Syllabus Edition

First teaching 2021

Last exams 2024

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Working with Percentages (CIE IGCSE Maths: Extended)

Revision Note

Test Yourself
Mark

Author

Mark

Expertise

Maths

Percentage Increases & Decreases

How do I increase or decrease by a percentage?

  • Identify “before” & “after” quantities
  • If working in percentages, add to (or subtract from) 100 
    • a percentage increase of 25% is 100 + 25 = 125% of the "before" price
      • Add 25% to the original amount
    • a percentage decrease of 25% is 100 - 25 = 75% of the "before" price
      • Subtract 25% from the original amount
  • A multiplier, p, is the decimal equivalent of a percentage increase or decrease
    • The multiplier for a percentage increase of 25% is p = 1 + 0.25 = 1.25
      • Multiply the original amount by the multiplier, 1.25, to find the new amount
    • The multiplier for a percentage decrease of 25% is p = 1 - 0.25 = 0.75
      • Multiply the original amount by the multiplier, 0.75, to find the new amount
  • The amount "before" and the amount "after" a percentage change are related by the formula "before" × p = "after"
    • where p is the multiplier

How do I find a percentage change?

  • Method 1: rearrange the formula "before" × p = "after" to make p (the multiplier) the subject
    • p after over before 
    • Calculate p and interpret its value
      • p = 1.02 shows a percentage increase of 2%
      • p = 0.97 shows a percentage decrease of 3%
  • Method 2: Use the formula that the "percentage change" is  fraction numerator after space minus space before over denominator before end fraction cross times 100
    • A positive value is a percentage increase 
    • A negative value is a percentage decrease
  • The same formula can be used for percentage profit (or loss)
    • the "cost" price is the price a shop has to pay to buy something and the "selling" price is how much the shop sells it for


Percentage space profit space left parenthesis or space loss right parenthesis space equals space fraction numerator selling space price space minus space cost space price over denominator cost space price end fraction cross times 100

  • You can identify whether there is a profit or loss 
    • cost price < selling price = profit (formula gives a positive value)
    • cost price > selling price = loss (formula gives a negative value)

Worked example

(a) Increase £200 by 18%

Write 18% as a percentage (by dividing by 100)
 

18 ÷ 100 = 0.18
 

Find the decimal equivalent of an 18% increase (by adding 1 to 0.18)
 

1 + 0.18 = 1.18
 

Multiply £200 by 1.18
 

200 × 1.18

£236

(b) Decrease 500 kg by 23%

Write 23% as a percentage (by dividing by 100)
 

23 ÷ 100 = 0.23
 

Find the decimal equivalent of a 23% decrease (by subtracting 0.23 from 1)
 

1 - 0.23 = 0.77
 

Multiply 500 by 0.77
 

500 × 0.77

385 kg

(c) The number of students in a school goes from 250 to 310. Describe this as a percentage change.

Use the formula "percentage change" = fraction numerator after space minus space before over denominator before end fraction cross times 100
 

fraction numerator 310 space minus space 250 over denominator 250 end fraction cross times 100 space equals space 24 percent sign
 

This is a positive value so is a "percentage increase"
 

A percentage increase of 24%

Reverse Percentages

What is a reverse percentage?

  • A reverse percentage question is one where we are given the value after a percentage increase or decrease and asked to find the value before the change

How to do reverse percentage questions

  • You should think about the "before" quantity (even though it is not given in the question)
  • Find the percentage change as a multiplier, (the decimal equivalent of a percentage change)
    • a percentage increase of 4% means p = 1 + 0.04 = 1.04
    • a percentage decrease of 5% means p = 1 - 0.05 = 0.95
  • Use "before" × p = "after" to write an equation
    • get the order right: the change happens to the "before", not to the "after"
  • Rearrange the equation to find the "before" quantity...
    • ...by dividing the "after" quantity by the multiplier, p

Exam Tip

  • A reverse percentage question involves dividing by the multiplier, p, not multiplying by it
  • To spot a reverse percentage question, see if you are being asked to find a quantity in the past, e.g.
    Find the "old" / "original" / "before" amount ...

Worked example

Jennie is now paid £31 500 per year, after having a pay rise of 5%. How much was Jennie paid before the pay rise?

The "before" amount is unknown and the "after" amount is 31 500
Find the multiplier, p (by writing 5% as a decimal and adding it to 1)
 

p = 1 + 0.05 = 1.05
 

Use "before" × p = "after" to write an equation
 

"before" × 1.05 = 31 500
 

Find "before" (by dividing both sides by 1.05)
 

"before" = fraction numerator 31 space 500 over denominator 1.05 end fraction = 30 000
 

She was paid £30 000 before the pay rise

Jennie was paid £30 000 before the pay rise

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Mark

Author: Mark

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.