Communication & Homeostasis (OCR A Level Biology)

Topic Questions

1a
Sme Calculator
4 marks
(i)
State what homeostasis is.

[1]

(ii)

Blood pH is a physiological factor that is controlled by homeostasis in mammals.

Give three other examples of physiological factors that are controlled by homeostasis in mammals.

[3]

1b
Sme Calculator
3 marks

Explain why homeostasis is important.

1c
Sme Calculator
4 marks

It is important that organisms are able to control their blood pH level as fluctuations in this can affect enzyme activity.

(i)
Name the part of an enzyme that is affected by extremes of pH.
[1]
(ii)
Explain how the part of the enzyme named in i) is affected by extremes of pH.
[3]

Did this page help you?

2a
Sme Calculator
6 marks

The nervous and endocrine systems in mammals allow for communication between different parts of the body. This plays an important role in the process of homeostasis.

(i)

The nervous system consists of two regions which extend across the entire human body. 

Name these two regions and identify the structures that they are made up of.

[4]

(ii)
Describe the pathway within the nervous system that allows for the coordination and regulation of body functions.
[2]
2b
Sme Calculator
6 marks

The endocrine system is made up of glands which produce chemicals carried by the blood.

(i)
Name the chemicals produced by endocrine glands and describe their function.

[2]

(ii)
The diagram below shows the major endocrine glands in a male human.ocr-a-5-1e-sq-glands-diagram

State the names of the glands labelled Y and Z.
[2]
(iii)

The gland labelled X on the diagram is sometimes referred to as the ‘master gland’.

Name this gland and explain why it is referred to as the master gland.

[2]

Did this page help you?

3a
Sme Calculator
4 marks

Negative feedback is used in the majority of homeostatic control mechanisms.

(i)
Describe the role of receptors and effectors as two components of a negative feedback control loop.

[2]

(ii)
Describe the effect of a negative feedback loop on a factor that has increased above its normal range.

[2]

3b
Sme Calculator
4 marks
(i)
Describe what positive feedback is.

[2]

(ii)

Blood glucose levels are controlled by the release of insulin and glucagon hormones from the pancreas.

When blood glucose levels rise, the pancreas releases insulin which causes target cells to take up glucose and the liver to convert glucose into glycogen. This causes blood glucose levels to fall again.

State whether the control of blood glucose levels is an example of negative or positive feedback and explain why.

[2]

Did this page help you?

4a
Sme Calculator
5 marks
(i)
State what cell signalling is and explain why it is important.

[2]

(ii)
Describe the stages of cell signalling.

[3]

4b
Sme Calculator
4 marks

Cell signalling can occur via paracrine signalling and endocrine signalling.

For each type of cell signalling, describe when each pathway would be used and identify the type of signalling molecule used.

4c
Sme Calculator
4 marks

Transmission of messages in cell signalling pathways requires crossing cell surface membranes.

(i)
Name the two types of receptor molecules that are found on or in the cell surface membrane.

[2]

(ii)
Describe how receptor molecules on cell surface membranes are involved in cell signalling.

[2]

Did this page help you?

5a
Sme Calculator
2 marks

One factor that is controlled by homeostasis is body temperature.

Explain why it is important that a stable core temperature is maintained in organisms.

5b
Sme Calculator
4 marks

Thermoregulation is the control of internal core body temperature. Animals can be split into endotherms and ectotherms depending on the methods used by the animal for thermoregulation.

(i)
Describe the differences between endotherms and ectotherms in terms of thermoregulation.

[2]

(ii)
Describe the two ways in which endotherms detect changes in temperature.
[2]
5c
Sme Calculator
5 marks
(i)

Describe how vasoconstriction is used in endotherms as a warming mechanism in thermoregulation.

[3]

(ii)
Name two other warming mechanisms used by endotherms.
[2]

Did this page help you?

1a
Sme Calculator
6 marks

The polar bear, Ursus maritimus, is a large bear native to the Arctic and nearby areas. They have unique adaptations that allow them to thermoregulate effectively, some of which are shown in the image below.ocr-a-5-1h-sq-polar-bear-fur

Identify two adaptations shown in the image, and explain how they help the polar bear to thermoregulate.

1b
Sme Calculator
3 marks

Polar bears also have a specialised, countercurrent circulatory system.

Suggest how this adaptation helps polar bears to regulate their body temperature.

1c
Sme Calculator
6 marks

A recent study found that polar bears have evolved genes that produce more nitric acid than other bear species. Nitric acid controls whether cells use their available nutrients to produce metabolic energy, or convert it into body heat.

(i)

Nitric acid is acting as a signalling molecule in the polar bear.

Explain why.

[2]

(ii)
Explain how polar bears have evolved to have this trait.
[4]

Did this page help you?

2a
Sme Calculator
6 marks

The series of stages below outline the events that occur when blood volume decreases due to a significant blood loss.ocr-a-5-1h-sq-homeostasis-flow-chart

(i)
Explain how the release of aldosterone results in an increase in blood pressure.
[3]
(ii)

The normal range for 24-hour urine output volume is between 800 and 2000 ml per day. A patient admitted to hospital with significant blood loss showed an output of 250 ml in 24 hours. 

