AQA AS Physics

Revision Notes

5.4.1 Electromotive Force & Internal Resistance

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Electromotive Force

  • When charge passes through a power supply such as a battery, it gains electrical energy
  • The electromotive force (e.m.f) is defined as:

The amount of chemical energy converted to electrical energy per coulomb of charge (C) when passing through a power supply

emf definition, downloadable AS & A Level Physics revision notes

  • This can also be written as:

Emf energy equation

 

  • E.m.f can be represented by the symbol ε (greek letter epsilon)
    • It is not actually a force, and is measured in volts (V)

  • E.m.f is equal to the potential difference across the cell when no current is flowing
  • E.m.f can be measured by connecting a high-resistance voltmeter around the terminals of the cell in an open circuit, as so:

Measuring emf, downloadable AS & A Level Physics revision notes

e.m.f is measured using a voltmeter connected in parallel with the cell

  • The terminal potential difference (p.d) is the potential difference across the terminals of a cell
    • If there was no internal resistance, the terminal p.d would be equal to the e.m.f

  • It is defined as:

V = IR

  • Where:
    • V = terminal p.d (V)
    • I = current (A)
    • R = resistance (Ω)

  • Since a cell has internal resistance, the terminal p.d is always lower than the e.m.f
  • In a closed circuit, current flows through a cell and a potential difference develops across the internal resistance
  • Since resistance opposes current, this reduces the energy per unit charge (voltage) available to the rest of the external circuit
  • This difference is called the ‘lost volts'
    • Lost volts is usually represented by little v
    • It is defined as

The work done per unit charge / coulomb to overcome the internal resistance / resistance inside the battery (when current flows)

    • In other words, this is the voltage lost in the cell due to internal resistance
    • So, from conservation of energy: v = e.m.f − terminal p.d

 v = ε – V = Ir (Ohm’s law)

  • Where:
    • v = lost volts (V)
    • I = current (A)
    • r = internal resistance of the battery (Ω)
    • ε = e.m.f (V)
    • V = terminal p.d (V)

  • The e.m.f is the sum of these potential differences, giving the equation below:

EMF equation, downloadable AS & A Level Physics revision notes

  • E.m.f can therefore be defined as the total, or maximum, voltage available to the circuit

Internal Resistance

  • All power supplies have some resistance between their terminals
    • This is called internal resistance (r)

  • Internal resistance is defined as:

The resistance of the materials within the battery

  • It is internal resistance that causes the charge circulating to dissipate some electrical energy from the power supply itself
    • This is why the cell becomes warm after a period of time

  • Therefore, over time the internal resistance causes loss of voltage or energy loss in a power supply
  • A cell can be thought of as a source of e.m.f with an internal resistance connected in series. This is shown in the circuit diagram below:

Internal Resistance Circuit, downloadable AS & A Level Physics revision notes

Circuit showing the e.m.f and internal resistance of a power supply

  • Where:
    • Resistor R is the 'load resistor'
    • r is the internal resistance
    • ε is the e.m.f
    • Vr is the lost volts
    • VR is the p.d across the load resistor, which is the same as the terminal p.d

Worked example

A battery of e.m.f 7.3 V and internal resistance r of 0.3 Ω is connected in series with a resistor of resistance 9.5 Ω.WE - internal resistance question image, downloadable AS & A Level Physics revision notesDetermine:

a)     The current in the circuit

b)     Lost volts from the battery

Worked example internal resistance (2), downloadable AS & A Level Physics revision notes

Exam Tip

If the exam question states 'a battery of negligible internal resistance', this assumes that e.m.f of the battery is equal to its voltage. Internal resistance calculations will not be needed here.If the battery in the circuit diagram includes internal resistance (like that in the worked example), then the e.m.f equations must be used.

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Author: Stewart

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