DP IB Chemistry: HL

Revision Notes

Syllabus Edition

First teaching 2014

Last exams 2024

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14.2.2 Ozone Revisited

Ozone Revisited

  • We have seen previously that ozone is a molecule with two resonance structures leading to a resonance hybrid

Lewis structures for ozone, downloadable IB Chemistry revision notes

The two Lewis resonance structures for ozone

  • The central oxygen atom has three electron domains and a lone pair, so the domain geometry is triangular planar and the molecular geometry is bent linear
  • The presence of the lone pair repels the bonding pairs more strongly so the bond angle is reduced to 117o

Molecular-structure-of-ozone, downloadable IB Chemistry revision notes

The molecular structure of ozone

  • The bond order for each bond in ozone is

bond order in O3 = total number of O3 bonding pairs ÷ total number of positions = 3 ÷ 2 = 1.5

  • This gives a polar molecule with bonds that are weaker than the double bond in oxygen molecules

Oxygen and ozone, downloadable IB Chemistry revision notes

The structure of oxygen and ozone

  • You would expect O-O bonds to be non-polar as the atoms have the same electronegativity; this is correct, but overall the molecule is polar due to the uneven distribution of electron cloud charge
  • The formal charge on the Lewis structures show that the electrons are unevenly distributed

FC= (number of valence electrons) – ½(number of bonding electrons) – (number of non-bonding electrons)

FC (oxygen A) = (6) - ½(2) - (6) = -1

FC (oxygen B) = (6) - ½(6) - (2) = +1

FC (oxygen C) = (6) - ½(4) - (4) = 0

Formal charges of the oxygen in ozone, downloadable IB Chemistry revision notes

Formal charges on the oxygens in ozone

Catalytic Depletion

  • The bonding and structure of ozone is key to understanding how the catalytic depletion of ozone occurs in the stratosphere
  •  High energy UV radiation in the stratosphere breaks the oxygen-oxygen double bond creating oxygen atoms

O2 (g) → O⋅ (g) + O⋅ (g) ∆H +ve, UV light, λ < 242 nm

  • These oxygen atoms have unpaired electrons - they are known as free radicals
  • The free radicals are highly reactive and quickly attack oxygen molecules forming ozone in an exothermic reaction, which raises the temperature of the stratosphere

   OZONE FORMATION         O⋅ (g) + O2 (g) → O3 (g) ∆H – ve

  • Ozone requires less energy to break than oxygen
    • It produces an oxygen molecule and an oxygen free radical:

   OZONE DEPLETION          O3 (g) → O⋅ (g) + O2 (g) ∆H +ve, UV light, λ< 330 nm

  • The radical reacts with another ozone molecule making two molecules of oxygen in an exothermic reaction

   OZONE DEPLETION         O3 (g) + O⋅ (g) → 2O2 (g) ∆H – ve

  • The temperature in the stratosphere is maintained by the balance of ozone formation and ozone depletion in a process known as the Chapman Cycle
  • It is not a closed system as matter and energy flow in and out, but it is what is called a steady state

The Chapman cycle, downloadable IB Chemistry revision notes

The Chapman cycle

Catalytic Depletion

  • The two main man made culprits that accelerate the depletion of ozone are nitrogen oxides and CFCs
  • Nitrogen monoxide, NO, is produced from the high temperatures inside internal combustion engines
  • If you count the valence electrons in nitrogen monoxide (5 + 6 =11), the odd number tells you it is a free radical as it has an unpaired electron
  • The nitrogen monoxide reacts with ozone forming oxygen and a nitrogen dioxide radical

NO⋅ (g) + O3 (g) → NO2⋅ (g) + O2 (g)

  • The nitrogen dioxide produced is also a free radical (it has 5 + 6 + 6= 17 electrons) and you can show the second step where it reacts with another molecule of ozone, producing oxygen and regenerating the NO⋅ radical:

NO2⋅ (g) + O3 (g) → NO⋅ (g) + 2O2 (g)

  • An alternative to the second step shows the NO2⋅ reacting with an oxygen radical to produce the same products but in a different stoichiometry

NO2⋅ (g) + O⋅ (g) → NO⋅ (g) + O2 (g)

  • The nitrogen monoxide is regenerated so it has a catalytic role in the process
  • Combining the two equations and cancelling out the NO⋅ and NO2⋅ and you arrive at the overall depletion of ozone

O3 (g) + O⋅ (g) → 2O2 (g)

  • A similar process happens with CFCs
  • The C-Cl bond in the CFCs is weaker than the C-F bond and breaks more easily in the presence of UV light creating chlorine radicals

CCl2F2 (g) + UV → CClF2⋅ (g) + Cl⋅ (g)

  • The chlorine radicals attack ozone and are regenerated at the end of the cycle

Cl⋅ (g) + O3 (g) → ClO⋅ (g) + O2 (g)

ClO⋅ (g) + O⋅ (g) → Cl⋅ (g) + O2 (g)

  • Once again a molecule of ozone has been destroyed by a catalytic free radical
  • The net effect of these reactions is that these pollutants have created an imbalance in the natural ozone cycle leading to an overall depletion in stratospheric ozone
  • CFCs are greatly damaging to stratospheric ozone and have been largely replaced by safer alternatives following the 1985 Montreal Protocol
  • The depletion of ozone has allowed greater amounts of harmful UV light to reach the surface of the Earth
  • UV light has been linked to greater incidence of skin cancer and cataracts as well as the destruction of phytoplankton and reduced plant growth

Exam Tip

There are different conventions about showing radicals. Sometimes the dot is shown above the symbol of the element, sometimes to the left of the species and sometimes to the right. 
In this course, radical dots are often ignored in exam mark schemes about ozone depletion, so you wouldn't be penalised if you omitted them or put them in different places. However, where the symbol for a radical is specified in the syllabus is in the halogenation of alkanes so you should include them there. The syllabus just states that radicals must be represented by a single dot.

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