DP IB Maths: AA HL

Revision Notes

2.7.1 Factor & Remainder Theorem

Test Yourself

Factor Theorem

What is the factor theorem?

  • The factor theorem is used to find the linear factors of polynomial equations
  • This topic is closely tied to finding the zeros and roots of a polynomial function/equation
    • As a rule of thumb a zero refers to the polynomial function and a root refers to a polynomial equation
  • For any polynomial function P(x)
    • (x - k) is a factor of P(x) if P(k) = 0
    • P(k) = 0 if (x - k) is a factor of P(x)

How do I use the factor theorem?

  • Consider the polynomial function P(x) = anxn + an-1xn-1 + … + a1xa0 and (x - k) is a factor
    • Then, due to the factor theorem P(k) = ankn + an-1kn-1 + … + a1k + a0 = 0
    • P left parenthesis x right parenthesis equals left parenthesis x minus k right parenthesis cross times Q left parenthesis x right parenthesis, where Q(x) is a polynomial that is a factor of P(x)
    • Hence, fraction numerator P left parenthesis x right parenthesis over denominator x minus k end fraction equals Q left parenthesis x right parenthesis , where Q(x) is another factor of P(x)
  • If the linear factor has a coefficient of x then you must first factorise out the coefficient
    • If the linear factor is left parenthesis a x blank – blank b right parenthesis blank equals a open parentheses x minus b over a close parentheses rightwards arrow P open parentheses b over a close parentheses equals 0

Exam Tip

  • A common mistake in exams is using the incorrect sign for either the root or the factor
  • If you are asked to find integer solutions to a polynomial then you only need to consider factors of the constant term

Worked example

Determine whether left parenthesis x minus 2 right parenthesis is a factor of the following polynomials:

a)
space f left parenthesis x right parenthesis equals x cubed minus 2 x squared minus x plus 2.

page1

b)
space g left parenthesis x right parenthesis equals 2 x cubed plus 3 x squared minus x plus 5.

2-7-1-ib-aa-hl-factor-theorem-b-we-solution

It is given that left parenthesis 2 x minus 3 right parenthesis is a factor of space h left parenthesis x right parenthesis equals 2 x cubed minus b x squared plus 7 x minus 6.

c)
Find the value of b.

mZEjMdDm_2-7-1-ib-aa-hl-factor-theorem-c-we-solution

Remainder Theorem

What is the remainder theorem? 

  • The remainder theorem is used to find the remainder when we divide a polynomial function by a linear function
  • When any polynomial P(x) is divided by any linear function (x - k) the value of the remainder R is given by P(k) = R
    • Note, when P(k) = 0 then (x - k) is a factor of P(x)

How do I use the remainder theorem?

  • Consider the polynomial function P(x) = anxn + an-1xn-1 + … + a1xa0 and the linear function (x - k
    • Then, due to the remainder theorem P(k) = ankn + an-1kn-1 + … + a1k + a0 = R
    • P left parenthesis x right parenthesis equals left parenthesis x minus k right parenthesis cross times Q left parenthesis x right parenthesis plus R, where Q(x) is a polynomial
    • Hence, fraction numerator P left parenthesis x right parenthesis over denominator x minus k end fraction equals Q left parenthesis x right parenthesis plus fraction numerator R over denominator x minus k end fraction , where R is the remainder
  • If the linear function has a coefficient of x then you must first factorise out the coefficient
    • If the linear function is left parenthesis a x blank – blank b right parenthesis blank equals a open parentheses x minus b over a close parentheses rightwards arrow P open parentheses b over a close parentheses equals R

Worked example

Let space f left parenthesis x right parenthesis equals 2 x to the power of 4 minus 2 x cubed minus x squared minus 3 x plus 1, find the remainder R when space f left parenthesis x right parenthesis is divided by:

a)
x minus 3.

2-7-1-ib-aa-hl-remainder-theorem-a-we-solution

b)
x plus 2.

2-7-1-ib-aa-hl-remainder-theorem-b-we-solutionThe remainder when space f left parenthesis x right parenthesis is divided by left parenthesis 2 x plus k right parenthesis is 893 over 8.

c)
Given that k greater than 0, find the value of k.

2-7-1-ib-aa-hl-remainder-theorem-c-we-solution

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