Explain why.

[3]

2b
Sme Calculator
2 marks

As the action of aldosterone takes effect, this is detected by receptors in the body and the secretion of aldosterone decreases.

Name and describe the mechanism that results in this decrease.

2c
Sme Calculator
3 marks

Suggest and explain the effect of blood loss on heart rate.

Did this page help you?

3a
Sme Calculator
4 marks

Suggest how the opening of stomata can contribute towards homeostatic mechanisms in plants.

3b
Sme Calculator
3 marks

Explain why the homeostatic control of gas exchange in plants is important in maximising the growth rate of plants.

3c
Sme Calculator
2 marks

The image below shows stomata viewed using a light microscope. The image magnification is x60.

ocr-a-5-1h-sq-stomata-image

The measured length of one stoma in the image is 4 mm.

Calculate the actual size of the stoma, giving the answer in µm and to three significant figures.

Did this page help you?

4a
Sme Calculator
3 marks
(i)

An example of cell signalling occurs when glycoproteins called cytokines are produced by T lymphocytes.

Describe the signalling effects of cytokines on other cells.

[2]

(ii)

Due to their size, cytokines cannot cross the phospholipid bilayer into cells.

Suggest how cytokines trigger a response in target cells.

[1]

4b
Sme Calculator
5 marks

A second cell signalling molecule related to the immune system is histamine which is produced by mast cells when an allergen is detected.

(i)

Histamine stimulates vasodilation as a result of its relaxing effects on vascular smooth muscle.

Describe the events involving histamine which lead to the relaxation of vascular smooth muscle.

[3]

(ii)
Suggest symptoms that someone may experience due to vasodilation during an allergic reaction.
[2]
4c
Sme Calculator
4 marks

The table below shows varying levels of plasma histamine and associated severity of symptoms.

Plasma histamine level (ng / mL) Symptom severity
0.3 - 1.0 Normal range - no symptoms
1.0 - 2.0 Mild
3.0 - 5.0 Moderate

(i)

A patient’s histamine level increased from 0.4 ng / mL to 4.8 ng / mL.

Calculate the percentage increase of the patient’s histamine level.

[2]

(ii)

A second patient had a 56% increase in their histamine levels from 0.9 ng / mL.

State the severity of symptoms that the patient would be experiencing.

[2]

Did this page help you?

5a
Sme Calculator
4 marks
(i)
Gular fluttering is a method used by birds such as the nightjar as a method of thermoregulation. Gular fluttering involves rapid vibration of muscles in the throat and moist buccal cavity with the beak open as it rapidly inhales and exhales.

Suggest how gular fluttering works as an effective cooling mechanism for the nightjar.

[2]

(ii)
Other species of animals may pant to stay cool. Gular fluttering differs from panting in that it does not involve the trachea, lungs and alveoli of the animal.

Suggest how the energy requirement for gular fluttering differs to that of panting.

[2]

5b
Sme Calculator
3 marks

In colder weather, some birds are able to drop their body temperature by between 5 and 7OC and enter a regulated hypothermia.

Suggest how this is beneficial to the bird in cold weather.

5c
Sme Calculator
4 marks

Hypothermia in humans occurs when core body temperature in humans falls below 35oC, and positive feedback causes this decrease in temperature to continue.

Explain how positive feedback could accelerate the process of hypothermia.

Did this page help you?

1a
Sme Calculator
8 marks

Fig. 2.1 shows a naked mole rat, Heterocephalus glaber.

q2-paper-3-june-2019-ocr-a-level-biology

Fig. 2.1

The naked mole rat is a mammal. However, it has several features that are unusual for mammals.

Naked mole rats regulate their temperature in a way that is different from most mammals.

(i)

Some features of thermoregulation in naked mole rats are listed below:

  • They live in complex underground tunnel systems, which tend to have a stable temperature of 30–32 °C. However, sometimes the environmental temperature can increase or decrease outside this range.
  • In experiments that examine environmental temperature changes, the core body temperature of naked mole rats remains close to that of the environmental temperature.
  • When tunnel temperature increases they often move to cooler parts of the tunnel system.
  • When tunnel temperature decreases they often lie together in large groups.

Outline two ways in which thermoregulation in naked mole rats is different from thermoregulation in most mammals.

[2]

(ii)

In humans, when core body temperature falls below 35 °C, positive feedback causes this decrease in core body temperature to continue. This process is known as hypothermia.

Explain how positive feedback could accelerate the process of hypothermia.

[4]

(iii)

Mammals, including naked mole rats, have temperature receptors that play a role in thermoregulation.

The table below lists four statements about mammalian temperature receptors.

Write either ‘true’ or ‘false’ in the empty boxes to indicate whether each statement is true or false.

Statement True or False?
Peripheral temperature receptors detect the temperature of internal organs  
Receptors in the hypothalamus detect core body temperature  
Blood temperature is detected by the receptors in the hypothalamus  
Temperature receptors send impulses to the medulla oblongata, which regulates body temperature  

[2]

1b
Sme Calculator
3 marks

An unusual characteristic of naked mole rats is their tolerance of pain.

