CIE A Level Maths: Pure 3

Topic Questions

5.1 Further Integration

1
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6 marks
(i)
Find the integral

integral 1 over x space space d x.

(ii)
Use calculus to evaluate

integral subscript 0 superscript 1 e to the power of x space space straight d x.

(iii)
Find an expression for y given that

y equals integral 3 cos space theta space space straight d theta space.

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2
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8 marks
i)
Integrate

      integral sin space space open parentheses 2 x plus 1 space close parentheses space d x.

ii)
Use calculus to find the exact value of

      integral subscript straight pi over 6 end subscript superscript straight pi over 4 end superscript space space s e c squared space open parentheses 2 theta space minus space straight pi over 6 close parentheses space d theta

iii)
Find an expression for y given that

      space fraction numerator d y over denominator d x end fraction equals 4 space cos space left parenthesis 5 x plus 2 right parenthesis space

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3
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8 marks
(i)
Integrate

integral 8 open parentheses 2 x minus 1 close parentheses cubed space space d x.

(ii)
Use calculus to find the exact value of

integral subscript 0 superscript straight pi over 4 end superscript sin space 2 x space space d x.

(iii)
Find an expression for y given that

fraction numerator d y over denominator d x end fraction equals space 3 e to the power of 3 x end exponent.

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4a
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3 marks

Given that u equals 3 x plus 2 show that

(i)
straight d u equals 3 space space straight d x,

(ii)
integral 3 cos space open parentheses 3 x plus 2 space close parentheses space space straight d x equals integral cos space u space straight d u.

4b
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3 marks

Hence find an expression in terms of x for the integral

integral 3 cos space open parentheses 3 x plus 2 space close parentheses space straight d x space.

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5a
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2 marks

Given the identity cos space 2 A identical to 1 minus 2 space sin squared A space, show that

sin squared A equals 1 half left parenthesis 1 minus cos space 2 A right parenthesis space.

5b
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3 marks

Hence find the exact value of

integral subscript straight pi over 2 end subscript superscript straight pi sin squared x space straight d x.

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6
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4 marks

Use the substitution space u equals 4 x plus 1 spaceto find

integral subscript 2 superscript 6 4 open parentheses 4 x plus 1 close parentheses to the power of 1 half end exponent d x

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7
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4 marks

Find an expression for y given that

   fraction numerator d y over denominator d x end fraction equals 7 e to the power of 3 x minus 4 end exponent.

Integrate

   integral space fraction numerator 1 over denominator 4 x plus 9 space space end fraction d x.

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8
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4 marks
(i)
Given that  straight f open parentheses x close parentheses equals 2 x squared plus 5, find straight f apostrophe open parentheses x close parentheses.

 

(ii)
Hence, or otherwise, find

integral fraction numerator 4 x over denominator 2 x squared plus 5 end fraction space straight d x.

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9
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6 marks

Use integration by parts to find an expression for

integral negative 3 x sin space x space straight d x.

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10
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5 marks

Find the exact value of

integral subscript 1 superscript 2 e to the power of 3 x plus 2 end exponent space d x

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11a
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2 marks

Integrate 

   integral space fraction numerator 1 over denominator x squared space plus space 5 squared end fraction space d x.

11b
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3 marks
i)
Show that 

      fraction numerator 4 over denominator 4 x squared space plus space 36 end fraction space equals space fraction numerator 1 over denominator x squared space plus space 3 squared end fraction

ii)
Hence find an expression for y given that

      fraction numerator d y over denominator d x end fraction space equals space fraction numerator 4 over denominator 4 x squared space plus space 36 end fraction space

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12
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6 marks

Use the substitution u equals sin space x to find the value of

   integral subscript 0 superscript straight pi over 2 end superscript space cos to the power of 2 space end exponent 2 x space cos space x space d x space space.

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13
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4 marks

Use integration by parts to show that

      integral space 2 x e to the power of 2 x end exponent space space d x equals 1 half e to the power of 2 x end exponent open parentheses 2 x minus 1 close parentheses plus c

where c is a constant.

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14
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5 marks
i)
Integrate

      integral space fraction numerator 1 over denominator 2 minus 3 x end fraction space space d x

ii)
Find an expression for space y spacegiven that

      y equals space integral space open parentheses fraction numerator 2 over denominator 2 x plus 1 end fraction minus space fraction numerator 1 over denominator 3 minus x end fraction close parentheses space space d x

giving your answer as a single logarithm.

