1
1 mark
1 markThe atomic structure of an unknown element is shown below.
What is the atomic number and mass number for the unknown element?
| Atomic Number | Mass Number | |||
| ☐ | A | 6 | 11 | |
| ☐ | B | 5 | 11 | |
| ☐ | C | 5 | 6 | |
| ☐ | D | 6 | 10 |
Did this page help you?
1.1 Atomic Structure
2a3 marks
Atoms contain electrons, neutrons and protons.
i)
Draw one line to link each particle to its correct relative charge.
(2)
ii)
Which of the following is the relative mass of a proton?
(1)
| ☐ | A | 0 | |
| ☐ | B |  |
|
| ☐ | C | 1 | |
| ☐ | D | -1 |
2b1 mark
Argon is in group 0 of the periodic table.
Identify, using the periodic table on the back cover of this paper, which of these elements is in the same period as argon.
| ☐ | A | bromine | |
| ☐ | B | iron | |
| ☐ | C | magnesium | |
| ☐ | D | xenon |
2c3 marks
Figure 4 shows the atomic number and mass number of two isotopes of argon.
| isotope | atomic number | mass number |
| argon-38 | 18 | 38 |
| argon-40 | 18 | 40 |
Figure 4
Describe the structure of an atom of argon-38 and of an atom of argon-40.
Did this page help you?
31 mark
As the atomic model developed, protons, neutrons and electrons were discovered.
What was the correct order of discovery?
| First | Second | Third | |||
| ☐ | A | Proton | Neutron | Electron | |
| ☐ | B | Proton | Electron | Neutron | |
| ☐ | C | Electron | Proton | Neutron | |
| ☐ | D | Electron | Neutron | Proton |
Did this page help you?
4a3 marks
Chlorine has an atomic number of 17.
Figure 3 shows the arrangement of electrons in an atom of chlorine.
Figure 3
i)
What is the electronic configuration of this atom?
(1)
| ☐ | A | 10.7 | |
| ☐ | B | 17 | |
| ☐ | C | 2.8.7 | |
| ☐ | D | 7.8.2 |
ii)
Explain, using Figure 3, why chlorine belongs to group 7 of the periodic table.
(2)
4b5 marks
5 marksThe nucleus of an atom is made up of protons and neutrons.
Atoms of chlorine contain 17 protons.
Figure 4 shows some information about a proton, a neutron and an electron.
| relative mass | relative charge | |
| proton | 1 | +1 |
| neutron | 1 | 0 |
| electron | very small | -1 |
Figure 4
i)
Explain, using the information in Figure 3 and Figure 4, why atoms of chlorine have no overall charge.
(2)
ii)
Atoms of chlorine-37 have a mass number of 37.
Calculate the number of neutrons in atoms of chlorine-37.
(1)
number of neutrons = .................................................
iii)
There are two isotopes of chlorine, chlorine-35 and chlorine-37.
Explain the meaning of the term isotopes.
(2)
Did this page help you?
51 mark
Chlorine–35 and chlorine–37 are isotopes.
Which statement describes an isotope?
| ☐ | A | Atoms with the same number of protons and different numbers of electrons | |
| ☐ | B | Atoms with the same number of neutrons and different numbers of electrons | |
| ☐ | C | Atoms with the same number of protons and different numbers of neutrons | |
| ☐ | D | Atoms with the same number of neutrons and different numbers of protons |
Did this page help you?
6a3 marks
3 marksHigher Tier Only
Titanium and iron are examples of transition metals.
Figure 6 shows the percentage abundance of each isotope in a sample of titanium.
Figure 6
Calculate the relative atomic mass of titanium in this sample.
relative atomic mass = ......................................
6b4 marks
Iron, when heated in air, reacts with oxygen to form iron oxide.
i)
This reaction is an example of
(1)
| ☐ | A | crystallisation | |
| ☐ | B | distillation | |
| ☐ | C | neutralisation | |
| ☐ | D | oxidation |
ii)
The equipment shown in Figure 7 can be used to find the mass of oxygen that combines with iron.
Figure 7
Describe how the equipment shown in Figure 7 could be used to find the mass of oxygen that combines with 0.500 g of iron wool in a crucible and lid of known mass.
(3)
6c4 marks
4 marks2.24 g of iron combines with 0.96 g of oxygen to form an oxide of iron.
Determine the formula of this oxide of iron and use it to complete the balanced equation.
(relative atomic masses: Fe = 56.0, O = 16.0)
You must show your working.
balanced equation for the reaction is
................ Fe + ................O2 → ................................................
Did this page help you?