CIE A Level Maths: Probability & Statistics 2

Topic Questions

2.2 Linear Combinations of Random Variables

1a
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4 marks

The discrete random variable X has the probability distribution shown in the following table.

bold italic x 0 1 2 3 4
bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 0.1 0.2 0.3 0.2 0.2

(i)
Show that E left parenthesis X right parenthesis equals 2.2.
(ii)
Show that V a r left parenthesis X right parenthesis equals 1.56.
1b
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1 mark

Complete the row in the table below to show the probability distribution for X plus 5.

bold italic x 0 1 2 3 4
bold italic x bold plus bold 5 5        
bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 0.1 0.2 0.3 0.2 0.2
1c
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2 marks

Use the second and third rows in table in part (b) with the formula E left parenthesis X plus 5 right parenthesis equals sum left parenthesis x plus 5 right parenthesis p to verify that E left parenthesis X plus 5 right parenthesis equals E left parenthesis X right parenthesis plus 5.

1d
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2 marks

Use the second and third rows in table in part (b) with the formulae E left parenthesis X plus 5 right parenthesis squared equals sum left parenthesis x plus 5 right parenthesis squared p and V a r left parenthesis X plus 5 right parenthesis equals E left parenthesis X plus 5 right parenthesis squared minus left parenthesis E left parenthesis X plus 5 right parenthesis right parenthesis squared to verify that V a r left parenthesis X plus 5 right parenthesis equals V a r left parenthesis X right parenthesis.

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2a
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4 marks

The discrete random variable X has the probability distribution shown in the following table.

bold italic x -1 0 1 2 3
bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 0.2 0.1 0.1 0.5 0.1

(i)
Show that E left parenthesis X right parenthesis equals 1.2
(ii)
Show that V a r left parenthesis X right parenthesis equals 1.76
2b
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1 mark

Complete the row in the table below to show the probability distribution for 3 X.

bold italic x -1 0 1 2 3
bold 3 bold italic x -3        
bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 0.2 0.1 0.1 0.5 0.1
2c
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2 marks

Use the second and third rows in table in part (a) with the formula E left parenthesis 3 X right parenthesis equals sum left parenthesis 3 x right parenthesis p to verify that E left parenthesis 3 X right parenthesis equals 3 space E left parenthesis X right parenthesis.

2d
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2 marks

Use the second and third rows in table in part (a) with the formula E left parenthesis 3 X right parenthesis squared equals sum left parenthesis 3 x right parenthesis squared p space and space V a r left parenthesis 3 X right parenthesis equals E left parenthesis 3 X right parenthesis squared minus left parenthesis E left parenthesis 3 X right parenthesis right parenthesis squared to verify that V a r left parenthesis 3 X right parenthesis equals 9 space V a r left parenthesis X right parenthesis.

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3
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6 marks

X is a random variable such that E left parenthesis X right parenthesis equals 5 space and space V a r left parenthesis X right parenthesis equals 3.

Using the formulae E left parenthesis a X plus b right parenthesis equals a E left parenthesis X right parenthesis plus b space and space V a r left parenthesis a X plus b right parenthesis equals a squared V a r left parenthesis X right parenthesis, find the mean and variance of the following random variables:

(i)
4 X plus 1
(ii)
7 X minus 2
(iii)
5 minus X

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4a
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2 marks

If X is normally distributed, then a X plus b is normally distributed for any constants a and b.

Using the formulae E left parenthesis a X plus b right parenthesis equals a E left parenthesis X right parenthesis plus b space and space V a r left parenthesis a X plus b right parenthesis equals a squared V a r left parenthesis X right parenthesis, show that, if X tilde N left parenthesis mu comma sigma squared right parenthesis then:

a X plus b tilde space N left parenthesis a mu plus b comma a squared sigma squared right parenthesis

4b
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4 marks

The random variable X space tilde N left parenthesis 50 comma 16 right parenthesis, write down the distribution for the random variable:

(i)
2 X plus 10
(ii)
3 X minus 20
(iii)
50 minus X
4c
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4 marks

The random variable Y tilde N left parenthesis 15 comma 5 squared right parenthesis

(i)
Find P left parenthesis Y less than 18 right parenthesis
(ii)
Write down the distribution of 4 Y plus 40
(iii)
Find P left parenthesis 4 Y plus 40 less than 112 right parenthesis

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5a
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4 marks

If X and Y are two independent random variables, then:

E left parenthesis X plus-or-minus Y right parenthesis equals E left parenthesis X right parenthesis plus-or-minus E left parenthesis Y right parenthesis space and space V a r left parenthesis X plus-or-minus Y right parenthesis equals V a r left parenthesis X right parenthesis plus V a r left parenthesis Y right parenthesis

The random variable S has a mean of 10 and a variance of 5 and the random variable T has a mean of 15 and a variance of 7.

