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Proton (1H) NMR Spectroscopy (CIE A Level Chemistry)

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Interpreting & Explaining Proton (1H) NMR Spectra

  • Nuclear Magnetic Resonance (NMR) spectroscopy is used for analysing organic compounds
  • Atoms with odd mass numbers usually show signals on NMR
  • In 1H NMR, the magnetic field strengths of protons in organic compounds are measured and recorded on a spectrum
  • Protons on different parts of a molecule (in different molecular environments) emit different frequencies when an external magnetic field is applied
  • All samples are measured against a reference compound – Tetramethylsilane (TMS)
    • TMS shows a single sharp peak on NMR spectra, at a value of zero
    • Sample peaks are then plotted as a ‘shift’ away from this reference peak
    • This gives rise to ‘chemical shift’ values for protons on the sample compound
    • Chemical shifts are measured in parts per million (ppm)

Features of an NMR spectrum

  • NMR spectra show the intensity of each peak against its chemical shift
  • The area under each peak gives information about the number of protons in a particular environment
  • The height of each peak shows the intensity/absorption from protons
  • A single sharp peak is seen to the far right of the spectrum
    • This is the reference peak from TMS
    • Usually at chemical shift 0 ppm

Low resolution 1H NMR for ethanol

Analytical Techniques - Features of a 1H NMR Spectrum, downloadable AS & A Level Chemistry revision notes

The key features of this spectrum are the number and position of the peaks

Molecular environments

  • Hydrogen atoms of an organic compound are said to reside in different molecular environments
    • E.g. Methanol has the molecular formula CH3OH
    • There are 2 molecular environments: -CH3 and -OH
  • The hydrogen atoms in these environments will appear at 2 different chemical shifts
  • Different types of protons are given their own range of chemical shifts

Worked example

How many different 1H chemical environments occur in 2-methylpropane?

Answer:

  • Two different 1H chemical environments occur in 2-methylpropane
    • The three methyl groups are in the same 1H environment
    • The lone hydrogen is in its own 1H environment

Worked example environments answer, downloadable AS & A Level Chemistry revision notes

Chemical shift values for 1H molecular environments table

Environment of proton Example Chemical shift range, δ / ppm
alkane –CH3, –CH2–, >CH 0.9 - 1.7
alkyl next to C=O CH3–C=O, –CH2–C=O, >CH–C=O 2.2 - 3.0
alkyl next to aromatic ring CH3–Ar, –CH2–Ar, >CH2–Ar 2.3 - 3.0
alkyl next to electronegative atom CH3–O, CH2–O, CH2–Cl   3.2 - 4.0
attached to alkene =CHR 4.5 - 6.0
attached to aromatic ring H–Ar 6.0 - 9.0
aldehyde HCOR 9.3 - 10.5
alcohol* ROH 0.5 - 6.0
phenol* Ar–OH  4.5 - 7.0
carboxylic acid RCOOH 9.0 - 13.0
alkyl amine* R–NH–   1.0 - 5.0
aryl amine* Ar–NH2 3.0 - 6.0
amide RCONHR 5.0 - 12.0

* δ values for O–H protons and N–H protons vary depending on the solvent and concentration

  • Protons in the same chemical environment are chemically equivalent
    • 1,2-dichloroethane, Cl-CH2-CH2-Cl has one chemical environment as these four hydrogens are all exactly equivalent
  • Each individual peak on a 1H NMR spectrum relates to protons in the same environment
    • Therefore, 1,2-dichloroethane would produce one single peak on the NMR spectrum as the protons are in the same environment

Identifying molecular environments in 1,2-dichloroethane

1,2-dichloroethane, downloadable AS & A Level Chemistry revision notes

All four protons in the 1,2-dichloroethane molecule are equivalent

Low resolution 1H NMR

  • Peaks on a low resolution NMR spectrum refer to molecular environments of an organic compound
    • E.g. Ethanol has the molecular formula CH3CH2OH
    • This molecule as 3 separate environments: -CH3, -CH2, -OH
    • So 3 peaks would be seen on its spectrum at 1.2 ppm (-CH3), 3.7 ppm (-CH2) and 5.4 ppm (-OH)

Low resolution NMR spectrum of ethanol

Analytical Techniques - Low Resolution NMR of Ethanol, downloadable AS & A Level Chemistry revision notes