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15a
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3 marks

Show that

      fraction numerator 2 x minus 1 over denominator left parenthesis x plus 1 right parenthesis left parenthesis x minus 2 right parenthesis end fraction

can be written in the form

      space space space fraction numerator A over denominator x plus 1 end fraction plus fraction numerator B over denominator x minus 2 end fraction

15b
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4 marks

Hence find

      integral space fraction numerator 2 x minus 1 over denominator left parenthesis x plus 1 right parenthesis left parenthesis x minus 2 right parenthesis space end fraction d x space space space space space space space space space space space space space space space space space space space space x greater than 2

writing your answer as a single logarithm.

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1a
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3 marks

Use calculus to find

         integral space open parentheses x squared plus 5 minus 3 over x squared space close parentheses space d x

1b
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2 marks

Write down

         integral space 3 e to the power of 3 x end exponent space d x

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2a
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2 marks

Find the integral

      integral space 5 left parenthesis e to the power of 5 x end exponent minus e to the power of negative 5 x end exponent right parenthesis space d x

2b
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2 marks

Find an expression for y given that

      y equals space integral space open parentheses sin space x plus cos space x close parentheses space space d x space

2c
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3 marks

Use calculus to evaluate

         integral subscript negative 8 end subscript superscript negative 2 end superscript 1 over x space d x

giving your answer as a single logarithm.

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3a
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2 marks

Integrate

      integral space 2 space sin space x space cos space x space space d x

3b
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4 marks

Use calculus to find the value of

      integral subscript 1 superscript 3 space open parentheses 4 x plus 1 close parentheses to the power of 5 space d x

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4
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5 marks

Use a suitable substitution to find the following


      integral space 8 x space sin space left parenthesis 3 x squared plus 1 right parenthesis space space d x

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5
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5 marks

Use the substitution space space u equals 2 plus ln space x space space to show that

      integral fraction numerator space 1 over denominator x open parentheses 2 plus ln space x close parentheses cubed space end fraction space d x equals negative fraction numerator 1 over denominator 2 open parentheses ln space x space plus 2 close parentheses squared end fraction plus c


where c is the constant of integration.

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6a
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3 marks

Show that, for theta not equal to k pi (where k is an integer),

         fraction numerator 2 minus 2 space cos squared space theta space over denominator sin space 2 theta end fraction space equals tan space theta

6b
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4 marks

Use calculus and your result from part (a) to show that

         integral subscript straight pi over 6 end subscript superscript straight pi over 3 end superscript space space fraction numerator 2 minus 2 space cos squared space theta over denominator sin space 2 theta end fraction space space d theta equals 1 half ln space 3 space

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7
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6 marks

Use calculus to find the exact value of

         integral subscript straight pi over 2 end subscript superscript fraction numerator 5 straight pi over denominator 6 end fraction end superscript space space fraction numerator 2 space cos space x over denominator 1 minus cos space 2 x end fraction space space space d x.

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8a
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2 marks

Find an expression for straight f left parenthesis x right parenthesis given that

         straight f open parentheses x close parentheses equals space integral fraction numerator 5 over denominator 2 x plus 3 end fraction space space d x

8b
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3 marks

Find an expression for y given that

      fraction numerator d y over denominator d x end fraction space equals space 2 e to the power of 3 x minus 5 end exponent minus 5 e to the power of 5 x end exponent

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9a
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2 marks

Show that

         sin squared space open parentheses 3 x plus 2 close parentheses identical to 1 half left parenthesis 1 minus cos left parenthesis 6 x plus 4 right parenthesis right parenthesis space space

9b
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3 marks

Hence, or otherwise, find an expression for

      integral sin squared space open parentheses 3 x plus 2 close parentheses space space d x space

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10a
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2 marks

Write  e to the power of 2 x end exponent open parentheses 1 plus e to the power of 2 x end exponent plus e squared close parentheses  in the form  space e to the power of straight f open parentheses x close parentheses end exponent plus e to the power of g open parentheses x close parentheses end exponent plus e to the power of h open parentheses x close parentheses end exponent comma spacewhere straight f open parentheses x close parentheses, straight g open parentheses x close parentheses and straight h open parentheses x close parenthesesare all linear functions of x.

10b
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4 marks

Hence show that

        integral subscript 0 superscript 1 space e to the power of 2 x end exponent open parentheses 1 plus e to the power of 2 x end exponent plus e squared close parentheses space d x equals 3 over 4 open parentheses e to the power of 4 minus 1 close parentheses

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11
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5 marks

Use calculus to show that

        integral subscript 0 superscript 1 fraction numerator 3 x e to the power of negative 3 x squared end exponent over denominator 3 minus 2 e to the power of negative 3 x squared end exponent end fraction space space d x equals 1 fourth ln space left parenthesis 3 minus 2 e to the power of negative 3 end exponent space right parenthesis.

