Fig. 6.1 shows a single photomultiplier tube and its internal components. The tube can detect gamma photons in high-energy physics experiments.
A single gamma photon incident on the scintillator crystal generates many photons of blue light. These visible light photons travel to the photocathode where they are converted into photoelectrons. The number of electrons is then multiplied in the photomultiplier tube with the help of electrodes called dynodes. A short pulse of electric current is produced at the output end of the photomultiplier tube.
Fig. 6.1
Fig. 6.2
C = .......................................° [2]
[2]
Show that the energy of a single photon of wavelength 450 nm is less than 3 eV.
[3]
[1]
The pulse of electrons at the anode lasts for a time of 2.5 × 10−9 s.
Calculate the average current due to this pulse.
average current = .................................... A [3]
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