Edexcel AS Chemistry

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1.10.4 Deducing Kc Expressions

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Deducing Kc Expressions

Equilibrium expression & constant

  • The equilibrium expression links the equilibrium constant, Kc, to the concentrations of reactants and products at equilibrium taking the stoichiometry of the equation into account
  • So, for a given reaction:

aA + bB ⇌ cC + dD

  • Kc is defined as follows:

Equilibria Equilibrium Expression, downloadable AS & A Level Chemistry revision notes

Equilibrium expression linking the equilibrium concentration of reactants and products at equilibrium

  • The Kc of a reaction is specific and only changes if the temperature of the reaction changes

Homogeneous systems and Kc 

  • A homogeneous system is where all of the reactants and products are in the same physical state, e.g.

CH3COOH (l) + C2H5OH (l) ⇌ CH3COOC2H5 (l) + H2O (l)

  • For this reaction, all of the reactants and products are in the same, liquid state / phase and will, therefore, all feature in the Kc expression
    • Kcfraction numerator left square bracket CH subscript 3 COOC subscript 2 straight H subscript 5 right square bracket space left square bracket straight H subscript 2 straight O right square bracket over denominator left square bracket CH subscript 3 COOH right square bracket space left square bracket straight C subscript 2 straight H subscript 5 OH right square bracket end fraction

Heterogeneous systems and Kc 

  • A heterogeneous system is where not all of the reactants and products are in the same physical state, e.g.

CaCO3 (s) ⇌ CaO (s) + CO2 (g)

  • Solids are ignored in equilibrium expressions
    • This leads to a Kc expression of Kc = [CO2]

Exam Tip

For Kc expressions, it is important that you use square brackets as sometimes examiners are instructed to be strict about the appearance of brackets in expressions

Square brackets implies concentration

Worked example

Deducing equilibrium expressions

Deduce the equilibrium expression for the following reactions:

  1. Ag+ (aq) + Fe2+ (aq) ⇌ Ag (s) + Fe3+ (aq)
  2. N2 (g) + 3H2 (g) ⇌ 2NH3 (g)
  3. 2SO2 (g) + O2 (g) ⇌ 2SO3 (g)

Answer 1:

    • Kcfraction numerator left square bracket Fe to the power of 3 plus end exponent space left parenthesis aq right parenthesis right square bracket over denominator left square bracket Fe to the power of 2 plus end exponent space left parenthesis aq right parenthesis right square bracket space left square bracket Ag to the power of plus space left parenthesis aq right parenthesis right square bracket end fraction
    • [Ag (s)] is not included in the equilibrium expression as it is a solid

Answer 2:

    • Kc =fraction numerator left square bracket NH subscript 3 space left parenthesis straight g right parenthesis right square bracket squared over denominator left square bracket straight N subscript 2 space left parenthesis straight g right parenthesis right square bracket space left square bracket straight H subscript 2 space left parenthesis straight g right parenthesis right square bracket cubed end fraction

Answer 3:

    • Kc =fraction numerator left square bracket SO subscript 3 space left parenthesis straight g right parenthesis right square bracket squared over denominator left square bracket SO subscript 2 space left parenthesis straight g right parenthesis right square bracket squared space left square bracket straight O subscript 2 space left parenthesis straight g right parenthesis right square bracket end fraction

Exam Tip

The value of Kc indicates the position of equilibrium:

   Kc = 1 - the position of equilibrium is halfway between the reactants and products

   Kc < 1 - the position of equilibrium lies towards the left-hand side, i.e. the reactants

   Kc > 1 - the position of equilibrium lies towards the right-hand side, i.e. the products

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