Practice Paper 1 (DP IB Maths: AA HL)

Practice Paper Questions

1a
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2 marks

The following diagram shows the graph of y space equals space f space left parenthesis x right parenthesis comma space long dash 3 space less or equal than x space less or equal than space 6.

q1-practice-paper-setb-ib-dp-aa-hl

Write down the value of

i)
 f left parenthesis negative 2 right parenthesis
ii)
 f to the power of negative 1 end exponent left parenthesis 1 right parenthesis.
1b
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1 mark

Find the value of left parenthesis f space ring operator space f right parenthesis space left parenthesis 0 right parenthesis.

1c
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2 marks

Given that straight g left parenthesis x right parenthesis space equals space f space left parenthesis x space plus space 5 right parenthesis space minus 5, find the domain and range of g.

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2a
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3 marks

Students are arranged for a graduation photograph in rows which follows an arithmetic sequence. There are 20 students in the fourth row and 44 in the 10th row.

i)
Find the common difference, d, of the arithmetic sequence.

ii)
Find the first term of the arithmetic sequence.
2b
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3 marks

Given there are 20 rows of students in the photograph, calculate how many students there are altogether

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3a
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4 marks

The heights, in metres, of a flock of 20 flamingos are recorded and shown below:

0.4 0.9 1.0 1.0

1.2

1.2 1.2 1.2 1.2 1.2
1.3 1.3 1.3 1.4 1.4 1.4 1.4 1.5 1.5 1.6

An outlier is an observation that falls either more than 1.5 x (interquartile range) above the upper quartile or less than 1.5 x (interquartile range) below the lower quartile.

i)
Find the values of straight Q 1 comma space straight Q 2 and straight Q 3.

ii)
Find the interquartile range.

iii)
Identify any outliers.
3b
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3 marks

Using your answers to part (a), draw a box plot for the data.

q3b-practice-paper-setb-ib-dp-aa-hl

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4
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6 marks

Let f open parentheses x close parentheses space equals fraction numerator space g open parentheses x close parentheses over denominator h open parentheses x close parentheses end fraction,where g open parentheses 2 close parentheses equals 4, h open parentheses 2 space close parentheses equals negative 1, g apostrophe open parentheses 2 close parentheses equals 0 and h apostrophe open parentheses 2 close parentheses equals 2.

Find the equation of the tangent of fat x equals 2.

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5a
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3 marks

Prove that square root of 3 space sin space 2 theta space plus space cos space 2 theta space minus 1 space equals space 2 space sin space theta open parentheses square root of 3 space cos space theta minus space sin theta close parentheses

5b
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5 marks

Hence solve square root of 3 space end root sin space 2 theta space plus space cos space 2 theta space plus space 3 space cos theta space long dash space square root of 3 space end root sin space theta space equals space 1 comma space w h e r e space 0 less or equal than theta less or equal than 360 degree

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6
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6 marks

It is given that  sec theta equals 7 over 3,  where  pi less than theta less than 2 pi

Find the exact value of cosec theta.

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7
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6 marks

alpha and beta are non-real solutions of the equation 2 x squared minus open parentheses 2 k minus 3 close parentheses x plus 2 k equals 0
Given that  alpha squared plus beta squared equals 9 over 4
 and k not equal to 0,  find the value of k.

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8a
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2 marks

Consider the following limit: 

limit as x rightwards arrow 0 of space fraction numerator negative 1 plus cos space 2 x over denominator x squared end fraction 

Explain why it is appropriate to use l’Hôpital’s rule to attempt to evaluate this limit.

8b
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2 marks

Show that employing l’Hôpital’s rule once leads to an indeterminate form when you attempt to evaluate the limit.

8c
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2 marks

By employing l’Hôpital’s rule a second time, show that the limit exists and find its value.

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9a
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2 marks

Frank plays a game involving a biased six-sided die.
The faces of the die are numbered 1 to 6.
The score of the game, X, is the number which lands face up after the die is rolled.
The following table shows the probability distribution for X.

bold italic S bold italic c bold italic o bold italic r bold italic e bold comma bold space bold italic x 1 2 3 4 5 6
bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 1 over 6 1 half p 1 over 8 3 over 2 p 1 over 12 3 p

Calculate the exact value of p.

9b
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3 marks

Frank plays the game once.

Calculate the expected score.

9c
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3 marks

Frank plays the game twice and adds the scores together.

