Rearranging Formula (Cambridge O Level Maths)

Topic Questions

1
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2 marks

MakeĀ x the subject of this formula.

2 y space equals space 5 x space minus space 7

x space equals ................................................Ā 

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2
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2 marks

Rearrange the formulaĀ 5 w space ā€“ space 3 y space plus space 7 space equals space 0 to make w the subject.

w = ..............................................Ā 

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3
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2 marks

RearrangeĀ 2 left parenthesis w plus h right parenthesis equals P to makeĀ w the subject.
Ā 

w= ....................................................Ā 

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4
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2 marks

MakeĀ p the subject ofĀ 

5 p plus 7 equals m.

p = ...................................................

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1
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2 marks

y space equals space square root of u squared space x end root

Rearrange the formula to writeĀ x in terms ofĀ u and y.

xĀ = ..............................................

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2
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3 marks

Make xĀ the subject of the formula.

x equals fraction numerator 3 plus x over denominator y end fraction


x equals .................................................

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3
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3 marks

MakeĀ p the subject ofĀ 

y squared minus 2 p squared equals h.

Ā 

p = ...................................................Ā 

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4
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3 marks

s equals u t plus 1 half a t squared

Rearrange the formula to write a in terms of u, t and s.
Ā 

a = Ā ...................................................Ā 

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5
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3 marks

MakeĀ P the subject of the formulaĀ Ā A equals P plus fraction numerator P R T over denominator 100 end fraction.
Ā 

P = ...............................................

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6
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3 marks

m equals square root of fraction numerator k cubed plus 1 over denominator 4 end fraction end root

Make kĀ  the subject of the formula.

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1
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3 marks

RearrangeĀ  2 open parentheses 4 x minus y close parentheses equals 5 x minus 3Ā  to make y the subject.

Ā 

y = ...................................................Ā 

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2
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2 marks

MakeĀ t the subject of the formulaĀ space s equals k minus t squared.
Ā 

t equals................................................Ā 

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3
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3 marks

Make y the subject of the formulaĀ Ā p equals square root of fraction numerator x plus y over denominator 5 end fraction end root

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4
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3 marks

Make tĀ the subject of the formulaĀ Ā 2 open parentheses d minus t close parentheses equals 4 t plus 7

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5
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3 marks

Make m the subject of the formulaĀ Ā v equals square root of fraction numerator 2 E over denominator m end fraction end root

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1
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3 marks

The equationĀ  x squared over 2 plus 1 over x squared minus 2 over x equals 3 x plus 1Ā  can be written asĀ Ā x to the power of 4 plus a x cubed plus b x squared plus c x plus 2 equals 0.

Find the values ofĀ a,Ā b andĀ c.

Ā 

a = ...................................................Ā Ā 


b = ...................................................Ā 


c = ...................................................Ā 

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2
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3 marks

The equationĀ  x cubed over 3 minus fraction numerator 1 over denominator 2 x squared end fraction plus 4 equals 0Ā  can be written in the formĀ a x to the power of n plus b x to the power of n minus 3 end exponent minus 3 equals 0.
Find the value of a, the value ofĀ b and the value of n.

Ā 

a equals...............................................Ā 

Ā  Ā 
b equals...............................................Ā 

Ā  Ā 
n equals...............................................

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3
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4 marks

Rearrange the formula to make x the subject.

k equals fraction numerator 2 m minus x over denominator x end fraction

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4
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4 marks

Make yĀ the subject of the formula

t equals fraction numerator 2 minus 3 y over denominator y plus 2 end fraction

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5
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4 marks

Make m the subject of

m over v minus t over b equals fraction numerator m minus t over denominator R end fraction

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