Edexcel International AS Maths: Statistics 1

Topic Questions

3.1 Discrete Random Variables

1a
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3 marks

The discrete random variable, X, is defined as the number of sixes obtained from rolling two fair dice.

(i)
Find the probability of obtaining two sixes from rolling two fair dice.
(ii)
Complete the following probability distribution table for X:

 bold italic x

0

1

2

 bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis  25 over 36

 

 

1b
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2 marks

Use the table, or otherwise, to find the probability of obtaining at least one six from rolling two fair dice.

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2a
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1 mark

The discrete random variable X has the probability function

P open parentheses X equals x close parentheses open curly brackets table row cell 1 fourth end cell cell x equals 0 comma 1 comma 2 comma 3 end cell row 0 otherwise end table close

Briefly explain why X has a uniform probability distribution.

2b
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2 marks

Find:

(i)
P left parenthesis 1 less or equal than X less or equal than 2 right parenthesis
(ii)
P left parenthesis X less than 3 right parenthesis.

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3a
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2 marks

The discrete random variable X has the probability function

P open parentheses X equals x close parentheses space equals space open curly brackets table row cell k x end cell cell x equals 2 comma 3 end cell row 0 otherwise end table close

Use the fact that the sum of all probabilities equals 1 to show that k equals 0.2.

3b
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2 marks

Write down:

(i)
P left parenthesis 2 less or equal than X less than 3 right parenthesis
(ii)
P left parenthesis X equals 5 right parenthesis.

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4a
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2 marks

A discrete random variable  has the probability distribution shown in the following table:

 bold italic x

2

4

6

8

10

 bold P stretchy left parenthesis X equals x stretchy right parenthesis  2 over 5  1 over 10  1 fifth p  1 over 10 

Use the fact that the sum of all probabilities equals 1 to find the value of p.

4b
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4 marks

Find:

(i)
P left parenthesis X less or equal than 4 right parenthesis
(ii)
P left parenthesis X greater than 7 right parenthesis
(iii)
P left parenthesis 2 less or equal than X less or equal than 6 right parenthesis
(iv)
P left parenthesis 3 less than X less than 7 right parenthesis.

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5a
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2 marks

The discrete random variable X has the probability function

P open parentheses X equals x close parentheses equals open curly brackets table row cell k x end cell cell x equals 1 comma space 3 end cell row cell fraction numerator k x over denominator 2 end fraction end cell cell x equals 2 comma space 4 end cell row 0 otherwise end table close

Use the fact that the sum of all probabilities equals 1 to show that k equals 1 over 7.

5b
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1 mark

Briefly explain why X has a non-uniform probability distribution.

5c
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2 marks

Show that P left parenthesis X less or equal than 2 right parenthesis equals P left parenthesis X equals 4 right parenthesis.

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6a
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2 marks

The discrete random variable  has the probability distribution shown in the following table:

bold italic x

1

2

3

4

5

bold italic P stretchy left parenthesis X equals x stretchy right parenthesis 5 over 12 2 over 12 1 over 12 3 over 12 1 over 12

Complete the following cumulative probability function table for :

bold italic x

1

2

3

4

5

5 over 12 7 over 12     1
6b
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5 marks

Use your table from part (a) to find:

(i)
F left parenthesis 3 right parenthesis
(ii)
P left parenthesis X greater or equal than 4 right parenthesis
(iii)
P left parenthesis 2 less or equal than X less or equal than 4 right parenthesis.

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7a
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3 marks

The discrete random variable X has the cumulative probability distribution shown in the following table:

bold italic x

-2

-1

0

1

2

bold italic P bold left parenthesis bold italic X bold less or equal than bold italic x bold right parenthesis 1 fifth 2 over 5 3 over 5 4 over 5 5 over 5

Complete the following probability distribution table for X:

bold italic x

-2

-1

0

1

2

bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 1 fifth 1 fifth      
7b
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2 marks

Find:

(i)
P left parenthesis X less than 0 right parenthesis
(ii)
P left parenthesis X greater than 0 right parenthesis.
7c
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2 marks

Explain, with a reason, whether X has a uniform probability distribution or not.

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8a
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2 marks

The discrete random variable X has the probability distribution shown in the following table:

bold italic x

1

2

3

4

5

bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis  5 over 12  2 over 12  1 over 12  3 over 12  1 over 12

Use the formula space E left parenthesis X right parenthesis equals sum x p space to show that E left parenthesis X right parenthesis equals 29 over 12.

8b
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2 marks

Use the formula E left parenthesis X squared right parenthesis equals sum x squared p to show that E left parenthesis X squared right parenthesis equals 95 over 12.