Find the probability Frank has a total score of 4, giving your answer as a fraction.

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10a
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2 marks

Frank has a biased six-sided die.
The faces of the die are numbered 1 to 6.
Frank's score, X, is the number which lands face up after his die is rolled.
The following table shows the probability distribution for X.

bold italic S bold italic c bold italic o bold italic r bold italic e bold comma bold space bold italic x 1 2 3 4 5 6
bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 1 over 10 1 half p 1 fifth 3 over 2 p 1 fifth 3 p

Calculate the exact value of p.

10b
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3 marks

Frank plays the game once.

Calculate the expected score.

10c
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3 marks

Frank plays the game twice and adds the scores together.

Find the probability Frank has a total score of 4, giving your answer as a fraction.

10d
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4 marks

Jenny has a different biased six-sided die.
On Jenny's die, the faces are numbered as multiples of 3.
Jenny's score, Y, is the number which lands face up after her die is rolled.
The following table shows the probability distribution for Y.

bold italic S bold italic c bold italic o bold italic r bold italic e bold comma bold space bold italic y 3 6 9 12 15 18
bold italic P bold left parenthesis bold italic Y bold equals bold italic y bold right parenthesis a a b b b b


It is given that the range of possible values for a is 0 space less than space a space less than space 1 half space.

i)
Find the range of possible values for b.
ii)
Hence, find the range of possible values for E left parenthesis Y right parenthesis.
10e
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6 marks

Frank and Jenny each roll their die once. The probability that Frank's score is at least as high as Jenny's is 23 over 80.

Find the value of E left parenthesis Y right parenthesis.

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11a
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3 marks

The points A(2, 3, 0), B(-2, 4, 1), C(1, -1, 3) and D(5, -2, 2) lie on the plane capital pi subscript 1 and form a parallelogram, where AB and CD are one pair of parallel edges and BC and AD are the other pair of parallel edges.  Each unit on the coordinate grid is equivalent to 1 cm in length.

Find the vector product of AB with rightwards arrow on top and AC with rightwards arrow on top.

11b
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2 marks

Hence, or otherwise, find the Cartesian equation of the plane capital pi subscript 1.

11c
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4 marks

A second plane capital pi subscript 2 contains the point with position vector open parentheses table row 5 row cell negative 3 end cell row 5 end table close parentheses and also the line L, which has vector equation space r equals open parentheses table row 6 row 1 row 2 end table close parentheses space plus lambda open parentheses table row 4 row cell negative 1 end cell row cell negative 1 end cell end table close parentheses.

Show that capital pi subscript 1 and capital pi subscript 2are parallel.

11d
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3 marks

A parallelepiped is a 3D object made up of six faces that are parallelograms lying in pairs of parallel planes.  EFGH is a parallelogram on capital pi subscript 2 that is congruent to ABCD, and points A, B, C and D on capital pi subscript 1 are joined to points E, F, G and H respectively on capital pi subscript 2 to form a parallelepiped.

Given that the coordinates of E are (3, 6, 0), find the coordinates of point H.

11e
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5 marks

The volume of a parallelepiped can be found using the formula open vertical bar open parentheses bold italic a cross times bold italic b close parentheses. bold italic c close vertical bar where bold italic a comma space bold italic b and bold italic c  are vectors corresponding to three edges meeting at a single vertex of the parallelepiped.

Show that the volume of the parallelepiped ABCDEFGH is 40 cm3

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12a
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3 marks

A mathematical function f is defined by f open parentheses x close parentheses equals x e to the power of 2 x end exponent.

Show that f apostrophe apostrophe open parentheses x close parentheses equals open parentheses 4 x plus 4 close parentheses e to the power of 2 x end exponent.

12b
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7 marks

Prove by mathematical induction that if f open parentheses x close parentheses equals x e to the power of 2 x end exponent, then f to the power of open parentheses n close parentheses end exponent open parentheses x close parentheses equals open parentheses 2 to the power of n x plus n 2 to the power of n minus 1 end exponent close parentheses e to the power of 2 x end exponent.

12c
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7 marks

Let  g open parentheses x close parentheses equals ln open parentheses 1 plus m x close parentheses comma space m element of Z to the power of plus. 

Consider the function h defined by h open parentheses x close parentheses equals f open parentheses x close parentheses cross times g open parentheses x close parentheses.

Given that the term in x to the power of 4 of the Maclaurin series for h open parentheses x close parentheses has coefficient 6, find the value of m.

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