Find the mean and variance of:

(i)
S plus T
(ii)
S minus T
5b
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3 marks

Using the above formulae and the formulae E left parenthesis a X plus b right parenthesis equals a space E left parenthesis X right parenthesis plus b space and space V a r left parenthesis a X plus b right parenthesis equals a squared space V a r left parenthesis X right parenthesis, it follows that if X and Y are two independent random variables then:

E left parenthesis a X plus b Y right parenthesis equals a space E left parenthesis X right parenthesis plus b space E left parenthesis Y right parenthesis space a n d space V a r left parenthesis a X plus b Y right parenthesis equals a squared space V a r left parenthesis X right parenthesis plus b squared space V a r left parenthesis Y right parenthesis

Find the mean and variance of 3 S plus 2 T.

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6
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8 marks

If X space and space Y are normally distributed and independent then X plus Y is also normally distributed. As a X plus b is also normally distributed it follows that a X plus b Y is normally distributed.

In particular, if X tilde N left parenthesis mu subscript x comma sigma subscript x superscript 2 right parenthesis space and space Y tilde N left parenthesis mu subscript y comma sigma subscript y superscript 2 right parenthesis are two independent distributions, then:

X plus Y tilde space N left parenthesis a mu subscript x plus b mu subscript y comma a squared sigma subscript x superscript 2 plus b squared sigma subscript y superscript 2 right parenthesis

The random variables R space tilde N left parenthesis 10 comma 16 right parenthesis comma space space S space tilde N left parenthesis 15 comma 9 right parenthesis space and space space T space tilde N left parenthesis 25 comma 25 right parenthesis are independent.

Write down the distribution of:

(i)
R plus S
(ii)
2 S plus 3 T

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7a
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3 marks

The random variable is normally distributed with a mean of 10 and a standard deviation of 3.

State the distribution of the sum of three independent observations of the random variable X.

7b
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2 marks

State the distribution of the random variable 3 X.

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1
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4 marks

The random variable X has mean 8 and variance 15. Given that

E left parenthesis a X plus b right parenthesis equals 23
V a r left parenthesis a X plus b right parenthesis equals 135

Find the two possible values of b.

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2a
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8 marks

The probability distribution for the random variable X is shown below.

bold italic x 1 3 5 7
bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 0.5 0.15 0.25 0.1

Find the value of:

(i)
E left parenthesis fraction numerator X plus 7 over denominator 2 end fraction right parenthesis
(ii)
V a r left parenthesis X over 5 minus 2 right parenthesis
(iii)
V a r left parenthesis 100 minus 2 X right parenthesis
(iv)
E left parenthesis 3 X squared minus 1 right parenthesis
2b
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2 marks

Show that E left parenthesis X minus E left parenthesis X right parenthesis right parenthesis equals space 0

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3a
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5 marks

The random variable X has mean of mu and standard deviation of sigma. The random variable Y has mean of 3 and standard deviation of 4. Given that

E left parenthesis 2 X plus 5 Y right parenthesis equals 25
V a r left parenthesis 2 X plus 5 Y right parenthesis equals 724

Find the value of mu and the value of sigma.

3b
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1 mark

State the assumption that has been made about the random variables X space and space Y.

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4a
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3 marks

A fair six-sided dice labelled with numbers 1, 1, 2, 2, 3, 3 is rolled and the number it lands on is denoted D.

Show that E left parenthesis D right parenthesis equals 2 and find V a r left parenthesis D right parenthesis.

4b
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3 marks

The dice is rolled twice and the arithmetic mean of the two numbers, which is denoted ̅ D is calculated.

Draw up a probability distribution table for ̅ D.

4c
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2 marks

Find E left parenthesis ̅ D right parenthesis and V a r left parenthesis ̅ D right parenthesis.

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5a
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4 marks

Frank has a variable tariff for his electricity and gas bills. His monthly electricity bill is $E and his monthly gas bill is $G. E space and space G are independent random variables with distributions N left parenthesis 85 comma 9.4 squared right parenthesis space and space N left parenthesis 53 comma 12.45 right parenthesis respectively.

Find the probability that the total electricity and gas bill in a month exceeds $150.

5b
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5 marks

Frank has a part-time job tutoring college students. His monthly income from this job can be modelled as a Normal distribution with mean $504 and standard deviation $41. Frank uses this income to pay for his gas and electricity bills, he puts the remaining money into his partner’s bank account each month.

(i)
Find the probability that Frank puts between $350 and $450 into his partner’s bank account in a month.
(ii)
What assumption did you make in part (b)(i) regarding his income and his bills.

