Work, Energy & Power (Edexcel A Level Further Maths: Further Mechanics 1)

Topic Questions

1a
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5 marks

A parcel of mass 5 kg is projected with speed 8 ms−1 up a line of greatest slope of a fixed rough inclined ramp.

The ramp is inclined at angle alpha to the horizontal, where sin alpha   equals space 1 over 7.

The parcel is projected from the point A on the ramp and comes to instantaneous rest at the point B on the ramp, where AB = 14 m.

The coefficient of friction between the parcel and the ramp is mu.

In a model of the parcel’s motion, the parcel is treated as a particle.

Use the work-energy principle to find the value of mu.   

1b
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1 mark

Suggest one way in which the model could be refined to make it more realistic.

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2a
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4 marks

A car of mass 600 kg is moving along a straight horizontal road.

At the instant when the speed of the car is v space ms to the power of negative 1 end exponent, the resistance to the motion of the car is modelled as a force of magnitude open parentheses 200 plus 2 v close parentheses space straight N.

The engine of the car is working at a constant rate of 12 kW.

Find the acceleration of the car at the instant when v equals 20.

2b
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5 marks

Later on the car is moving up a straight road inclined at an angle theta to the horizontal, where sin theta space equals space 1 over 14.

At the instant when the speed of the car is v space ms to the power of negative 1 end exponent, the resistance to the motion of the car from non-gravitational forces is modelled as a force of magnitude open parentheses 200 plus 2 v close parentheses space straight N.

The engine is again working at a constant rate of 12 kW.

At the instant when the car has speed w space ms to the power of negative 1 end exponent, the car is decelerating at 0.05 ms−2.

Find the value of w.

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3a
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4 marks

fig-1-june-2018-8fm0-a-level-further-maths

Figure 1

Figure 1 shows a ramp inclined at an angle θ to the horizontal, where sin space theta equals 2 over 7

A parcel of mass 4 kg is projected, with speed 5 ms–1, from a point A on the ramp.
The parcel moves up a line of greatest slope of the ramp and first comes to instantaneous rest at the point B, where AB = 2.5 m.
The parcel is modelled as a particle.

The total resistance to the motion of the parcel from non‑gravitational forces is modelled as a constant force of magnitude R newtons.

Use the work‑energy principle to show that R = 8.8 .

3b
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3 marks

After coming to instantaneous rest at B, the parcel slides back down the ramp. The total resistance to the motion of the particle is modelled as a constant force of magnitude 8.8 N.

Find the speed of the parcel at the instant it returns to A.

3c
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2 marks

Suggest two improvements that could be made to the model.

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4a
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4 marks

A van of mass 750 kg is moving along a straight horizontal road. At the instant when the van is moving at v space ms to the power of negative 1 end exponent, the resistance to the motion of the van is modelled as a force of magnitude lambda v space straight N, where lambda is a constant.

The engine of the van is working at a constant rate of 18 kW.
At the instant when v equals 15, the acceleration of the van is 0.6 ms–2.

Show that lambda equals 50.

4b
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5 marks

The van now moves up a straight road inclined at an angle to the horizontal, where sin space alpha equals 1 over 15
At the instant when the van is moving at v ms–1, the resistance to the motion of the van from non‑gravitational forces is modelled as a force of magnitude 50 v space straight N.
When the engine of the van is working at a constant rate of 12 kW, the van is moving at a constant speed V ms–1.

Find the value of V.

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5a
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4 marks

A lorry of mass 16 000 kg moves along a straight horizontal road.

The lorry moves at a constant speed of 25 ms-1

In an initial model for the motion of the lorry, the resistance to the motion of the lorry is modelled as having constant magnitude 16 000 N.

Show that the engine of the lorry is working at a rate of 400 kW.

5b
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6 marks

The model for the motion of the lorry along the same road is now refined so that when the speed of the lorry along the same road is V ms-1, the resistance to the motion of the lorry is modelled as having magnitude 640V Newtons.

Assuming that the engine of the lorry is working at the same rate of 400 kW,

use the refined model to find the speed of the lorry when it is accelerating at 2.1 ms-2.

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6
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7 marks

A particle, P, of mass m kg is projected with speed 5 ms-1 down a line of greatest slope of a rough plane. The plane is inclined to the horizontal at an angle alpha, where sin space alpha equals 3 over 5.

The total resistance to the motion of P is a force of magnitude 1 fifth m g.

Use the work-energy principle to find the speed of P at the instant when it has moved a distance 8 m down the plane from the point of projection.

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7a
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4 marks

A car of mass 600 kg pulls a trailer of mass 150 kg along a straight horizontal road. The trailer is connected to the car by a light inextensible towbar, which is parallel to the direction of motion of the car. The resistance to the motion of the trailer is modelled as a constant force of magnitude 200 N. At the instant when the speed of the car is v ms–1, the resistance to the motion of the car is modelled as a force of magnitude open parentheses 200 plus lambda v close parentheses space straight N, where lambda is a constant.

