DP IB Maths: AA HL

Revision Notes

5.9.4 Advanced Applications of Integration

Test Yourself

Area Between Curve & y-axis

What is meant by the area between a curve and the y-axis?

5-9-4-ib-hl-ai-aa-extraaa-fig1-area-yaxis

 

  • The area referred to is the region bounded by
    • the graph of y equals f left parenthesis x right parenthesis
    • the y-axis
    • the horizontal line y equals a
    • the horizontal line y equals b
  • The exact area can be found by evaluating a definite integral
  • The graph of y equals f left parenthesis x right parenthesis could be a straight line
    • using basic shape area formulae may be easier than integration
      • e.g. area of a trapezium: A equals 1 half h open parentheses a plus b close parentheses

How do I find the area between a curve and the y-axis?

  • Use the formula

A equals integral subscript a superscript b open vertical bar x close vertical bar space d x

    • This is given in the formula booklet
    • The function is normally given in the form y equals f left parenthesis x right parenthesis
      • so will need rearranging into the form x equals g left parenthesis y right parenthesis
    • a and b may not be given directly as could involve the x-axis (y equals 0) and/or a root of x equals g left parenthesis y right parenthesis
      • use a GDC to plot the curve, sketch it and highlight the area to help

STEP 1
Identify the limits a and b
Sketch the graph of y equals f left parenthesis x right parenthesis or use a GDC to do so, especially if a and b are not given directly in the question

STEP 2
Rearrange y equals f left parenthesis x right parenthesis into the form x equals g left parenthesis y right parenthesis
This is similar to finding the inverse function f to the power of negative 1 end exponent left parenthesis x right parenthesis

STEP 3
Evaluate the formula to evaluate the integral and find the area required
If using a GDC remember to include the modulus ( | … | ) symbols around x 

  • In trickier problems some (or all) of the area may be ‘negative’
    • this will be any area that is left of the y-axis (negative x-values)
    • |x| makes such areas ‘positive’
      • a GDC will apply ‘|x|’ automatically as long as the | … | are included
      • otherwise, to apply ‘|x|’, split the integral into positive and negative parts; write an integral and evaluate each part separately and add the modulus of each part together to give the total area

Exam Tip

  • Sketch and/or use your GDC to help visualise what the problem looks like

Worked example

Find the area enclosed by the curve with equation y equals 2 plus square root of x plus 4 end root, the y-axis and the horizontal lines with equations y equals 3 and y equals 6.

5-9-4-ib-hl-ai-aa-extraaa-we1-soltn

Volumes of Revolution Around x-axis

What is a volume of revolution around the x-axis?

  • A solid of revolution is formed when an area bounded by a function y equals f left parenthesis x right parenthesis
    (and other boundary equations) is rotated 2 pi radians left parenthesis 360 degree right parenthesis around the x-axis
  • The volume of revolution is the volume of this solid

2dk4S6Oy_6-2-4-cie-fig1-vol-of-rev

  • Be careful – the ’front’ and ‘back’ of this solid are flat
    • they were created from straight (vertical) lines
    • 3D sketches can be misleading

How do I solve problems involving the volume of revolution around x-axis?

  • Use the formula

 V equals pi integral subscript a superscript b y squared space d x

  • This is given in the formula booklet
  • y is a function of x
  • x equals a and x equals b are the equations of the (vertical) lines bounding the area
    • If x equals a and x equals b are not stated in a question, the boundaries could involve the y-axis (x equals 0) and/or a root of y equals f left parenthesis x right parenthesis
    • Use a GDC to plot the curve, sketch it and highlight the area to help
  • Visualising the solid created is helpful
    • Try sketching some functions and their solids of revolution to help

STEP 1
Identify the limits a and b
Sketching the graph of y equals f left parenthesis x right parenthesis or using a GDC to do so is helpful, especially when a and b are not given directly in the question

STEP 2
Square y

STEP 3
Use the formula to evaluate the integral and find the volume of revolution
An answer may be required in exact form

Exam Tip

  • If the given function involves a square root(s), problems can seem quite daunting
    • However, this is often deliberate, as the square root will be squared when applying the Volume of Revolution formula, and should leave the integrand as something more manageable
  • Whether a diagram is given or not, using your GDC to plot the curve, limits, etc (where possible) can help you to visualise and make progress with problems

Worked example

Find the volume of the solid of revolution formed by rotating the region bounded by the graph of y equals square root of 3 x squared plus 2 end root, the coordinate axes and the line x equals 3 by 2 pi radians around the x-axis.  Give your answer as an exact multiple of pi.

5-9-4-ib-hl-ai-aa-extraaa-we2-soltn

Volumes of Revolution Around y-axis

What is a volume of revolution around the y-axis?

  • Very similar to above, this is a solid of revolution which is formed when an area bounded by a function y equals f left parenthesis x right parenthesis (and other boundary equations) is rotated 2 pi radians left parenthesis 360 degree right parenthesis around the y-axis
  • The volume of revolution is the volume of this solid

How do I solve problems involving the volume of revolution around y-axis?

  • Use the formula

V equals straight pi integral subscript a superscript b x squared space d y 

  • This is given in the formula booklet
  • The function is usually given in the form y equals f left parenthesis x right parenthesis
    • so will need rearranging into the form x equals g left parenthesis y right parenthesis
  • a and b may not be given directly as could involve the x-axis (y equals 0) and/or a root of x equals g left parenthesis y right parenthesis
    • Use a GDC to plot the curve, sketch it and highlight the area to help
  • Visualising the solid created is helpful

STEP 1
Identify the limits a and b
Sketching the graph of y equals f left parenthesis x right parenthesis or using a GDC to do so is helpful, especially if a and b are not given directly in the question

STEP 2
Rearrange y equals f left parenthesis x right parenthesis into the form x equals g left parenthesis y right parenthesis
This is similar to finding the inverse function f to the power of negative 1 end exponent left parenthesis x right parenthesis

STEP 3
Square x

STEP 4
Use the formula to evaluate the integral and find the volume of revolution
An answer may be required in exact form

Exam Tip

  • If the given function involves a square root, problems can seem quite daunting
    • This is often deliberate, as the square root will be squared when applying the Volume of Revolution formula and the integrand will then become more manageable
  • Whether a diagram is given or not, using your GDC to plot the curve, limits, etc (where possible) can help you to visualise the problem and make progress

Worked example

Find the volume of the solid of revolution formed by rotating the region bounded by the graph of y equals arcsin space open parentheses 2 x plus 1 close parentheses and the coordinate axes by 2 straight pi radians around the y-axis.  Give your answer to three significant figures.

yzeHWPTm_5-9-4-ib-hl-ai-aa-extraaa-we3-soltn

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Paul

Author: Paul

Paul has taught mathematics for 20 years and has been an examiner for Edexcel for over a decade. GCSE, A level, pure, mechanics, statistics, discrete – if it’s in a Maths exam, Paul will know about it. Paul is a passionate fan of clear and colourful notes with fascinating diagrams – one of the many reasons he is excited to be a member of the SME team.