The Parabola (Edexcel International A Level Further Maths)
Revision Note
Author
Mark CurtisExpertise
Maths
The Equation of a Parabola
What is a parabola?
A parabola is a U-shaped quadratic curve with a line of symmetry
is a parabola
The line of symmetry is the -axis
is a parabola
The line of symmetry is the -axis
A parabola is part of a family of curves called the conics (or conic sections)
Conics are parabolae, hyperbolae and ellipses
What is the general equation of a parabola?
The general equation for a parabola is
in Cartesian form
in Parametric form
where is a positive constant
The -axis is the line of symmetry, as shown
The general equation can be rearranged
is the branch above the x-axis
is the branch below the x-axis
Exam Tip
You are given the Cartesian and parametric equations of a parabola in the Formulae Booklet.
Worked Example
A parabola has the parametric equations and where .
Show that its Cartesian equation is .
To find the Cartesian equation, eliminate from the parametric equations
It is easier to make the subject of
Substitute this into the equation for and simplify
Make the subject
The Focus & Directrix of a Parabola
What are the focus and directrix of a parabola?
The focus of the parabola is the point on the -axis
The directrix is the vertical line
For example, the parabola where has
a focus at
the directrix
What is the focus-directrix property?
The focus-directrix property says that:
“Points on a parabola are the same distance from the focus as they are horizontally from the directrix”
In other words:
If S is the focus of a parabola
and P is any point on the parabola
and X is the point on the directrix horizontally from P
Then the distance PS equals PX
PS = PX
This property is an example of a locus of points
Exam Tip
You are given the focus and directrix of a parabola in the Formulae Booklet, but not the focus-directrix property.
Worked Example
The diagram shows the point , the vertical line and a general point that can move in the plane.
If is restricted to always be the same distance from as it is horizontally from the vertical line, use coordinate geometry to prove that it must lie on the parabola .
It helps to add the point X on to the diagram, on the line horizontally from P
The question says that PS = PX
The distance PS can be found using Pythagoras' theorem
The distance PX can be found from the diagram
Square PS = PX and substitute in the results above
Expand and simplify both sides
must lie on this curve
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