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12a
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5 marks

Use integration by parts to find

         integral space open parentheses 2 x squared minus 1 close parentheses e to the power of x space d x

12b
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4 marks

Show that

         integral space ln space x space space d x equals x space ln space x space minus x plus c 

where c is the constant of integration.

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13a
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4 marks

Express

         fraction numerator x squared minus 4 x plus 7 over denominator open parentheses x minus 1 close parentheses open parentheses x minus 3 close parentheses squared end fraction

as partial fractions.

13b
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3 marks

Hence, or otherwise, find

         integral space fraction numerator x squared minus 4 x plus 7 over denominator open parentheses x minus 1 close parentheses open parentheses x minus 3 close parentheses squared space end fraction d x 

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14
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5 marks

Show that

            integral subscript 0 superscript square root of 3 over 2 end root end superscript fraction numerator 4 over denominator 9 plus 2 x squared end fraction space space d x equals fraction numerator straight pi square root of 2 over denominator 9 end fraction

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15
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4 marks

Given that space straight f apostrophe open parentheses x close parentheses equals 2 space tan space 3 x spaceand that  straight f open parentheses 0 close parentheses equals space 2 over 3 space show that


            straight f open parentheses x close parentheses equals 2 over 3 left parenthesis 1 plus ln space open vertical bar s e c space 3 x close vertical bar space right parenthesis space

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16
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5 marks

Given

 

      straight f left parenthesis x right parenthesis equals integral fraction numerator space 3 left parenthesis 8 x cubed plus 3 x right parenthesis over denominator 2 left parenthesis 4 x to the power of 4 plus 3 x squared plus 5 right parenthesis end fraction space space d x space space space space space space space space space space space space space space space x element of straight real numbers


and that the graph of  y equals straight f left parenthesis x right parenthesis  passes through the point (1, ln 144 ) find straight f left parenthesis x right parenthesis.

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This topic pack contains questions on the following:

  • Integrating Other Functions (Trig, ln & e etc)

  • Integrating with Trigonometric Identities

  • f'(x)/f(x)

  • Integration by Substitution (Reverse Chain Rule)

  • Harder Substitution

  • Integration by Parts

  • Integration using Partial Fractions

  • Integration Decision Making

1a
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2 marks

Integrate

   integral space fraction numerator 1 over denominator 2 x plus 3 space space end fraction d x

1b
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2 marks

Find an expression for space y spacegiven that

   fraction numerator d y over denominator d x end fraction equals 3 e to the power of 3 x plus 1 end exponent

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2a
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1 mark

Find the integral

   integral space sin space x space space d x

2b
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3 marks

Use calculus to evaluate

      integral subscript 1 superscript 4 space 1 over x space d x

2c
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2 marks

Find an expression for y given that

   y space equals space integral space 7 e to the power of 7 x end exponent space d x

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3a
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2 marks

Integrate

   integral space cos space 2 x space d x

3b
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4 marks

Use calculus to find the value of

   integral subscript 0 superscript 2 space open parentheses 3 x minus 1 close parentheses cubed space d x

3c
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2 marks

Find an expression for y given that

   fraction numerator d y over denominator d x end fraction equals e to the power of 5 x end exponent

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4
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5 marks

Use a suitable substitution to find

integral space minus 15 space sin space open parentheses 5 x minus 2 close parentheses space d x

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5a
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2 marks

Find an expression for straight f left parenthesis x right parenthesis given that

   straight f left parenthesis x right parenthesis space equals space integral space sin space open parentheses 2 x plus 1 close parentheses space d x

5b
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2 marks

Find an expression for y given that

   fraction numerator d y over denominator d x end fraction space equals space 3 space cos open parentheses 3 x plus 5 close parentheses

5c
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3 marks

Use calculus to find the exact value of

integral subscript fraction numerator 7 straight pi over denominator 6 end fraction end subscript superscript fraction numerator 4 straight pi over denominator 3 end fraction end superscript space s e c squared space open parentheses x minus straight pi close parentheses space d x

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6
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7 marks

Use calculus and the substitution space space u equals x plus 4 space to show that

      integral subscript 1 superscript 2 fraction numerator x over denominator x plus 4 end fraction space d x space equals space 1 space plus space 4 space In space 5 over 6

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7
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6 marks

Given that


      cos space 2 theta space identical to 2 space cos squared space theta minus 1

use calculus to find the exact value of

      integral subscript straight pi over 4 end subscript superscript straight pi over 2 end superscript space cos squared space theta space d theta

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8
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3 marks

Find

   integral space square root of 1 plus cot squared end root x space d x

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9
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4 marks
i)
Given that  straight f open parentheses x close parentheses equals 2 x cubed plus 4 x comma space find  straight f apostrophe open parentheses x close parentheses.