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6a
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1 mark

Veronica, a taxi driver in London, charges her customers a fixed fee of £5 plus £1.20 per mile. The lengths of her customers’ journeys are normally distributed with mean 16.7 miles and standard deviation 4.1 miles.

Find the standard deviation of the prices of Veronica’s taxi rides.

6b
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4 marks

Find the probability that a taxi ride will cost less than £30.

6c
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4 marks

Find the probability that the total cost of two independent taxi rides is more than £60.

6d
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2 marks

On a bank holiday, Veronica doubles her prices.

Find the variance of the prices of Veronica’s taxi ride on a bank holiday.

6e
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1 mark

Find the probability that a taxi ride on a bank holiday will cost more than £60.

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7a
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5 marks

The random variable X  has the distribution N left parenthesis 5.9 comma 2.1 squared right parenthesis.

Find the probability that the sum of 50 independent observations of exceeds 300.

7b
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1 mark

Hence find the probability that the arithmetic mean of 50 independent observations of X is less than 6.

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8a
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6 marks

Dinah’s Diner is famous for its triple burger which is made up of three beef patties, two rashers of bacon and a toasted bread bun. The mass, in grams, of a beef patty follows the distribution N left parenthesis 110 comma 6 squared right parenthesis. The mass, in grams, of a rasher of bacon follows the distribution N left parenthesis 30 comma 5 squared right parenthesis. The mass, in grams, of a toasted bread bun follows the distribution N left parenthesis 50 comma 3 squared right parenthesis.

Estimate the proportion of triple burgers at Dinah’s Diner that have a mass of more than 450 g.

8b
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1 mark

State, with a reason, whether the probability that the total mass of two triple burgers exceeding 900 g is equal to your answer in part (a).

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1a
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7 marks

The random variable X  has a mean of 40 and a variance of 36.

Find the mean and variance of:

(i)
2 X plus 5
(ii)
3 X minus 10
(iii)
100 minus 2 X
1b
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3 marks

It is known that X  follows a Normal distribution.

Find P left parenthesis 2 X plus 1 less than 75 right parenthesis.

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2
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4 marks

The random variable X has mean mu and variance sigma squared. Given that

E left parenthesis 2 X plus 7 right parenthesis equals 16
V a r left parenthesis 2 X plus 7 right parenthesis equals 5

Find the value of mu and the value of sigma squared.

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3a
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6 marks

The random variable X has mean and variance of 4, and the random variable Y has mean and variance of 5. X space and space Y are independent.

Find the mean and variance of the random variable:

(i)
X plus Y
(ii)
3 X plus 2 Y
(iii)
X minus Y
(iv)
3 X minus 2 Y
3b
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4 marks

Given that X space and space Y follow Normal distributions, find:

(i)
P left parenthesis X plus Y less than 4 right parenthesis
(ii)
P left parenthesis X minus Y greater than 4 right parenthesis

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4a
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3 marks

A game involves flipping a biased coin where the probability of landing on tails is 0.2, otherwise the coin lands on heads. In the game the coin is flipped twice and the number of tails, T, is recorded.

Draw up the probability distribution table for T.

4b
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3 marks

To calculate the score of the game, a player multiplies the number of tails by 10 and then subtracts 5.

Find the mean score.

4c
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4 marks

Find the standard deviation of the scores.

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5a
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1 mark

The probability distributions for two independent random variables S space and space T are shown below.

bold italic s

1

4

9

bold italic P bold left parenthesis bold italic S bold equals bold italic s bold right parenthesis

0.2

0.5

0.3

bold italic t 1

3

6

10

bold italic P bold left parenthesis bold italic T bold equals bold italic t bold right parenthesis

0.25

0.25

0.25

0.25


Find the value of E left parenthesis S right parenthesis
.

5b
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3 marks

Find the value of E left parenthesis 16 S plus 15 T right parenthesis.

5c
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4 marks

Given that V a r left parenthesis T right parenthesis equals 11.5, find the value of V a r left parenthesis S plus 2 T right parenthesis.

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6a
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5 marks

The distributions of the independent random variables X space and space Y are N left parenthesis 8 comma 2 right parenthesis space and space N left parenthesis 9 comma 3 right parenthesis respectively.

Find the probability that

(i)
2 X space plus space 3 Y space greater than space 44
(ii)

The sum of two observations from X and three observations from Y are greater than 44.

6b
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1 mark

Explain why your answers to (a) part (i) and (ii) are different.

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7a
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1 mark

Malik is fighting a boss in a video game. The loading times for the boss fight, L, follow a Normal distribution with mean of 14.1 seconds and variance of 6.1 seconds². The times it takes Malik to beat the boss, B, follow a Normal distribution with mean of 101.7 seconds and variance of 243.5 seconds².

