CIE AS Chemistry

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2.3.3 Reactions of the Halide Ions

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Halide Ions: Reducing Agents

  • Halide ions can also act as reducing agents and donate electrons to another atom
  • The halide ions themselves get oxidised and lose electrons
  • The reducing power of the halide ions increases going down the group
  • This trend can be explained by looking at the ionic radii of the halides’ ions

 Group 17 - Electron Arrangement in Halide Ions, downloadable AS & A Level Chemistry revision notes

The diagram shows that going down the group the ionic radii of the halogens increases

  • Going down the group, the halide ions become larger
  • The outermost electrons get further away from the nucleus
  • The outermost electrons also experience more shielding by inner electrons
  • As a result of this, the outermost electrons are held less tightly to the positively charged nucleus
  • Therefore, the halide ions lose electrons more easily going down the group and their reducing power increases

 

Group 17 - Reducing Power Trend, downloadable AS & A Level Chemistry revision notes

The reducing power of the halide ions increases going down the group

Exam Tip

The ionic radius is a measure of the size of an atom’s ion.

Reactions of Halide Ions

Silver ions & ammonia

  • Halide ions can be identified in an unknown solution by dissolving the solution in nitric acid and then adding a silver nitrate solution followed by ammonia solution
  • The halide ions will react with the silver nitrate solution as follows:

AgNO3(aq) + X-(aq) → AgX(s) + NO3-(aq)

(general equation)

Ag+(aq) + X-(aq) → AgX(s)

(ionic equation)
    • X- is the halide ion in both equations

  • If the unknown solution contains halide ions, then a precipitate of the silver halide will be formed (AgX)

Group 17 - Halide Test, downloadable AS & A Level Chemistry revision notes

A silver halide precipitate is formed upon addition of silver nitrate solution to halide ion solution

  • Dilute followed by concentrated ammonia is added to the silver halide solution to identify the halide ion
  • If the precipitate dissolves in dilute ammonia the unknown halide is chloride
  • If the precipitate does not dissolve in dilute but in concentrated ammonia the unknown halide is bromide
  • If the precipitate does not dissolve in dilute nor concentrated ammonia the unknown halide is iodide

Group 17 - Dissolving of Silver Halide, downloadable AS & A Level Chemistry revision notes

Silver chloride and silver bromide precipitates dissolve on addition of ammonia solution whereas silver iodide doesn’t

Reaction of halide ions with silver nitrate & ammonia solutions table

Group 17 - Table 1_Reactions of Halide Ions, downloadable AS & A Level Chemistry revision notes

Concentrated sulfuric acid

  • Chloride, bromide and iodide ions react with concentrated sulfuric acid to produce toxic gases
  • These reactions should therefore be carried out in a fume cupboard
  • The general reaction of the halide ions with concentrated sulfuric acid is:

H2SO4(l) + X-(aq) → HX(g) + HSO4-(aq)

(general equation)

Where X- is the halide ion

Reaction of chloride ions with concentrated sulfuric Acid

  • Concentrated sulfuric acid is dropwise added to sodium chloride crystals to produce hydrogen chloride gas

 Group 17 - Apparatus Set Up, downloadable AS & A Level Chemistry revision notes

Apparatus set up for the reaction of sodium chloride with concentrated sulfuric acid

 
  • The reaction that takes place is:

H2SO4(l) + NaCl(s) → HCl(g) + NaHSO4(s)      

  • The HCl gas produces is seen as white fumes

Reaction of bromide ions with concentrated sulfuric acid

  • The thermal stability of the hydrogen halides decreases down the group
  • The reaction of sodium bromide and concentrated sulfuric acid is:

H2SO4(l) + NaBr(s) → HBr(g) + NaHSO4(s)     

  • The concentrated sulfuric acid oxidises HBr which decomposes into bromine and hydrogen gas and sulfuric acid itself is reduced to sulfur dioxide gas:

2HBr(g) + H2SO4(l) → Br2(g) + SO2(g) + 2H2O(l)

  • The bromine is seen as a reddish-brown gas

Reaction of iodide ions with concentrated sulfuric acid

  • The reaction of sodium iodide and concentrated sulfuric acid is:

H2SO4 (l) + NaI (s) → HI (g) + NaHSO4 (s)          

  • Hydrogen iodide decomposes the easiest
  • Sulfuric acid oxidises the hydrogen iodide to several extents:
  • The concentrated sulfuric acid oxidises HI and is itself reduced to sulfur dioxide gas:

2HI (g) + H2SO4 (l) → I2 (g) + SO2 (g) + 2H2O (l)

  • Iodine is seen as a violet/purple vapour
  • The concentrated sulfuric acid oxidises HI and is itself reduced to sulfur:

6HI (g) + H2SO4 (l) → 3I2 (g) + S (s) + 4H2O (l)

  • Sulfur is seen as a yellow solid
  • The concentrated sulfuric acid oxidises HI and is itself reduced to hydrogen sulfide:

8HI (g) + H2SO4 (l) → 4I2 (g) + H2S (s) + 4H2O (l)

  • Hydrogen sulfide has a strong smell of bad eggs

Halide ion reactions with concentrated sulfuric acid table

Group 17 Table 2_Reactions of Halide Ions, downloadable AS & A Level Chemistry revision notes

Exam Tip

It gets easier to oxidise the hydrogen halides as you descend Group 17: the halides become stronger reducing agents

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