Reaction Rates Using Moles (AQA GCSE Chemistry)

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Reaction Rates Using Moles

Higher Tier Only

  • We have seen that the rate of reaction is a measure of a changing property per unit time
  • This will frequently be expressed in units of g/s or cm3/s for a change in mass or volume, respectively
  • However, it is often more useful to be able to express rate of reaction in terms of moles, in which case the unit will be mol/s
  • There is no direct way to measure moles, so first it is necessary to calculate the rate using the rate formula triangle:

Rate of Reaction - Formula Triangle, IGCSE & GCSE Chemistry revision notes

The rate formula triangle

  • After calculating the rate of reaction it can then be converted into mol/s
  • If you are working in mass per unit time then the process is:

mass per unit time ÷ molar mass of the substance = moles per unit time

  • If you are working in volume per unit time then you have to use the molar gas volume:

volume per unit time ÷ molar gas volume (24 000 cm3/mol ) = moles per unit time

Worked example

Calculate the rates of reaction, in mol/s, in the following experiments:

  1. 20.0 g of marble chips were added to a flask containing 100 cm3 of 2.0 mol/dm3 hydrochloric acid. The flask was placed on a balance and the mass was measured at the start of the reaction. After 2.5 minutes the mass was found to have decreased by 6.0 g.

  2. A piece of magnesium ribbon, 2 cm in length, was added to a flask containing 50.0 cm3 of 1.50 mol/dm3 sulfuric acid. The flask was connected to a gas syringe and the volume of gas measured every minute. 15 cm3 of gas had been collected after 6 minutes.

Answer 1:

  • Step 1: Convert the time into seconds

2.5 x 60 = 150 s

  • Step 2: Calculate the rate of reaction in g/s

6.0 g ÷ 150 s = 0.04 g/s

  • Step 3: Convert to mol/s
    • The loss in mass is due the carbon dioxide gas released
    • The molar mass of carbon dioxide, CO2, is 44.0 g/mol

0.04 g s-1 ÷ 44.0 g/mol = 9.1 x 10-4 mol/s

Answer 2: 

  • Step 1: Convert the time into seconds 

               6.0 x 60 = 360 s

  • Step 2: Calculate the rate of reaction in cm3/s

15 cm3  ÷ 360 s = 0.0417 cm3/s

  • Step 3: Convert to mol/s

0.0417 cm3/s ÷ 24 000 cm3/mol = 1.7 x 10-6 mol/s

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Stewart

Author: Stewart

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.