Acid causes pain responses in most mammals. Naked mole rats are tolerant of the pain caused by acid.

This tolerance can be explained by the type of pain receptor found in naked mole rats.

Fig. 2.2 shows a representation of the ion channels present in the pain receptors of naked mole rats and other mammals.

q2b-paper-3-june-2019-ocr-a-level-biology

Fig. 2.2

(i)

Use the information in Fig. 2.2 to suggest why naked mole rats do not feel pain when exposed to acid.

 [2]

(ii)

Explain how a pain receptor is an example of a transducer.

 [1]

1c
Sme Calculator
2 marks

Fig. 2.3 shows the relationship between body mass and lifespan in a range of mammal species.

q2c-paper-3-june-2019-ocr-a-level-biology

Fig. 2.3

(i)

Describe the relationship between body mass and lifespan shown in Fig. 2.3.

 [1]

(ii)

What conclusion can you draw from Fig. 2.3 about the lifespan of naked mole rats in comparison to other mammals?

 [1]

1d
Sme Calculator
3 marks

Naked mole rats can survive without oxygen for up to 18 minutes. This is several times longer than other mammals of a similar size.

The following information might help to explain how naked mole rats can survive without oxygen for a long time:

  • In normal glycolysis, the enzymes needed to convert glucose to triose phosphate may be inhibited by lactate.
  • Naked mole rats can use fructose as a respiratory substrate.
  • Fructose is converted to triose phosphate.
  • Triose phosphate can then enter the glycolysis pathway.
(i)

Suggest why the use of fructose allows naked mole rats to survive without oxygen for a long time.

[2]

(ii)

Suggest one other aspect of the physiology of naked mole rats that explains how they are able to survive without oxygen for a long time.

 [1]

Did this page help you?

2
Sme Calculator
3 marks

Many insects such as moths are insulated with scales and hair, and are known as facultative endotherms.

Their metabolism during flight can cause the temperature of the flight muscles to increase 20–30 °C above the external temperature.

(i)

Using the information provided, explain why many moths are described as endothermic.

[1]

(ii)

It is more difficult for moths to maintain their body temperature than for mammals and birds to maintain their body temperature.

Explain why.
[2]

Did this page help you?

3a
Sme Calculator
1 mark

The control of water and glucose levels in the body involves negative feedback loops.

Give an example of a mechanism which involves positive feedback.

Positive feedback could include:                                                        

3b
Sme Calculator
1 mark

Another control mechanism in the body involves the control of blood pH.

Suggest why it is important that an organism maintains a stable blood pH.

3c
Sme Calculator
3 marks

Homeostasis depends heavily on the action of negative feedback in the body.

Explain why homeostasis is controlled by negative feedback and not positive feedback mechanisms.

Did this page help you?

4a
Sme Calculator
5 marks

Explain how the maintenance of a constant body temperature in humans allows metabolic reactions within cells to proceed at maximum efficiency.

4b
Sme Calculator
2 marks

Hypothermia is a condition in which the body's core temperature is lowered. Hypothermia can affect people who take part in outdoor activities in winter without wearing suitable clothing.

Some people believe that consuming alcohol helps to keep warm, as it can give a feeling of warmth. Alcohol causes vasodilation.

Explain why it is not a good idea to give alcohol to someone with hypothermia.

4c
Sme Calculator
4 marks

Fig. 1 shows the heat flow through the skin of an athlete during vigorous exercise.

Exercise starts at 400 seconds.


temperature-change-during-exercise-sq

Fig. 1

Blood flow can be directed to those parts of the body that make the greatest demands.

Describe and explain the events that are occurring at points R and S.

Did this page help you?

5a
Sme Calculator
2 marks

Bees, such as Apis mellifera, are able to alter the temperature of their nests depending on factors such as external temperature. 

When a pathogen infects a colony the bees can raise the temperature of the nest; this is similar in function to humans getting a fever as part of the immune response. 

Explain how this behaviour benefits the colony. 

5b
Sme Calculator
2 marks

If the temperature of the colony becomes too high newly hatched bees may have malformations in their mouthparts and wings, and a shortened lifespan.

Suggest the cause of these malformations.

5c
Sme Calculator
2 marks

Another mechanism that can be used for thermoregulation in bee colonies is a behaviour where adult bees can crawl into cells adjacent to brood cells (containing eggs, larvae or pupae). This is shown in Fig. 1 below. 

bee-thermoregulation-behaviour-labels-sq

Fig. 1

Explain the benefit of this behaviour to the development of the bees in the brood cells. 

5d
Sme Calculator
2 marks

Colonies of bees can go through a system of swarming, where a large group of bees relocates to a new area. 

The image in Fig. 2 shows an example of a bee swarm. 

bee-swarm

Mark Osgatharp, CC BY-SA 3.0 <https://creativecommons.org/licenses/by-sa/3.0>, via Wikimedia Commons

Fig. 2

During the process of swarming the bees cooperate to allow for thermoregulation. 

The bees on the inside regularly swap places with the bees on the outside of the swarm. 

Suggest how this helps the colony to thermoregulate. 

Did this page help you?