 

ii)
Hence, or otherwise, find

      integral space fraction numerator 3 x squared plus 2 over denominator 2 x cubed plus 4 x end fraction space d x

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10a
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2 marks

Use the identity 

      sin space 2 A space identical to 2 space sin space A space cos space A

to show that

   4 space sin space theta over 2 space cos space theta over 2 space identical to 2 sin space theta

10b
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3 marks

Hence, or otherwise, find the integral

   integral space 4 sin space theta over 2 space cos space theta over 2 space space d theta

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11
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3 marks

Show that


   integral subscript 2 superscript 5 space 4 e to the power of 2 x minus 4 end exponent space space d x equals 2 open parentheses e to the power of 6 minus 1 close parentheses

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12
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6 marks

Use integration by parts to find, in terms of e, the exact value of

   integral subscript 0 superscript 1 left parenthesis 5 x minus 4 right parenthesis e to the power of 3 x end exponent space d x

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13a
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3 marks

Show that

         fraction numerator 11 over denominator left parenthesis 2 x minus 3 right parenthesis left parenthesis x plus 4 right parenthesis end fraction

can be written in the form

         fraction numerator A over denominator 2 x minus 3 end fraction plus fraction numerator B over denominator x plus 4 end fraction

13b
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4 marks

Hence find

integral space fraction numerator 11 over denominator left parenthesis 2 x minus 3 right parenthesis left parenthesis x plus 4 right parenthesis end fraction space d x

writing your answer as a single logarithm.

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14
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4 marks

Use calculus to find the value of

      integral subscript 2 superscript 4 fraction numerator 1 over denominator 4 plus 9 x squared end fraction space space d x

giving your answer to three significant figures.

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15a
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4 marks

Given that the graph of space y equals straight f left parenthesis x right parenthesis  passes through the point (0, 4) and that

      straight f apostrophe open parentheses x close parentheses equals fraction numerator 12 x squared plus 7 over denominator 2 open parentheses 4 x cubed plus 7 x plus 4 close parentheses end fraction


Find straight f left parenthesis x right parenthesis

15b
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1 mark

Explain why space x equals negative 1 half  must be excluded from the domain of space straight f open parentheses x close parentheses.

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16
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4 marks

Show that

      integral space tan space x space space d x equals ln space open vertical bar s e c space x close vertical bar space plus c space

where c is a constant.

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1
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5 marks

Use calculus to find the value of

      integral subscript 2 superscript 6 space open parentheses 1 over x plus fraction numerator 4 over denominator 2 x end fraction plus fraction numerator 3 over denominator 3 x minus 2 end fraction space close parentheses space d x


giving your answer in the form  p space ln space p plus q ln space q  ,  where p and q are prime numbers to be found.

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2a
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3 marks

Find an expression for space y spacegiven that

      fraction numerator space d y over denominator d x end fraction equals 5 space cos to the power of 2 space end exponent 4 x space sin space 4 x space

2b
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3 marks

Integrate

      integral space 3 x open parentheses 5 x squared plus 4 close parentheses to the power of 4 space d x

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3a
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3 marks

Find an expression for y given that

         y equals integral space 6 x squared e to the power of x cubed end exponent space d x

3b
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3 marks

Integrate

         integral space open parentheses 16 minus 32 x close parentheses sin space open parentheses 4 x minus 2 close parentheses squared space space d x

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4
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5 marks

Use calculus and the substitution  x equals cos space theta   to find the exact value of

      integral subscript fraction numerator 1 over denominator square root of 2 end fraction end subscript superscript fraction numerator square root of 3 over denominator 2 end fraction end superscript space fraction numerator 1 over denominator square root of 1 minus x squared end root end fraction space d x

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5
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5 marks

Find

         integral open parentheses space 2 space tan space x space plus 3 space s e c space x close parentheses squared space d x

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6a
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3 marks

Show that

         integral space tan space k x space space d x equals 1 over k ln space open vertical bar s e c space k x close vertical bar space space plus c

where k is a constant, and c is the constant of integration.

6b
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5 marks

Use calculus to find the exact value of

         integral subscript straight pi over 18 end subscript superscript straight pi over 9 end superscript fraction numerator cos e c to the power of 2 space end exponent 3 theta over denominator 3 c o t space 3 theta end fraction space d theta

writing your answer in the form  a space l n space b , where a and b are rational numbers to be found.