When the engine of the car is working at a constant rate of 15 kW, the car is moving at a constant speed of 25 ms–1.

Show that lambda equals 8.

7b
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4 marks

Later on, the car is pulling the trailer up a straight road inclined at an angle theta to the horizontal, where sin space theta equals 1 over 15.
The resistance to the motion of the trailer from non-gravitational forces is modelled as a constant force of magnitude 200 N at all times. At the instant when the speed of the car is v ms–1, the resistance to the motion of the car from non-gravitational forces is modelled as a force of magnitude open parentheses 200 plus 8 v close parentheses space straight N.

The engine of the car is again working at a constant rate of 15 kW.

When v equals 10, the towbar breaks. The trailer comes to instantaneous rest after moving a distance d metres up the road from the point where the towbar broke.

Find the acceleration of the car immediately after the towbar breaks.

7c
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4 marks

Use the work-energy principle to find the value of d.

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8a
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1 mark

A car of mass 1000 kg moves along a straight horizontal road.

In all circumstances, when the speed of the car is v space ms to the power of negative 1 end exponent, the resistance to the motion of the car is modelled as a force of magnitude c v squared space straight N, where c is a constant.

The maximum power that can be developed by the engine of the car is 50 kW.

At the instant when the speed of the car is 72 kmh–1 and the engine is working at its maximum power, the acceleration of the car is 2.25 ms–2.

Convert 72 kmh–1 into ms–1.

8b
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7 marks

Find the acceleration of the car at the instant when the speed of the car is 144 kmh–1 and the engine is working at its maximum power. 

8c
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4 marks

The maximum speed of the car when the engine is working at its maximum power is V kmh–1.

Find, to the nearest whole number, the value of V.

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9a
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4 marks

A truck of mass 1200 kg is moving along a straight horizontal road.

At the instant when the speed of the truck is vms–1, the resistance to the motion of the truck is modelled as a force of magnitude open parentheses 900 plus 9 v close parentheses space straight N.

The engine of the truck is working at a constant rate of 25 kW.

Find the deceleration of the truck at the instant when v equals 25.

9b
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5 marks

Later on, the truck is moving up a straight road that is inclined at an angle theta to the horizontal, where sin space theta space equals fraction numerator space 1 over denominator 20 end fraction.

At the instant when the speed of the truck is v ms–1, the resistance to the motion of the truck from non‑gravitational forces is modelled as a force of magnitude open parentheses 900 plus 9 v close parentheses space straight N.

When the engine of the truck is working at a constant rate of 25 kW the truck is moving up the road at a constant speed of V ms–1.

Find the value of V.

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10a
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2 marks

fig-1-oct-2021-8fm0-25-further-mechanics-edexcel

Figure 1

A small book of mass m is held on a rough straight desk lid which is inclined at an angle alpha to the horizontal, where tan space alpha space equals space 3 over 4.

The book is released from rest at a distance of 0.5 m from the edge of the desk lid, as shown in Figure 1. The book slides down the desk lid and then hits the floor that is 0.8 m below the edge of the desk lid. The coefficient of friction between the book and the desk lid is 0.4.

The book is modelled as a particle which, after leaving the desk lid, is assumed to move freely under gravity.

Find, in terms of m and g, the magnitude of the normal reaction on the book as it slides down the desk lid. 

10b
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5 marks

Use the work-energy principle to find the speed of the book as it hits the floor.

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11a
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7 marks

The total mass of a cyclist and his bicycle is 100 kg. 

In all circumstances, the magnitude of the resistance to the motion of the cyclist from non-gravitational forces is modelled as being k v squared N, where vms−1 is the speed of the cyclist.

The cyclist can freewheel, without pedalling, down a slope that is inclined to the horizontal at an angle alpha, where  sin space alpha space equals 1 over 35, at a constant speed of V ms−1.

When he is pedalling up a slope that is inclined to the horizontal at an angle beta, where sin space beta space equals space 1 over 70, and he is moving at the same constant speed V ms−1 , he is working at a constant rate of space P spacewatts.

Find P in terms of V.

11b
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4 marks

If he pedals and works at a rate of 35 V Watts on a horizontal road, he moves at a constant speed of U ms-1.

Find U in terms of V.

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12a
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5 marks

A van of mass 900 kg is moving along a straight horizontal road.

At the instant when the speed of the van is v ms−1, the resistance to the motion of the van is modelled as a force of magnitude open parentheses 500 plus 7 v close parentheses space straight N.

When the engine of the van is working at a constant rate of 18 kW, the van is moving along the road at a constant speed V ms−1.

Find the value of V.

12b
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4 marks

Later on, the van is moving up a straight road that is inclined to the horizontal at an angle theta , where sin space theta space equals space 1 over 21.

At the instant when the speed of the van is v ms−1, the resistance to the motion of the van from non-gravitational forces is modelled as a force of magnitude open parentheses 500 plus 7 v close parentheses space straight N.

The engine of the van is again working at a constant rate of 18 kW.

Find the acceleration of the van at the instant when v equals 15.

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