Specification Point 1.35 (Paper 2C Only):
Understand how to carry out calculations involving Gas Volumes and the Molar Volume of a Gas ( 24 dm3 and 24 000 cm3 at room temperature and pressure (rtp))
Volume of one mole of any gas is molar volume. It is 24dm3 or 24000 cm3 at R.T.P.
Calculations Involving Gases
Volume of Gas ( dm3 ) = Amount of Gas ( mol ) x 24
Volume of Gas ( cm3 ) = Amount of Gas ( mol ) x 24000
|Name of gas||Amount of gas||Volume of gas|
|Hydrogen||3 mol||( 3 x 24 ) = 72 dm3|
|Carbon Dioxide||0.25 mol||( 0.25 x 24 ) = 6 dm3|
|Oxygen||5.4 mol||( 5.4 x 24000 ) = 129600 cm3|
|Ammonia||0.02 mol||( 0.02 x 24 ) = 0.48 dm3|
|Name of gas||Volume of gas||Moles of gas|
|Methane||225.6 dm3||( 225.6 ÷ 24 ) = 9.4 mol|
|Carbon Monoxide||7.2 dm3||( 7.2 ÷ 24 ) = 0.3 mol|
|Sulfur Dioxide||960 dm3||( 960 ÷ 24 ) = 40 mol|
|Oxygen||1200 cm3||( 1200 ÷ 24000 ) = 0.05 mol|
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Jamie got a First class degree in Chemistry from Oxford University before going on to teach chemistry full time as a professional tutor. He’s put together these handy revision notes to match the Edexcel IGCSE Chemistry specification so you can learn exactly what you need to know for your exams.
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