8c
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1 mark

Write down the formula that links Var left parenthesis X right parenthesis comma space straight E left parenthesis X right parenthesis space and straight E left parenthesis X squared right parenthesis.

8d
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1 mark

Hence show that Var left parenthesis X right parenthesis equals 299 over 144.

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9a
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1 mark

The discrete random variable X has the probability function

P open parentheses X equals x close parentheses equals open curly brackets table row cell 1 fourth end cell cell x equals 0 end cell row cell 1 over 8 end cell cell x equals 1 comma space 2 end cell row cell 5 over 16 end cell cell x equals 3 end cell row p cell x equals 4 end cell row 0 otherwise end table close

Briefly explain how you can deduce that p equals 3 over 16.

9b
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2 marks

Find straight E left parenthesis X right parenthesis.

9c
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2 marks

Show that straight E left parenthesis X squared right parenthesis equals 103 over 16.

9d
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2 marks

Hence find Var left parenthesis X right parenthesis.

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10a
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1 mark

The discrete random variable X has the probability distribution shown in the following table:

bold italic x

1

2

3

4

5

bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 1 fifth 1 over 10 p p q

Use the fact that the sum of all probabilities equals 1 to show that space 2 p plus q equals 7 over 10.

10b
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2 marks

Given that straight E open parentheses straight X close parentheses equals 33 over 10, use the formula space straight E left parenthesis X right parenthesis equals sum x p spaceto show that space 7 p plus 5 q equals 29 over 10.

10c
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2 marks

Hence simultaneously solve the equations in part (a) and part (b) to find the values of p and q.

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11
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6 marks

X is a random variable such that straight E left parenthesis X right parenthesis equals 5 spaceand Var left parenthesis X right parenthesis equals 3.

Using the formulaespace space straight E left parenthesis a X plus b right parenthesis equals a space straight E left parenthesis X right parenthesis plus b spaceand Var left parenthesis a X plus b right parenthesis equals a squared Var left parenthesis X right parenthesis, find the mean and variance of the following random variables:

(i)
4 X plus 1
(ii)
7 X minus 2
(iii)
5 minus X.

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1a
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1 mark

Three biased coins are tossed.

Write down all the possible outcomes when the three coins are tossed.

1b
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3 marks

A random variable, X, is defined as the number of heads when the three coins are tossed minus the number of tails.

Given that for each coin the probability of getting heads is  3 over 5,

complete the following probability distribution table for X:

bold italic x        
bold P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis        

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2
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4 marks

The random variable X has the probability function

straight P open parentheses X equals x close parentheses equals open curly brackets table row cell 1 over k end cell cell x equals 1 comma 2 comma 3 comma 4 comma 5 comma 6 space end cell row 0 cell otherwise. end cell end table close

(i)
Write down the value of k.
(ii)
Write down the name of this probability distribution.
(iii)
Find the values of straight E left parenthesis X right parenthesis and Var left parenthesis X right parenthesis.

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3a
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2 marks

A student claims that a random variable X has a probability distribution defined by the following probability mass function:

P open parentheses X equals x close parentheses equals open curly brackets table row cell x squared over 30 end cell cell x equals negative 1 comma 1 comma 3 comma 5 end cell row 0 otherwise end table close

Explain how you know that the student’s function does not describe a probability distribution

3b
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2 marks

Given that the correct probability mass function is of the form

straight P open parentheses X equals x close parentheses equals open curly brackets table row cell x squared over k end cell cell x equals negative 1 comma 1 comma 3 comma 5 end cell row 0 otherwise end table close

where k is a constant,

find the exact value of k.

3c
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2 marks

Find P left parenthesis X greater than 0 right parenthesis.

3d
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1 mark

State, with a reason, whether or not X is a discrete random variable.

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4a
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2 marks

The random variable X has the probability function

straight P open parentheses X equals x close parentheses equals open curly brackets table row cell 0.21 end cell cell x equals 0 comma 1 end cell row cell k x end cell cell x equals 3 comma 6 end cell row cell 0.11 end cell cell x equals 10 comma 15 end cell row 0 otherwise end table close

Find the value of k.

4b
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2 marks

Construct a table giving the probability distribution of X.

4c
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1 mark

Find straight P left parenthesis 3 less than X less or equal than 14 right parenthesis.

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5a
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1 mark

A discrete random variable X has the probability distribution shown in the following table:

bold italic x  negative 1  1  2
bold P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 5 over 12 p 1 fourth

Find the value of p.

