This is achieved by setting up and updating a pair of matrices
    • The first is a matrix of (least) distances between nodes
      • it is generally called the distance matrix 
      • the final distance matrix shows the shortest distance between any pair of nodes
    • The second matrix allows the shortest route between nodes to be deduced
      • it is generally called the route matrix
  • At each stage (iteration) of Floyd's algorithm, both the distance matrix and route matrix are updated
  • Floyd's algorithm will seem long winded and slow at first
    • But the symmetry (in undirected networks) in the distance matrix can reduce the amount of work involved whilst also acting as a check

 

How do I set up the initial distance matrix and initial route matrix for Floyd's algorithm?

  • The initial distance matrix has the direct distances between nodes
    • If there is no direct distance the symbol infinity is used (to represent/assume a very large distance!)
    • In an undirected network, all distance matrices will exhibit symmetry
      • this is because the distance from node A to C, say, will be the same as the distance from C to A
      • this will apply to all pairs of nodes
      • this helps reduce the work required in Floyd's algorithm but also acts as a means of checking each distance matrix 
  • The initial route matrix assumes the shortest route between each pair of nodes is a direct link
    • So the shortest route between A and D, say, is to go directly from A to D
    • It doesn't matter if there is no direct link between a pair of nodes
      • this will be accounted for later in Floyd's algorithm

Worked example

For the network shown below, set up the initial distance matrix and the initial route matrix for Floyd's algorithm.

floyd-we-network

Use the direct distances given on the diagram
Where there is no direct link, use infinity for the (initial) distance

There is a direct link between nodes A and C, with a distance of 5, so row A, column C will contain a 5
(This is also true for row C, column A, as the network is undirected)

There is no direct link between nodes A and E, so use infinity (also true for row E, column A)

  Initial distance matrix
  A B C D E
A - 7 5 10 bold infinity
B 7 - 4 17 3
C 5 4 - 6 bold infinity
D 10 17 6 - 3
E bold infinity 3 bold infinity 3 -

The initial route matrix has the destination node directly in place for each starting node

  Initial route matrix
  A B C D E
A A B C D E
B A B C D E
C A B C D E
D A B C D E
E A B C D E

How do I update the distance matrix in Floyd's algorithm?

  • For the FIRST iteration highlight the first row and the first column of the distance matrix
    • For the other cells in the distance matrix (except those labelled with a '-')
      • add the corresponding highlighted distances together
      • if this is less than the current distance, then the current distance gets updated

floyd-1st-iteration-distance

  • This process of updating distances is repeated for each iteration of Floyd's algorithm
    • The number of iterations will be equal to the number of nodes
      • On the second iteration, the SECOND row and SECOND column would be highlighted
      • On the k to the power of th iteration, the k to the power of th row and column would be highlighted

How do I update the route matrix in Floyd's algorithm?

  • For the FIRST iteration, highlight the first column of the route matrix
  • Find the corresponding cells that have been updated in the distance matrix for this iteration
    • These cells are updated with the node in the highlighted column

floyd-1st-iteration-route

  • This process of updating routes is repeated for each iteration of Floyd's algorithm
    • The number of iterations will be equal to the number of nodes
      • On the second iteration, the SECOND column would be highlighted
      • On the k to the power of th iteration, the k to the power of th column would be highlighted

Exam Tip

  • An exam question is unlikely to ask you to do all iterations of Floyd's algorithm
    • Make sure you can recognise where to start if given matrices after, say, the third iteration

Worked example

The distance and route matrices below follow one complete iteration of Floyd's algorithm.

  Distance matrix       Route matrix
  A B C D E       A B C D E
A - 7 5 10 infinity     A A B C D B
B 7 - 4 17 3     B A B C A E
C 5 4 - 6 infinity     C A B C D E
D 10 17 6 - 3     D A A C D E
E infinity 3 infinity 3 -     E A B C D E

Complete the remaining iterations of Floyd's algorithm, showing both the distance and route matrices after each iteration.