The low resolution NMR spectrum of ethanol shows 3 peaks for the 3 molecular environments

High resolution 1H NMR

  • More structural details can be deduced using high resolution NMR
  • The peaks observed on a high resolution NMR may sometimes have smaller peaks clustered together
  • The splitting pattern of each peak is determined by the number of protons on neighbouring environments

The number of peaks a signal splits into = n + 1

    • (Where n = the number of protons on the adjacent carbon atom)

Predicting Shifts & Splitting Patterns

Spin-Spin Splitting

  • A high resolution 1H NMR spectrum can show you the structure of the molecule but also the peaks can be split into sub-peaks or splitting patterns
  • These are caused by a proton's spin interacting with the spin states of nearby protons that are in different environments
    • This can provide information about the number of protons bonded to adjacent carbon atoms
    • The splitting of a main peak into sub-peaks is called spin-spin splitting or spin-spin coupling

High resolution 1H NMR spectrum of ethanol

The high resolution 1H NMR spectrum of ethanol showing the splitting patterns of each of the 3 peaks. Using the n+1, it is possible to interpret the splitting pattern

Exam Tip

  • It is very rare that the spin-spin splitting of equivalent protons is covered in teaching because it is so rarely asked in exams
  • Equivalent protons do not cause spin-spin splitting
    • The simplest example of this is benzene
      • In benzene, all of the protons are equivalent
      • This means that they are seen as one singlet in the high resolution 1H NMR spectrum  of benzene 

The n+1 rule

  • The number of sub-peaks is one greater than the number of adjacent protons causing the splitting
    • For a proton with protons attached to an adjacent carbon atom, the number of sub-peaks in a splitting pattern = n+1
  • When analysing spin-spin splitting, it shows you the number of hydrogen atoms on the adjacent carbon atom
  • These are the splitting patterns that you need to be able to recognise from a 1H spectra:

1H NMR peak splitting patterns table

Number of adjacent protons (n) Splitting pattern using the n+1 rule the peak will split into .... Relative intensities in splitting pattern Shape
0 1, singlet 1 NMR singlet peak
1 2, doublet 1 : 1 NMR doublet peak
2 3, triplet 1 : 2 : 1 NMR triplet peak
3 4, quartet 1 : 3 : 3 : 1 NMR quartet peak
  • Splitting patterns must occur in pairs because each proton splits the signal of the other
  • There are some common splitting pairs you will see in a spectrum however you don't need to learn these but can be worked out using the n+1 rule
    • You will quickly come to recognise the triplet / quartet combination for a CH3CH2 because it is so common

Common pair of splitting patterns

  • A quartet and a triplet in the same spectrum usually indicate an ethyl group, CH3CH2-
  • The signal from the CH3 protons is split as a triplet by having two neighbours
  • The signal from the CH2 protons is split as a quartet by having three neighbours
  • Here are some more common pairs of splitting patterns

Common pairs of splitting patterns

Common pairs of splitting patterns, downloadable AS & A Level Chemistry revision notes

1H NMR spectrum of propane

Propane spectrum, downloadable AS & A Level Chemistry revision notes

  • The CH2 signal in propane (blue) is observed as a heptet because it has six neighbouring equivalent H atoms (n+1 rule), three on either side in two equivalent CH3 groups
  • The CH3 groups (red) produce identical triplets by coupling with the CH2 group

Worked example

For the compound (CH3)2CHOH, predict the following:

  1. The number of peaks
  2. The type of proton and chemical shift 
  3. The relative peak areas
  4. The splitting pattern

Answers:

  1. The number of peaks
    • 3 peaks
  2. The type of proton and chemical shift 
    • (CH3)2CHOH at 0.9 - 1.7 ppm
    • (CH3)2CHOH at 3.2 - 4.0 ppm
    • (CH3)2CHOH at 0.5 - 6.0 ppm
  3. The relative peak areas
    • Ratio 6 : 1 : 1
  4. The splitting pattern
    • (CH3)2CHOH split into a doublet (1+1=2)
    • (CH3)2CHOH split into a heptet (6+1=7)

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Caroline

Author: Caroline

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about creating high-quality resources to help students achieve their full potential.