5b
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5 marks

X is sampled twice such that the results of the two experiments are independent of each other, and the outcomes of the two experiments are recorded.  A new random variable, Y, is defined as the sum of the two outcomes.

Complete the following probability distribution table for Y:

bold italic y negative 2 0 1 2 3 4
bold P bold left parenthesis bold italic Y bold equals bold italic y bold right parenthesis            
5c
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4 marks

Find:

(i)
P left parenthesis Y not equal to 0 right parenthesis
(ii)
P left parenthesis Y greater than 1 right parenthesis
(iii)
P left parenthesis negative 2 less than Y less than 2 right parenthesis
(iv)
P left parenthesis Y less than 0 space space or space space Y greater or equal than 2 right parenthesis

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6a
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4 marks

Leonidas is playing a game with a fair six-sided dice on which the faces are numbered 1 to 6. He rolls the dice until either a ‘6’ appears or he has rolled the dice four times. The random variable X is defined as the number of times that the dice is rolled.

Write down the probability distribution of X in table form.

6b
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2 marks

Complete the following cumulative probability function table for X:

bold italic x

1

2

3

4

bold P bold left parenthesis bold italic X bold less or equal than bold italic x bold right parenthesis        
6c
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2 marks

Find the probability that X is

(i)
at most 3
(ii)
at least 3.

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7a
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1 mark

The discrete random variable X has the probability distribution shown in the following table:

bold italic x negative 2 0 2 4 6
bold P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis p 2 over 15 1 fourth 2 over 15 p

Without working out the value of p, explain why space straight E left parenthesis X right parenthesis equals 2.

7b
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1 mark

Find the value of p.

7c
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2 marks

Find Var left parenthesis X right parenthesis.

7d
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2 marks

The outcome of a random variable Y is double the outcome of X.

Complete the probability distribution for Y below:

bold italic y negative 4 0 4 8  
bold P bold left parenthesis bold italic Y bold equals bold italic y bold right parenthesis   2 over 15      
7e
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2 marks

Find straight P left parenthesis Y greater than X right parenthesis.

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8a
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5 marks

The discrete random variable X has the probability distribution shown in the following table:

bold italic x 0  1  2  3  4
bold P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis p p 0.2 0.1 q

It is given that space E left parenthesis X right parenthesis equals 2.45.

Find the values of p and q.

8b
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2 marks

Find Var left parenthesis X right parenthesis.

8c
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2 marks

Find P left parenthesis X less than E left parenthesis X right parenthesis right parenthesis.

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9a
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6 marks

A discrete random variable, X, can take the values 1, 3, 5 or 7 and it has the cumulative distribution function straight F open parentheses x close parentheses given in the table.

x

1

3

5

7

straight F open parentheses x close parentheses

0.5

0.65

0.9

1

Find the value of:

(i)
P left parenthesis X equals 3 right parenthesis
(ii)
P left parenthesis 3 X plus 3 greater than X plus 9 right parenthesis
(iii)
E left parenthesis X right parenthesis
(iv)
text Var end text left parenthesis X right parenthesis.
9b
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5 marks

Find the value of:

(i)
E open parentheses X over 2 plus 7 close parentheses

(ii)
Var open parentheses fraction numerator 2 minus straight x over denominator 5 end fraction close parentheses

(iii)
E left parenthesis 3 X squared minus 1 right parenthesis.

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1a
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1 mark

Three biased coins are tossed.

Write down all the possible outcomes when the three coins are tossed.

1b
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3 marks

A random variable, X, is defined as the number of heads when the three coins are tossed.

Given that for each coin the probability of getting heads is  2 over 3,

complete the following probability distribution table for X:

bold italic x

0

1

2

3

bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis        

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2
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3 marks

The random variable X has the probability function

P open parentheses X equals x close parentheses equals open curly brackets table attributes columnalign left columnspacing 1.4ex end attributes row cell 1 over k end cell cell x equals 1 comma 2 comma 3 comma 4 comma 5 end cell row 0 otherwise end table close

(i)
Show that k equals 5.
(ii)
Write down the name of this probability distribution.

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3a
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2 marks

The random variable X has the probability function

P open parentheses X equals x close parentheses equals open curly brackets table attributes columnalign left columnspacing 1.4ex end attributes row cell k x end cell cell x equals 1 comma 3 comma 5 comma 7 end cell row 0 otherwise end table close

Find the value of k.

3b
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2 marks

Find P left parenthesis X greater than 3 right parenthesis.

3c
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1 mark

State, with a reason, whether or not X is a discrete random variable.

