Practice Paper 1 (DP IB Maths: AA HL)

Practice Paper Questions

1a
Sme Calculator
2 marks
(i)
Expand open parentheses 2 k minus 1 close parentheses cubed

(ii)
Hence, or otherwise, show that open parentheses 2 k minus 1 close parentheses cubed minus open parentheses 2 k minus 1 close parentheses equals 8 k cubed minus 12 k squared plus 4 k
1b
Sme Calculator
3 marks

Thus prove, given  k greater than 1, k element of straight natural numbers,  that the difference between an odd natural number greater than 1 and its cube is always even.

Did this page help you?

2
Sme Calculator
5 marks
Let  Aand B be events such that P open parentheses A close parentheses equals 0.3 comma space P open parentheses B close parentheses equals 0.75 and P open parentheses A union B close parentheses equals 0.9

Find P open parentheses B vertical line A close parentheses.

Did this page help you?

3a2 marks

The functions f and g are defined such that f open parentheses x close parentheses equals 6 x plus 7 and  g open parentheses x close parentheses equals fraction numerator x minus 5 over denominator 3 end fraction.

Show that open parentheses f ring operator g close parentheses open parentheses x close parentheses equals 2 x minus 3.            

3b
Sme Calculator
3 marks

Given that open parentheses f ring operator g close parentheses to the power of negative 1 end exponent open parentheses a close parentheses equals 6, find the value of a.                                           

Did this page help you?

4
Sme Calculator
5 marks

The following diagram shows the graph of y equals f open parentheses x close parentheses. The graph has a horizontal asymptote at y equals negative 2 .  The graph crosses the x-axis at x equals negative 1  and x equals 1,  and the y-axis at y equals 1.

4-2-sme-ib-hl-aa-paper-1-section-a-model-answers

On the following set of axes, sketch the graph of y equals open square brackets f open parentheses x close parentheses close square brackets squared minus 2, clearly showing any asymptotes with their equations along with the coordinates of any local maxima or minima.

 q4-1-sme-ib-hl-aa-paper-1-section-a-model-answers

Did this page help you?

5
Sme Calculator
5 marks

Given that fraction numerator d y over denominator d x end fraction equals 3 x squared cos open parentheses 3 x cubed plus straight pi over 2 close parentheses and that the graph of y passes through the point open parentheses 0 comma negative 1 close parentheses, find an expression for y in terms of x.

Did this page help you?

6
Sme Calculator
7 marks

The plane space capital pi spacehas the Cartesian equation 5 x minus y minus z equals 15.

The line L has the vector equation r equals open parentheses table row cell negative 4 end cell row 2 row cell negative 1 end cell end table close parentheses plus lambda open parentheses table row k row cell negative 2 end cell row 2 end table close parentheses comma space lambda comma k element of straight real numbers .  The acute angle between the line L and the plane space capital pi space is 60 degree

Find the possible values of k.        

 

Did this page help you?

7a
Sme Calculator
3 marks

Show that log subscript 4 open parentheses cos space 2 x plus 13 close parentheses equals log subscript 2 square root of cos space 2 x plus 13 end root

7b
Sme Calculator
5 marks

Hence or otherwise  log subscript 2 open parentheses 3 square root of 2 cos space x close parentheses equals log subscript 4 open parentheses cos space 2 x plus 13 close parentheses for negative straight pi over 2 less than x less than straight pi over 2

Did this page help you?

8a
Sme Calculator
3 marks

The function f is defined by f open parentheses x close parentheses equals straight e to the power of 2 x end exponent minus 4 straight e to the power of x plus 1 comma space x element of straight real numbers comma space x less or equal than a. The graph of y equals f open parentheses x close parentheses is shown in the following diagram.

q8a-sme-ib-hl-aa-paper-1-section-a-model-answers

Find the largest value of a such that f has an inverse function.

8b
Sme Calculator
5 marks

For this value of a, find an expression for f to the power of negative 1 end exponent open parentheses x close parentheses, stating its domain.

Did this page help you?

9
Sme Calculator
7 marks

A continuous random variable X has the probability density function f given by

f open parentheses x close parentheses equals open curly brackets table row cell πx over 81 sin open parentheses πx over 9 close parentheses comma end cell cell space space space space space space space space 0 less or equal than x less or equal than 9 end cell row cell space space space space space space space space space space space space space space space space space space 0 comma end cell cell space space space space space space space space otherwise end cell end table close 

Find P open parentheses 3 less or equal than X less or equal than 6 close parentheses.   

Did this page help you?

10a
Sme Calculator
5 marks

Express negative 2 minus 2 square root of 3 straight i  in the form  r e to the power of straight i theta end exponent, where r greater than 0 and negative pi less than theta less or equal than pi.

10b
Sme Calculator
5 marks

Let the roots of the equation z cubed equals negative 2 minus 2 square root of 3 straight i be u comma space v and w.

Find u comma space v and w expressing your answers in the form r e to the power of straight i theta end exponent, where r greater than 0 and negative pi less than theta less or equal than pi.                 

10c
Sme Calculator
4 marks

On an Argand diagram u comma v and w are represented by the points straight U comma space straight V and straight W respectively.

Find the area of triangle UVW.

10d
Sme Calculator
4 marks

By considering the sum of the roots u comma v and w, show that

cos open parentheses fraction numerator 2 straight pi over denominator 9 end fraction close parentheses plus cos open parentheses fraction numerator 4 straight pi over denominator 9 end fraction close parentheses plus cos open parentheses fraction numerator 8 straight pi over denominator 9 end fraction close parentheses equals 0

Did this page help you?

11a
Sme Calculator
8 marks

The function f is defined by  f open parentheses x close parentheses equals 2 straight e to the power of sin 2 x end exponent.

Find the first two derivatives of f open parentheses x close parentheses and hence find the Maclaurin series for f open parentheses x close parentheses up to and including the x squared term.

11b
Sme Calculator
4 marks

Show that the coefficient of x cubed in the Maclaurin series for f open parentheses x close parentheses is zero.

11c
Sme Calculator
6 marks

Using the Maclaurin series for arctan space xand straight e to the power of x minus 1, find the Maclaurin series for arctan open parentheses straight e to the power of italic 2 x end exponent minus 1 close parentheses up to and including the x cubed term.

11d
Sme Calculator
3 marks

Hence, or otherwise, find  limit as x rightwards arrow 0 of fraction numerator f open parentheses x close parentheses minus 2 over denominator arctan open parentheses straight e to the power of 2 x end exponent minus 1 close parentheses end fraction

Did this page help you?

12a
Sme Calculator
3 marks

Let f open parentheses x close parentheses equals fraction numerator ln p x over denominator q x end fraction where x greater than 0 comma space space p comma space q element of straight real numbers to the power of plus.

Show that  f apostrophe open parentheses x close parentheses equals fraction numerator 1 minus ln p x over denominator q x squared end fraction . 

12b
Sme Calculator
3 marks

The graph of f has exactly one maximum point A.

Find the x-coordinate of A.         

12c
Sme Calculator
3 marks

The second derivative of f is given by f " open parentheses x close parentheses equals fraction numerator 2 ln p x minus 3 over denominator q x cubed end fraction.  The graph of f has exactly one point of inflexion B.

Show that the x-coordinate of B is straight e to the power of 3 over 2 end exponent over p

12d
Sme Calculator
7 marks

The region R is enclosed by the graph of  f, the x-axis, and the vertical lines through the maximum point A and the point of inflexion B.

q12b-sme-ib-hl-aa-paper-1-section-a-model-answers

Calculate the area of R in terms of q and show that the value of the area is independent of p.

Did this page help you?