CIE A Level Physics

Revision Notes

Syllabus Edition

First teaching 2020

Last exams 2024

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16.1.2 Work Done by a Gas

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Work Done by a Gas

  • When a gas expands, it does work on its surroundings by exerting pressure on the walls of the container it's in
  • This is important, for example, in a steam engine where expanding steam pushes a piston to turn the engine
  • The work done when a volume of gas changes at constant pressure is defined as:

W = pΔV

  • Where:
    • W = work done (J)
    • p = external pressure (Pa)
    • V = volume of gas (m3)

 
  • For a gas inside a cylinder enclosed by a moveable piston, the force exerted by the gas pushes the piston outwards
  • Therefore, the gas does work on the piston

Work done by gas, downloadable AS & A Level Physics revision notes

The gas expansion pushes the piston a distance s

Derivation

  • The volume of gas is at constant pressure. This means the force F exerted by the gas on the piston is equal to :

F = p × A

  • Where:
    • p = pressure of the gas (Pa)
    • A = cross-sectional area of the cylinder (m2)

  • The definition of work done is:

W = F × s

  • Where:
    • F = force (N)
    • s = displacement in the direction of force (m)

  • The displacement of the gas d multiplied by the cross-sectional area A is the increase in volume ΔV of the gas:

W = p × A × s

  • This gives the equation for the work done when the volume of a gas changes at constant pressure:

W = pΔV

  • Where:
    • ΔV = increase in the volume of the gas in the piston when expanding (m3)

 
  • This is assuming that the surrounding pressure p does not change as the gas expands
  • This will be true if the gas is expanding against the pressure of the atmosphere, which changes very slowly
  • When the gas expands (V increases), work is done by the gas
  • When the gas is compressed (V decreases), work is done on the gas

Worked example

When a balloon is inflated, its rubber walls push against the air around it.Calculate the work done when the balloon is blown up from 0.015 m3 to 0.030 m3.Atmospheric pressure = 1.0 × 105 Pa.

Step 1: Write down the equation for the work done by a gas

W = pΔV

Step 2: Substitute in values

                        ΔV = final volume − initial volume = 0.030 − 0.015 = 0.015 m3

W = (1.0 × 105) × 0.015 = 1500 J

Exam Tip

The pressure p in the work done by a gas equation is not the pressure of the gas but the pressure of the surroundings. This is because when a gas expands, it does work on the surroundings.

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