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4a
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2 marks

The random variable X has the probability function

P open parentheses X equals x close parentheses equals open curly brackets table row cell 0.23 end cell cell x equals negative 1 comma space 4 end cell row k cell x equals 0 comma space 2 end cell row cell 0.13 end cell cell x equals 1 comma 3 end cell row 0 otherwise end table close

Find the value of k.

4b
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2 marks

Construct a table giving the probability distribution of X.

4c
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1 mark

Find P left parenthesis 0 less or equal than X less than 3 right parenthesis.

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5
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5 marks

A discrete random variable X has the probability distribution shown in the following table:

bold italic x  0 1 2 3 4
P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 5 over 24 1 third 1 fourth 1 over 12 1 over 8

Find:

(i)
P left parenthesis X less than 4 right parenthesis
(ii)
F left parenthesis 2.5 right parenthesis
(iii)
P left parenthesis X greater than 1 right parenthesis
(iv)
P left parenthesis 2 less than X less or equal than 4 right parenthesis
(v)
P left parenthesis 0 less than X less than 4 right parenthesis

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6a
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1 mark

Leonardo has constructed a biased spinner with six sectors labelled 0 comma space 1 comma space 1 comma space 2 comma space 3 spaceand 5. The probability of the spinner landing on each of the six sectors is shown in the following table:

number on sector

0

1

1

2

3

5

probability 6 over 20 p 3 over 20 5 over 20 3 over 20 1 over 20

Find the value of p.

6b
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3 marks

Leonardo is playing a game with his biased spinner.  The score for the game, X, is the number which the spinner lands on after being spun.

Leonardo plays the game twice and adds the two scores together. Find the probability that Leonardo has a total score of 5.

6c
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2 marks

Complete the following cumulative probability function table for X:

Score bold italic x

0

1

2

3

5

bold italic P bold left parenthesis bold italic X bold less or equal than bold italic x bold right parenthesis 6 over 20       1
6d
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2 marks

Find the probability that X is

(i)
no more than 1
(ii)
at least 3.

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7a
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1 mark

The discrete random variable X has the probability distribution shown in the following table:

bold italic x

2

3

5

7

11

bold P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis 1 fourth 1 third p 1 over 6 1 over 12

Find the value of p.

7b
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2 marks

Find straight E left parenthesis X right parenthesis.

7c
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2 marks

Find Var left parenthesis X right parenthesis.

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8a
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2 marks

The discrete random variable X has the probability distribution shown in the following table:

bold italic x negative 2 0 2 4 6
bold P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis p 1 half q 1 over 15 q

It is given that straight E left parenthesis X right parenthesis equals 0.

Show that space p minus 4 q equals 2 over 15.

8b
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1 mark

Write down a second equation involving p and q.

8c
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2 marks

Hence find the values of p and q.

8d
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2 marks

Find Var left parenthesis X right parenthesis.

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9
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4 marks

The random variable X has mean mu and variance sigma squared. Given that

straight E left parenthesis 2 X plus 7 right parenthesis equals 16
Var left parenthesis 2 X plus 7 right parenthesis equals 5 comma

find the value of mu and the value of sigma squared.

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1a
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1 mark

Two biased coins are tossed and a fair spinner with three sectors numbered 1 to 3 is spun.

Write down all the possible outcomes when the two coins are tossed and the spinner is spun.

1b
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5 marks

A random variable, X, is defined as the number of heads when the two coins are tossed multiplied by the number the spinner lands on when it is spun.

For each coin the probability of getting heads is  1 third.

Complete the following probability distribution table for X:

bold italic x

0

1

2

3

   
bold P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis            

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2a
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2 marks

A student claims that a random variable X has a probability distribution defined by the following probability mass function:

P open parentheses X equals x close parentheses equals open curly brackets table row cell fraction numerator 1 over denominator 3 x squared end fraction end cell cell x equals negative 3 comma space minus 1 end cell row cell fraction numerator 1 over denominator 3 x cubed end fraction end cell cell x equals 1 comma space 3 end cell row 0 otherwise end table close

Explain how you know that the student’s function does not describe a probability distribution.

2b
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2 marks

Given that the correct probability mass function is of the form

P open parentheses X equals x close parentheses equals open curly brackets table row cell k over x squared end cell cell x equals negative 3 comma space minus 1 end cell row cell k over x cubed end cell cell x equals 1 comma space 3 end cell row 0 otherwise end table close

where k is a constant,

Find the exact value of k.

2c
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2 marks

Find P left parenthesis X less than 2 right parenthesis.

2d
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1 mark

State, with a reason, whether or not X is a discrete random variable.

