Tiny sensors in smartphones could be used to determine the position of the phone on the Earth’s surface by measuring the Earth’s magnetic flux density.
A current and a magnetic field of flux density B are applied to a slice of semiconductor as shown. The slice has thickness t and depth d.
Electrons collect at the top edge of the slice and the bottom edge becomes positively charged. As a result a potential difference known as a Hall voltage VHALL, develops.
Explain why electrons will collect at the top edge of the slice.
Add to the diagram to show clearly two points between which VHALL, develops.
Electrons continue to collect at the top edge of the slice, until the force on a moving electron due to the magnetic field is equal to the force on the electron due to the electric field.
Derive the following equation for VHALL:
where n is the number of charge carriers per unit volume of the semiconductor.
Show that the units are the same on each side of the equation
The table gives the values of n and t for a number of material samples.
material | n / m-3 | t / m |
copper | 8.47 x 1028 | 110 x 10-6 |
germanium | 2.25 x 1019 | 1.10 x 10-6 |
silicon | 1.44 × 1016 | 120 x 10-6 |
Deduce which sample would result in the largest Hall voltage for a particular current and magnetic field.
Two sensors in the smartphone were used to determine the horizontal component BH, and the vertical component BV of the Earth’s magnetic flux density.
Calculate the angle of the Earth’s magnetic field to the horizontal.
BH = 19.0 µT
BV = 49.0 µT
Angle = .....................................
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