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First teaching 2021

Last exams 2024

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Solving Trig Equations (CIE IGCSE Maths: Extended)

Revision Note

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Daniel I

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Daniel I

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Maths

Solving Trig Equations

You can use the symmetry of trig graphs to find multiple solutions to a trig equation

How are trigonometric equations of the form sin x = k solved?

  • The solutions to the equation sin x = 0.5 in the range 0° < x < 360° are x = 30° and x = 150°
    • If you like, check on a calculator that both sin(30) and sin(150) give 0.5
  • The first solution comes from your calculator (by taking inverse sin of both sides)
    • x = sin-1(0.5) = 30°
  • The second solution comes from the symmetry of the graph y = sin x between 0° and 360°
    • Sketch the graph
    • Draw a vertical line from x = 30° to the curve, then horizontally across to another point on the curve, then vertically back to the x-axis again
    • By the symmetry of the curve, the new value of x is 180° - 30° = 150°
  • In general, if x° is an acute angle that solves sin x = k, then 180° - x° is the obtuse angle that solves the same equation
  • If the calculator gives x as a negative value, continue drawing the curve to the left of the x-axis to help

cie-igcse-3-12-2-solving-trig-equations-1

How are trigonometric equations of the form cos x = k solved?

  • The solutions to the equation cos x = 0.5 in the range 0° < x < 360° are x = 60° and x = 300°
    • If you like, check on a calculator that both cos(60) and cos(300) give 0.5
  • The first solution comes from your calculator (by taking inverse cos of both sides)
    • x = cos-1(0.5) = 60°
  • The second solution comes from the symmetry of the graph y = cos x between 0° and 360°
    • Sketch the graph
    • Draw a vertical line from x = 60° to the curve, then horizontally across to another point on the curve, then vertically back to the x-axis again
    • By the symmetry of the curve, the new value of x is 360° - 60° = 300°
  • In general, if x° is an angle that solves cos x = k, then 360° - x° is another angle that solves the same equation
  • If the calculator gives x as a negative value, continue drawing the curve to the left of the x-axis to help

cie-igcse-3-12-2-solving-trig-equations-2

How are trigonometric equations of the form tan x = k solved?

  • The solutions to the equation tan x = 1 in the range 0° < x < 360° are x = 45° and x = 225°
    • Check on a calculator that both tan(45) and tan(225) give 1
  • The first solution comes from your calculator (by taking inverse tan of both sides)
    • x = tan-1(1) = 45°
  • The second solution comes from the symmetry of the graph y = tan x between 0° and 360°
    • Sketch the graph
    • Draw a vertical line from x = 45° to the curve, then horizontally across to another point on the curve (a different “branch” of tan x), then vertically back to the x-axis again
    • The new value of x is 45° + 180° = 225° as the next “branch” of tan x is shifted 180° to the right
  • In general, if x° is an angle that solves tan x = k, then x° + 180° is another angle that solve the same equation
  • If the calculator gives x as a negative value, continue drawing the curve to the left of the x-axis to help

cie-igcse-3-12-2-solving-trig-equations-3

Exam Tip

  • Use a calculator to check your solutions by substituting them into the original equation
  • For example, 60° and 330° are incorrect solutions of cos x = 0.5, as cos(330) on a calculator is not equal to 0.5

Worked example

Solve sin x = 0.25 in the range 0° < x < 360°, giving your answers correct to 1 decimal place

Use a calculator to find the first solution (by taking inverse sin of both sides)

x = sin-1(0.25) = 14.4775… = 14.48° to 2 dp

Sketch the graph of y = sin x and mark on (roughly) where x = 14.48 and y = 0.25 would be
Draw a vertical line up to the curve, then horizontally across to the next point on the curve, then vertically back down to the x-axis

cie-igcse-3-12-2-solving-trig-equations-4

Find this value using the symmetry of the curve (by taking 14.48 away from 180)

180° – 14.48° = 165.52°

Give both answers correct to 1 decimal place

x = 14.5° or x = 165.5°

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Daniel I

Author: Daniel I

Daniel has taught maths for over 10 years in a variety of settings, covering GCSE, IGCSE, A-level and IB. The more he taught maths, the more he appreciated its beauty. He loves breaking tricky topics down into a way they can be easily understood by students, and creating resources that help to do this.