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3a
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4 marks

The random variable X has the probability function

P left parenthesis X equals x right parenthesis equals x squared over 495 comma space space space space x equals p comma 2 p comma 3 p comma 4 p comma 5 p

where p greater than 0 is a constant.

Construct a table giving the probability distribution of X.

3b
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4 marks

Find:

(i)
the mean, mu,
(ii)
the standard deviation, sigma,

of X.

3c
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2 marks

Find P left parenthesis mu minus sigma less than X less than mu plus sigma right parenthesis.

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4
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6 marks

The independent random variables X and Y have probability distributions

P left parenthesis X equals x right parenthesis equals p comma space space space space space space x equals 1 comma 2 comma 3 comma 5 comma 8 comma 11
P left parenthesis Y equals y right parenthesis equals begin inline style q over y end style comma space space space space space space y equals 1 comma 3 comma 6

where p and q are constants.

Find P left parenthesis X greater than Y right parenthesis.

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5a
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6 marks

Leofranc is playing a gambling game with a fair six-sided dice on which the faces are numbered 1 to 6.  He must pay £2 to play the game.  He then chooses a ‘lucky number’ between 1 and 6, and rolls the dice until either his lucky number appears or he has rolled the dice four times.  If his lucky number appears on the first roll, he receives £5 back.  If his lucky number appears on the second, third or fourth rolls, he receives £3, £2 or £1 back respectively.  If his lucky number has not appeared by the fourth roll, then the game is over and he receives nothing back.

The random variable W is defined to be Leofranc’s profit (i.e., the amount of money he receives back minus the cost of playing the game) when he plays the game one time.  Note that a negative profit indicates that Leofranc has lost money on the game.

Draw up the probability distribution table for W.

5b
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3 marks

Find the probability that when playing the game one time Leofranc

(i)
wins money
(ii)
loses money
(iii)
breaks even (i.e. does not win or lose money).
5c
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2 marks

Find the expected profit after one game.

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6a
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1 mark

The discrete random variable X has the probability distribution shown in the following table:

bold italic x  negative 3  negative 2  -1  0  1
bold P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis  p  q  0.1  q  p

Write down the value of space straight E left parenthesis X right parenthesis.

6b
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1 mark

It is given that straight E left parenthesis X squared right parenthesis equals 3.4.

Find Var left parenthesis X right parenthesis.

6c
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5 marks

Find the values for p and q.

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7a
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1 mark

A spinner has three sectors labelled 0, 1 and 2. Let X be the random variable denoting the number the spinner lands on when spun. The probability distribution table for X is shown below:

bold italic x  0  1

2

bold italic P bold left parenthesis bold italic X bold equals bold italic x bold right parenthesis a b c

It is given that space E left parenthesis X right parenthesis equals 1.1 spaceand space Var left parenthesis X right parenthesis equals 0.89.

Write down the value of E left parenthesis X squared right parenthesis.

7b
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4 marks

Find the values of a comma space b and c.

7c
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4 marks

Susie spins the spinner twice and adds together the two numbers to calculate her score, S. Tommy spins the spinner once and doubles the number to calculate his score, T. Each spin of the spinner is independent of all other spins.

Draw up the probability distribution table for:

(i)
S comma
(ii)
T.
7d
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1 mark

Which player is most likely to get a score that is bigger than 2?

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8
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7 marks

The probability of rolling a 6 on a biased die is p.  In a game, this die is rolled twice and then the player multiplies the number of times the die lands on a 6 by 50 and then adds 5 to calculate the score.

(i)
Given that the mean score is 15, draw up a probability distribution table for the number of times the die lands on a 6 when rolled twice.
(ii)
Find the variance of the scores.

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9
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4 marks

All the odd numbers from 1 to 99 inclusive are written on individual pieces of paper and placed inside a bag. A piece of paper is picked at random and the odd number Y is recorded.

Find the expectation and standard deviation of Y.

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10a
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5 marks

A biased four-sided dice is rolled and the number that it lands on is denoted  which has probability distribution shown below.

x negative 2 negative 1 1 half 2
P open parentheses X equals x close parentheses a b c c

The cumulative distribution function of X is given by:

x negative 2 negative 1 1 half 2
straight F open parentheses x close parentheses 1 over 7 2 over 5 d e

Find the values of a comma b comma c comma d comma spaceand e.

10b
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2 marks

Saskia and Tamara place a game by rolling the dice. Saskia’s score is the number the dice lands on and Tamara’s score is the reciprocal of that number.

Find the probability that Saskia’s score is bigger than Tamara’s score.

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