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The Diffraction Grating (CIE AS Physics)

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The Diffraction Grating Equation

  • A diffraction grating is a plate on which there is a very large number of parallel, identical, close-spaced slits
  • When monochromatic light is incident on a grating, a pattern of narrow bright fringes is produced on a screen

Diffraction grating

Diffraction grating diagram, downloadable AS & A Level Physics revision notes

Diagram of diffraction grating used to obtain a fringe pattern

  

  • The angles at which the maxima of intensity (constructive interference) are produced can be deduced by the diffraction grating equation:

d sin open parentheses theta close parentheses space equals space n lambda

  • Where:
    • d = spacing between adjacent slits (m)
    • θ = angular separation between the order of maxima (degrees)
    • n = order of maxima (n = 0, 1, 2, 3...)
    • λ = wavelength of light source (m)

  • Exam questions sometimes state the lines per m (or per mm, per nm etc.) on the grating which is represented by the symbol N
  • d can be calculated from N using the equation

d space equals fraction numerator space 1 over denominator N end fraction

Angular Separation

  • The angular separation of each maxima is calculated by rearranging the grating equation to make θ the subject
  • The angle θ is taken from the centre meaning the higher orders are at greater angles

Angular separation

Angular separation, downloadable AS & A Level Physics revision notes

Angular separation depends on the order of maxima

 

  • The angular separation between two angles is found by subtracting the smaller angle from the larger one
  • The angular separation between the first and second maxima n1 and n2 is θ2θ1

Orders of Maxima

  • The maximum angle to see orders of maxima is when the beam is at right angles to the diffraction grating
    • This means θ = 90o and sin θ = 1

  • The highest order of maxima visible is therefore calculated by the equation:

n space equals space d over lambda

  • Note that since n must be an integer, if the value is a decimal it must be rounded down
    • E.g If n is calculated as 2.7 then n = 2 is the highest-order visible

Worked example

An experiment was set up to investigate light passing through a diffraction grating with a slit spacing of 1.7 µm. The fringe pattern was observed on a screen. The wavelength of the light is 550 nm.

Worked Example: Diffraction Grating, downloadable AS & A Level Physics revision notes

Calculate the angle α between the two second-order lines.

Answer:

Step 1: List the known quantities

  • Order of maxima, n = 2
  • Diffraction slit spacing, d = 1.7 µm = 1.7 × 10–6 m
  • Wavelength, λ = 550 nm = 550 × 10–9 m

Step 3: Rearrange for θ and substitute in the values

sin open parentheses theta close parentheses space equals space fraction numerator 2 space cross times space open parentheses 550 space cross times space 10 to the power of negative 9 end exponent close parentheses space over denominator 1.7 space cross times space 10 to the power of negative 6 end exponent end fraction space equals space 0.64705

theta space equals space sin to the power of negative 1 end exponent open parentheses 0.64705 close parentheses space equals space 40.54 to the power of degree

Step 4: Calculate α

  • θ is the angle from the centre to the second-order line (β on the diagram)

alpha space equals space 2 theta space equals space 2 cross times 40.5 space equals space 81 degree space

Exam Tip

Take care that the angle θ is the correct angle taken from the centre and not the angle taken between two orders of maxima.

Determining the Wavelength of Light

Method

  • The wavelength of light can be determined by rearranging the grating equation to make the wavelength λ the subject
  • The value of θ, the angle to the specific order of maximum measured from the centre, can be calculated through trigonometry
  • The distance from the grating to the screen is marked as D
  • The distance between the centre and the order of maxima (e.g. n = 2 in the diagram) on the screen is labelled as h - the fringe spacing
  • Measure both these values with a ruler
  • This makes a right-angled triangle where angle θ can be described as the ratio h over D space equals space tan space theta

Order of maxima and wavelength

Wavelength of light setup, downloadable AS & A Level Physics revision notes

The wavelength of light is calculated by the angle to the order of maximum

 

  • Remember to find the inverse of tan to find theta space equals space tan to the power of negative 1 end exponent open parentheses h over D close parentheses
  • This value of θ can then be substituted back into the diffraction grating equation to find the value of the wavelength (with the corresponding order n)

Improving the experiment and reducing uncertainties

  • The fringe spacing can be subjective depending on its intensity on the screen. Take multiple measurements of h (between 3-8) and find the average
  • Use a Vernier scale to record h, in order to reduce percentage uncertainty
  • Reduce the uncertainty in h by measuring across all fringes and dividing by the number of fringes
  • Increase the grating to screen distance D to increase the fringe separation (although this may decrease the intensity of light reaching the screen)
  • Conduct the experiment in a darkened room, so the fringes are clearer
  • Use grating with more lines per mm, so values of h are greater to lower percentage uncertainty

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Ashika

Author: Ashika

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.