Defining Empirical & Molecular Formulae
- The molecular formula shows the number and type of each atom in a molecule
- E.g. the molecular formula of ethanoic acid is C2H4O2
- The empirical formula shows the simplest whole number ratio of the elements present in one molecule of the compound
- E.g. the empirical formula of ethanoic acid is CH2O
Worked Example
Deducing molecular & empirical formulaeDeduce the molecular and empirical formula of the following compounds:
Answer
Calculating Empirical & Molecular Formulae
Empirical formula
- Empirical formula is the simplest whole number ratio of the elements present in one molecule or formula unit of the compound
- It is calculated from knowledge of the ratio of masses of each element in the compound
- The empirical formula can be found by determining the mass of each element present in a sample of the compound
- It can also be deduced from data that gives the percentage compositions by mass of the elements in a compound
Worked Example
Empirical formula from mass
Determine the empirical formula of a compound that contains 10 g of hydrogen and 80 g of oxygen.

- The above example shows how to calculate empirical formula from the mass of each element present in the compound
- The example below shows how to calculate the empirical formula from percentage composition
Worked Example
Empirical formula from %
Determine the empirical formula of a compound that contains 85.7% carbon and 14.3% hydrogen.

Molecular formula
- The molecular formula gives the exact numbers of atoms of each element present in the formula of the compound
- The molecular formula can be found by dividing the relative molecular mass of the molecular formula by the relative formula mass of the empirical formula
- Multiply the number of each element present in the empirical formula by this number to find the molecular formula
Worked Example
The empirical formula of X is C4H10S and the relative molecular mass of X is 180.2
What is the molecular formula of X?
(Ar data: C = 12.0, H = 1.0, S = 32.1)
Answer
Step 1: Calculate relative mass of the empirical formula
-
- Relative empirical mass = (C x 4) + (H x 10) + (S x 1)
- Relative empirical mass = (12.0 x 4) + (1.0 x 10) + (32.1 x 1)
- Relative empirical mass = 90.1
Step 2: Divide relative molecular mass of X by relative empirical mass
-
- Ratio between Mr of X and the Mr of the empirical formula = 180.2 / 90.1
- Ratio between Mr of X and the Mr of the empirical formula = 2
Step 3: Multiply each number of elements by 2
-
- (C4 x 2) + (H10 x 2) + (S x 2)
- (C8) + (H20) + (S2)
- Molecular formula of X is C8H20S2
Hydrated salts & Water of Crystallisation
- Water of crystallisation is when some compounds can form crystals which have water as part of their structure
- A compound that contains water of crystallisation is called a hydrated compound
- The water of crystallisation is separated from the main formula by a dot when writing the chemical formula of hydrated compounds
- E.g. hydrated copper(II) sulfate is CuSO4∙5H2O
- A compound which doesn’t contain water of crystallisation is called an anhydrous compound
- E.g. anhydrous copper(II) sulfate is CuSO4
- A compound can be hydrated to different degrees
- E.g. cobalt(II) chloride can be hydrated by six or two water molecules
- CoCl2 ∙6H2O or CoCl2 ∙2H2O
- The conversion of anhydrous compounds to hydrated compounds is reversible by heating the hydrated salt:
- The degree of hydration can be calculated from experimental results:
- The mass of the hydrated salt must be measured before heating
- The salt is then heated until it reaches a constant mass
- The two mass values can be used to calculate the number of moles of water in the hydrated salt - known as the water of crystallisation
Worked Example
10.0 g of hydrated copper sulfate are heated to a constant mass of 5.59 g. Calculate the formula of the original hydrated copper sulfate.
(Mr data: CuSO4 = 159.6, H2O = 18.0)
Answer
List the components |
CuSO4 |
H2O |
Note the mass of each component |
5.59 g |
10 - 5.59 = 4.41 g |
Divide the component mass by the components Mr |
|
|
Divide by the lowest figure to obtain the ratio |
|
|
Hydrated salt formula |
CuSO4•7H2O |
Exam Tip
- Instead of elements, you start with the salt and water
- Instead of dividing by atomic masses, you divide by molecular / formula masses
- The rest of the calculation works the same way as the empirical formula calculation