AQA AS Chemistry

Revision Notes

1.2.6 Hydrated Salts

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Water of Crystallisation

  • Water of crystallisation is when some compounds can form crystals which have water as part of their structure
  • A compound that contains water of crystallisation is called a hydrated compound
  • The water of crystallisation is separated from the main formula by a dot when writing the chemical formula of hydrated compounds
    • E.g. hydrated copper(II) sulfate is CuSO45H2O

  • A compound which doesn’t contain water of crystallisation is called an anhydrous compound
    • E.g. anhydrous copper(II) sulfate is CuSO4

  • A compound can be hydrated to different degrees
    • E.g. cobalt(II) chloride can be hydrated by six or two water molecules
    • CoCl2 6H2O or CoCl2 2H2O

  • The conversion of anhydrous compounds to hydrated compounds is reversible by heating the hydrated salt:
Hydrated:        CuSO4•5H2OCuSO4 + 5H2O        :Anhydrous

  • The degree of hydration can be calculated from experimental results:
    • The mass of the hydrated salt must be measured before heating
    • The salt is then heated until it reaches a constant mass
    • The two mass values can be used to calculate the number of moles of water in the hydrated salt - known as the water of crystallisation

Worked example

Calculating water of crystallisation

10.0 g of hydrated copper sulfate are heated to a constant mass of 5.59 g. Calculate the formula of the original hydrated copper sulfate.

(Mr data: CuSO4 = 159.6, H2O = 18.0) 

Answer

List the components 

CuSO4

H2O

Note the mass of each component

5.59 g

10 - 5.59 = 4.41 g

Divide the component mass by the components Mr

fraction numerator 5.59 over denominator 159.6 end fraction = 0.035

fraction numerator 4.41 over denominator 18.0 end fraction = 0.245

Divide by the lowest figure to obtain the ratio

fraction numerator 0.035 over denominator 0.035 end fraction= 1

fraction numerator 0.245 over denominator 0.035 end fraction= 7

Hydrated salt formula

CuSO4•7H2O

 

Exam Tip

A water of crystallisation calculation can be completed in a similar fashion to an empirical formula calculation
  • Instead of elements, you start with the salt and water
  • Instead of dividing by atomic masses, you divide by molecular / formula masses
  • The rest of the calculation works the same way as the empirical formula calculation

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