The time taken to complete the level, C, is the sum of the loading time and the time taken to beat the boss.

State an assumption that is needed to model C using a Normal distribution.

7b
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2 marks

Assuming the assumption in part (a) is true, write down the distribution for C.

7c
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3 marks

Find the probability that it takes Malik between 100 and 120 seconds to complete the level.

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1
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6 marks

The random variable X  has mean 2 and variance 3 and the random variable Y has mean 5 and variance 6. Given that X space and space Y are independent and that

E left parenthesis a X plus b Y right parenthesis equals negative 4 space
V a r left parenthesis a X plus b Y right parenthesis equals 51

Find the integer values of a and b.

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2a
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4 marks

The random variable X has mean mu and variance sigma squared.  The arithmetic mean of n independent observations of X is denoted by ̅ X.

Show that E left parenthesis ̅ X space right parenthesis equals mu and V a r left parenthesis ̅ X right parenthesis equals sigma squared over n.

2b
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4 marks

40 independent observations are taken from the distribution N left parenthesis 30 comma 5 squared right parenthesis and the arithmetic mean, ̅ Y, is calculated.

(i)
State, with a reason, whether the Central Limit Theorem is needed to model ̅ Y as a Normal distribution.
(ii)
Find P left parenthesis 29 less than Y space less than 30 right parenthesis.

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3
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7 marks

The probability of rolling a 6 on a biased die is p. In a game, this die is rolled twice and then the player multiplies the number of times the die lands on a 6 by 50 and then adds 5 to calculate the score.

(i)
Given that the mean score is 15, draw up a probability distribution table for the number of times the die lands on a 6 when rolled twice.
(ii)
Find the variance of the scores.

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4a
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4 marks

Two friends, Forrest and Gumpy, are planning to run a marathon together. The distributions F space tilde N left parenthesis 253 comma 95 right parenthesis space and space G space tilde N left parenthesis 281 comma 52 right parenthesis are used to model the times in minutes it takes Forrest and Gumpy to complete a marathon respectively. It can be assumed that their times are independent.

Find the probability that Forrest completes the marathon quicker than Gumpy.

4b
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3 marks

Find the probability that Gumpy is still running the marathon one hour after Forrest has completed it.

4c
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4 marks

Find the probability that their times taken to complete the marathon differ by more than 5 minutes.

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5
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7 marks

A paper bag can hold 20 kg before it breaks. The mass of an orange is modelled using a Normal distribution with mean 260 g and standard deviation 12 g. The mass of each orange is independent from the others.

Find the maximum number of oranges that a paper bag can hold before the probability of the bag breaking exceeds 0.1%.

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6a
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4 marks

Roger is considering buying a new pet. He has researched the prices, in €, of rabbits, chinchillas and degus. The information is shown in the table below. The prices of the three types of animals are normally distributed and independent of each other.

 

Mean

Standard Deviation

Rabbit

30

9

Chinchilla

145

20

Degu

37

6


Find the probability that the cost of two independently bought degus is less than €70.

6b
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4 marks

Find the probability that a randomly selected degu is more expensive than a randomly selected rabbit.

6c
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4 marks

Find the probability that a randomly selected chinchilla is more than five times as expensive as a randomly selected rabbit.

6d
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5 marks

Roger and his housemate Lucy have decided to buy one of each type of pet for their house. Roger loves rabbits so he will pay for the rabbit himself, he will pay 50% of the cost for the chinchilla and 10% of the cost for the degu.

Find the probability that, in total, Roger pays less than €100 for the three pets.

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7a
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4 marks

The random variables X tilde space N left parenthesis 50 comma 9 squared right parenthesis space a n d space Y tilde space N left parenthesis 400 comma 150 right parenthesis are independent.

Find P left parenthesis Y less than 7 X plus 40 right parenthesis.

7b
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5 marks

There’s a 99.95% chance that the sum of a random observation of Xand a random observation of Y is bigger than k.  Find the value of k.

7c
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5 marks

Find the probability that the sum of three independent observations of X is more than one third of one observation of Y.

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8
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7 marks

In a video game a player gets points for completing a level and for defeating enemies, these points are independent of each other. The amount of points a player gets for completing the level and for defeating an enemy can be modelled as L space tilde N left parenthesis 500 comma 220 right parenthesis space and space E tilde N left parenthesis 150 comma 85 right parenthesis respectively.

In a bonus stage, the points for completing the level are tripled and there are five enemies (points for defeating enemies are not tripled), the total score is the sum of the points for completing the level and defeating the enemies. The top 10% of scores make the leadership board.

Estimate the minimum score that would make the leadership board.

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