Syllabus Edition

First teaching 2023

First exams 2025

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Electric Potential (CIE A Level Physics)

Revision Note

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Ann H

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Ann H

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Physics

Electric Potential

  • To move a positive charge closer to another positive charge, work must be done to overcome the force of repulsion between them
  • Energy is therefore transferred to the charge that is being pushed upon
    • This means its potential energy increases

  • If the positive charge is free to move, it will start to move away from the repelling charge
    • As a result, its potential energy decreases back to 0

  • This is analogous to the gravitational potential energy of a mass increasing as it is being lifted upwards and decreasing as it falls
  • The electric potential at a point is defined as:

The work done per unit positive charge in bringing a small test charge from infinity to a defined point

  • Electric potential is a scalar quantity
    • This means it doesn’t have a direction

  • However, you will still see the electric potential with a positive or negative sign. This is because the electric potential is:
    • Positive when near an isolated positive charge
    • Negative when near an isolated negative charges
    • Zero at infinity

  • Positive work is done by the mass from infinity to a point around a positive charge and negative work is done around a negative charge. This means:
    • When a positive test charge moves closer to a negative charge, its electric potential decreases
    • When a positive test charge moves closer to a positive charge, its electric potential increases

    Work Done to Bring Like Charges Together

Electric Potential around Positive & Negative Charges 1, downloadable AS & A Level Physics revision notes

The electric potential V decreases in the direction of repulsion of the test charge and increases when moving towards each other

 

 Work Done to Separate Opposite Charges

Electric Potential around Positive & Negative Charges 2, downloadable AS & A Level Physics revision notes

The electric potential V decreases in the direction the test charge would naturally move in due to attraction and increases when the positive test charge moves away from the negative charge

 

  • To find the potential at a point caused by multiple charges, add up each potential separately

Potential Gradient

  • The electric potential in the field due to a point charge is defined as:

V space equals space fraction numerator Q over denominator 4 straight pi straight epsilon subscript 0 space r end fraction

  • Where:
    • V = the electric potential (V)
    • Q = the point charge producing the potential (C)
    • ε0 = permittivity of free space (F m-1)
    • r = distance from the centre of the point charge (m)

  • This equation shows that for a positive (+) charge:
    • As the distance from the charge, r  decreases, the potential increases
    • This is because more work has to be done on a positive test charge to overcome the repulsive force to bring them together

  • For a negative (−) charge:
    • As the distance from the charge, r  decreases, the potential V  decreases
    • This is because less work has to be done on a positive test charge since the attractive force will make it easier to bring them together

  • Unlike the gravitational potential equation, the minus sign in the electric potential equation will be included in the charge
  • The electric potential changes according to an inverse square law with distance

The Potential Around a Charged Sphere

Potential around charged sphere, downloadable AS & A Level Physics revision notes

The potential changes as an inverse law with distance near a charged sphere

Worked example

A Van de Graaf generator has a spherical dome of radius 15 cm. It is charged up to a potential of 240 kV.

Calculate

(a) How much charge is stored on the dome

(b) The potential at a distance of 30 cm from the dome

 

Answer:

 

Part (a)

Step 1: Write down the known quantities

  • Radius of the dome, r = 15 cm = 15 × 10-2 m
  • Potential difference, V = 240 kV = 240 × 103 V

Step 2: Write down the equation for the electric potential due to a point charge

V space equals space fraction numerator Q over denominator 4 straight pi straight epsilon subscript 0 r end fraction

Step 3: Rearrange for charge Q

Q space equals space V 4 straight pi straight epsilon subscript 0 r

Step 4: Substitute in values

Q = (240 × 103) × (4π × 8.85 × 10-12) × (15 × 10-2) = 4.0 × 10-6 C = 4.0 μC

 

Part (b)

Step 1: Write down the known quantities

  • Q = charge stored in the dome = 4.0 μC = 4.0 × 10-6 C
  • r = radius of the dome + distance from the dome = 15 + 30 = 45 cm = 45 × 10-2 m

Step 2: Write down the equation for electric potential due to a point charge

V space equals space fraction numerator Q over denominator 4 straight pi straight epsilon subscript 0 r end fraction

Step 3: Substitute in values

 

V space equals space fraction numerator stretchy left parenthesis 4.0 space cross times space 10 to the power of negative 6 end exponent stretchy right parenthesis over denominator stretchy left parenthesis 4 straight pi space cross times space 8.85 space cross times space 10 to the power of negative 12 end exponent stretchy right parenthesis space cross times space stretchy left parenthesis 45 space cross times space 10 to the power of negative 2 end exponent stretchy right parenthesis end fraction space equals space 79.93 space cross times space 10 cubed space equals space 80 space kV space stretchy left parenthesis 2 space straight s. straight f. stretchy right parenthesis

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Ann H

Author: Ann H

Ann obtained her Maths and Physics degree from the University of Bath before completing her PGCE in Science and Maths teaching. She spent ten years teaching Maths and Physics to wonderful students from all around the world whilst living in China, Ethiopia and Nepal. Now based in beautiful Devon she is thrilled to be creating awesome Physics resources to make Physics more accessible and understandable for all students no matter their schooling or background.