2nd Iteration

In the distance matrix, row A, column E, 3 + 7 = 10 and 10 < infinity so the distance is changed to 10

Row C, column E, 3 + 4 = 7 and 7 < ∞ so the distance is changed to 7

Likewise for row E and columns A and C (note the symmetry as the network is undirected)

In the route matrix, corresponding cells are changed

  Distance matrix       Route matrix
  A B C D E       A B C D E
A - 7 5 10 10     A A B C D B
B 7 - 4 17 3     B A B C A E
C 5 4 - 6 7     C A B C D B
D 10 17 6 - 3     D A A C D E
E 10 3 7 3 -     E B B B D E

3rd iteration

Row B, column D, 6 + 4 = 10 and 10 < 17 so distance is changed to 10

This is the same for row D, column B and the corresponding route matrix cells are updated too

  Distance matrix       Route matrix
  A B C D E       A B C D E
A - 7 5 10 10     A A B C D B
B 7 - 4 10 3     B A B C C E
C 5 4 - 6 7     C A B C D B
D 10 10 6 - 3     D A C C D E
E 10 3 7 3 -     E B B B D E

4th iteration

There are no changes in this iteration, but note that there still could be changes in the fifth iteration

  Distance matrix       Route matrix
  A B C D E       A B C D E
A - 7 5 10 10     A A B C D B
B 7 - 4 10 3     B A B C C E
C 5 4 - 6 7     C A B C D B
D 10 10 6 - 3     D A C C D E
E 10 3 7 3 -     E B B B D E

5th iteration (final iteration)

There are two cells to change on this iteration

  Distance matrix       Route matrix
  A B C D E       A B C D E
A - 7 5 10 10     A A B C D B
B 7 - 4 6 3     B A B C E E
C 5 4 - 6 7     C A B C D B
D 10 6 6 - 3     D A E C D E
E 10 3 7 3 -     E B B B D E

Final matrices

  Final distance matrix       Final route matrix
  A B C D E       A B C D E
A - 7 5 10 10     A A B C D B
B 7 - 4 6 3     B A B C E E
C 5 4 - 6 7     C A B C D B
D 10 6 6 - 3     D A E C D E
E 10 3 7 3 -     E B B B D E

How do I use Floyd's algorithm to find shortest distances and routes?

  • The shortest distance is found by reading off the value from the final distance matrix
  • To find the shortest route between nodes, use the final route matrix
    • start on the row for the starting node
    • find the cell that is under the destination node, then move to that row
    • repeat until the cell contains the destination node

Exam Tip

  • Exam questions will often involve the final matrices so questions can be asked about shortest distances and routes
  • The far majority of networks are undirected
    • there will be symmetry in each distance matrix
    • this can cut down the amount of work needed at each iteration of Floyd's algorithm
    • but the repetition can also act as a check

Worked example

The final distance and route matrices for Floyd's algorithm are given below.

  Final distance matrix       Final route matrix
  A B C D E       A B C D E
A - 7 5 10 10     A A B C D B
B 7 - 4 6 3     B A B C E E
C 5 4 - 6 7     C A B C D B
D 10 6 6 - 3     D A E C D E
E 10 3 7 3 -     E B B B D E

a)
i)
Find the shortest distance between nodes A and E.

ii)
Find the shortest distance between nodes B and C.

UL2EHNWX_picture-1

i)
Use the final distance matrix to find where row A meets column E

10

Also from row E, column A

ii)
Use the final distance matrix to find where row B meets column C

4

 Also from row C, column B

b)
Find the shortest route between nodes B and D.

GcyaGeij_picture-2

Start on row B (start node)
Node E is indicated under the destination node column (D) for this row, so move to row E
Node D is indicated under the destination node (D) so the route is complete

The shortest route is BED

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Paul

Author: Paul

Paul has taught mathematics for 20 years and has been an examiner for Edexcel for over a decade. GCSE, A level, pure, mechanics, statistics, discrete – if it’s in a Maths exam, Paul will know about it. Paul is a passionate fan of clear and colourful notes with fascinating diagrams – one of the many reasons he is excited to be a member of the SME team.