Practice Paper 3 (Pure 3) (CIE A Level Maths: Pure 1)

Practice Paper Questions

1
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3 marks

Solve the equation space open vertical bar x squared space long dash space 4 close vertical bar space equals space 3, giving your answers in exact form.

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2a
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4 marks

Show that 2 space sin space theta plus space 4 space cos space theta can be written as 2 square root of 5 space end root cos left parenthesis theta space long dash space alpha right parenthesis comma where alpha space equals space 0.464 to three significant figures.

2b
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3 marks

Hence solve the equation

2 space sin space theta space plus space 4 space cos space theta space equals space 3 space space space space space space space space minus straight pi space less or equal than straight theta less or equal than straight pi space space space space space

giving your answers correct to 3 significant figures.

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3
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4 marks

Differentiate fraction numerator 5 x to the power of 7 over denominator sin space 2 x end fractionwith respect to x

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4
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5 marks

Use calculus and the substitution space x space equals space cos space theta to find the exact value of

      integral subscript fraction numerator 1 over denominator square root of 2 end fraction end subscript superscript fraction numerator square root of 3 over denominator 2 end fraction end superscript space fraction numerator 1 over denominator square root of 1 minus x squared end root end fraction space straight d x

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5
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5 marks

Solve the equation

      8 space cos to the power of 4 space theta space minus space 5 space cos space 2 theta space minus 2 space equals 0 space space space space space space space space space 0 less or equal than theta less or equal than straight pi

tate your answers as multiples of straight pi.

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6a
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2 marks

The functions straight f left parenthesis x right parenthesis and straight g left parenthesis x right parenthesis are given as follows

   straight f left parenthesis x right parenthesis space equals space open parentheses 4 space plus space 3 x close parentheses to the power of 1 half end exponent space space space space space space space space space space space space space space space space space space space space space space space space space straight g left parenthesis x right parenthesis space equals space left parenthesis 9 space long dash space 2 x right parenthesis to the power of negative 1 half end exponent

Expand straight f left parenthesis x right parenthesis, in ascending powers of x up to and including the term in x squared.

6b
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2 marks

Expand straight g left parenthesis x right parenthesis, in ascending powers of x up to and including the term in x squared.

6c
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2 marks

Find the expansion of square root of fraction numerator 4 plus 3 x over denominator 9 minus 2 x end fraction end root in ascending powers of x, up to and including the term in x squared .

6d
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2 marks

Find the values of x for which your expansion in part (c) is valid.

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7a
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7 marks

A tree disease is spreading throughout a large forested area.

When the disease was first discovered, three trees were infected.

Ten days later ten trees were infected.

The differential equation

1 over t space fraction numerator d N over denominator d t end fraction equals k N

where k is a positive constant, is used to model the number of infected trees, N, at a time t days after the disease was first discovered.

Find the particular solution to the differential equation.

7b
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4 marks

Scientists believe the majority of the forest can be saved from infection if action is taken before 30 trees are infected.

Measured from the time when the disease was first discovered, how many days does the model predict the scientists have to take action in order to save the majority of the forest from infection?

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8
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5 marks

Use integration by parts to find

integral open parentheses 2 x squared space minus space 1 close parentheses e to the power of x space straight d x

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9a
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2 marks

Show that the equation x cubed space plus space 3 space equals space 5 x  can be rewritten as

      x space equals space cube root of 5 x space minus 3 end root

9b
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3 marks

Starting with x subscript 0 space equals space 1.8 comma use the iterative formula

      x subscript n plus 1 end subscript space equals space cube root of 5 x subscript n minus 3 end root

to find a root of the equation x cubed space plus space 3 space equals space 5 x, correct to two decimal places.

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10
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5 marks

Determine whether the following pairs of lines intersect, are parallel, or are skew.

If the lines intersect, find the coordinates of the point of intersection.

bold r space equals space long dash 7 bold i space long dash space bold j space plus space 6 bold k plus space s open parentheses bold i plus bold j minus bold k close parentheses space and straight r space equals space 2 bold i bold space plus space 2 bold j space plus space 11 bold k bold space plus space t left parenthesis 2 bold i space long dash bold j bold space plus 5 bold k right parenthesis.

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11
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5 marks

Find the perpendicular distance of the point P left parenthesis 6 comma space 0 comma space 3 right parenthesis to the line

bold r space equals space long dash bold i space plus space 5 bold j bold space plus space 2 bold k plus s space left parenthesis 3 bold i space minus 6 bold j bold space long dash space 2 bold k right parenthesis

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12a
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4 marks

f left parenthesis z right parenthesis equals z to the power of 4 minus 2 z cubed plus 6 z squared plus p z plus 125, where p is a real constant.

Given that 3 minus 4 i is a root of the equation f left parenthesis z right parenthesis equals 0 , show that z squared plus 4 z plus 5 is a factor of f left parenthesis z right parenthesis.

12b
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3 marks

Hence find the value of p and solve completely the equation  f left parenthesis z right parenthesis equals 0.

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13
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5 marks

On an Argand diagram, shade the region which satisfies both of the following inequalities:

vertical line z minus 4 i vertical line greater than vertical line z vertical line space space space space space and space space space space vertical line z minus 4 i vertical line less than vertical line z plus 2 vertical line

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