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7a
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3 marks

Show that

open parentheses cos open parentheses space theta plus straight pi over 8 close parentheses space plus sin space open parentheses space theta plus straight pi over 8 close parentheses close parentheses open parentheses sin space open parentheses space theta plus straight pi over 8 close parentheses minus cos open parentheses space theta plus straight pi over 8 close parentheses close parentheses space identical to negative cos open parentheses space 2 theta plus straight pi over 4 space close parentheses

7b
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3 marks

Hence, or otherwise, find the exact value of

      integral subscript 0 superscript straight pi over 8 end superscript open parentheses sin to the power of space 2 end exponent space open parentheses theta plus straight pi over 8 close parentheses minus space cos squared open parentheses theta plus straight pi over 8 close parentheses space close parentheses space space d theta

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8a
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3 marks

Show that

   integral subscript 0 superscript 1 space e to the power of a x plus b end exponent space space d x space equals space e to the power of b space open parentheses fraction numerator e to the power of a space minus 1 over denominator a end fraction close parentheses

where a and b are constants, and a not equal to 0.

8b
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2 marks

Using your working from part (a), or otherwise, evaluate  

      integral subscript 0 superscript c e to the power of a x plus b end exponent space space d x

giving your answer in terms of a comma space b and c, where a comma b and c are constants, and a not equal to 0.

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9a
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3 marks

Show that

      open parentheses 1 plus cot open parentheses space 2 theta plus straight pi over 4 space close parentheses close parentheses open parentheses 1 minus cot space open parentheses space 2 theta plus straight pi over 4 space close parentheses close parentheses identical to 2 minus cos e c to the power of 2 space end exponent open parentheses 2 theta plus straight pi over 4 space close parentheses

9b
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3 marks

Hence, or otherwise, find an expression for straight f left parenthesis theta right parenthesis given that

      straight f apostrophe open parentheses theta close parentheses equals open parentheses 2 plus 2 space cot open parentheses 2 theta plus straight pi over 4 close parentheses close parentheses open parentheses space 2 minus 2 space cot space open parentheses 2 theta plus straight pi over 4 close parentheses close parentheses

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10a
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6 marks

Find

      integral space space x to the power of 2 space end exponent space sin space 3 x space space d x

10b
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4 marks

Find

      integral space fraction numerator ln space x over denominator space x cubed end fraction space d x

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11
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6 marks

Find the integral

      space integral space fraction numerator 8 x squared minus 8 x minus 1 over denominator left parenthesis 4 x squared minus 1 right parenthesis left parenthesis x minus 2 right parenthesis end fraction space d x

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12
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7 marks

Use integration by parts to show that

      integral space e to the power of x sin space x space space d x equals 1 half e to the power of x open parentheses sin space x space minus cos space x close parentheses space plus c

where c is the constant of integration.

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13
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7 marks

Show that there are no positive values of a and b that satisfy the equation

      integral subscript 0 superscript 1 fraction numerator space 2 a over denominator a x plus b end fraction space space d x equals integral subscript b superscript 2 a end superscript space fraction numerator 1 over denominator x space end fraction space d x

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14
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6 marks

Given that

      straight f apostrophe open parentheses theta close parentheses equals fraction numerator 9 over denominator 3 minus 3 space sin squared open parentheses space 3 theta minus straight pi over 6 close parentheses end fraction

and also that 

      open square brackets straight f open parentheses straight pi over 6 close parentheses close square brackets squared space minus open square brackets straight f open parentheses straight pi over 9 close parentheses close square brackets squared space equals space 8 over 3 open parentheses 1 minus square root of 3 close parentheses

find straight f open parentheses straight theta close parentheses.

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15a
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4 marks

Express  fraction numerator 7 y plus 13 over denominator 12 y squared plus 43 y plus 36 space end fraction in partial fractions.

15b
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4 marks

Use your answer from part (a) to help find

      integral space fraction numerator space space 7 x squared plus 13 over denominator 12 x to the power of 4 plus 43 x squared plus 36 end fraction space d x

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16
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6 marks

Given that space straight f apostrophe open parentheses x close parentheses equals 1 fourth tan space open parentheses x over 2 close parentheses space spaceand  space straight f open parentheses fraction numerator 2 pi over denominator 3 end fraction close parentheses equals 1 half ln space 6 space,  show that

      straight f open parentheses x close parentheses equals ln square root of space open vertical bar 3 s e c space open parentheses x over 2 close parentheses close vertical bar space space end root

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