OCR A Level Chemistry

Revision Notes

6.9.6 Combined Techniques

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Deducing Organic Structures

  • Organic chemists use a variety of techniques to determine an organic structure
    • In real laboratory practice, certain pieces of information might already be known as target molecules are often tested once they are produced to check that the reaction has gone as planned
  •  The typical sequence using the common analytical techniques would be:
    1. Elemental analysis - to determine the empirical formula
    2. Mass spectrometry - to determine the molecular mass, and consequently the molecular formula, as well as fragments of the molecule
    3. Infrared spectrometry - to primarily identify functional groups but also identify types of bond, e.g. C-C, C=C
    4. NMR spectrometry - to determine the number of carbon / hydrogen atoms and their environments 
  • Each technique provides valuable information that can be used to propose a structure, although some techniques provide more information than others
    • Elemental analysis is sometimes skipped as the combination of mass spectrometry and NMR can suggest the molecular formula without the need for elemental analysis

Worked example

An unknown compound, X, of molecular formula, C4H8O, has the following MS, IR and 1H NMR spectra.

21-1-3-worked-example-image-1

MS of X

21-1-3-worked-example-image-2

IR spectrum of X

21-1-3-worked-example-image-3

1H NMR spectrum of X

Deduce the structure of X using the information given and any other additional information in the Data booklet. For each spectrum assign as much spectroscopic information as possible.

Answer

Mass Spectrum

      • The molecular ion peak is at m/z = 72, which corresponds to the relative molecular mass of C4H8O

Mr = (12 × 4) + (8 × 1) +(16) = 72

      • The large peak at  m/z = 43 could correspond to CH3CH2CH2+ or CH3CO+ indicating the loss of CH4O or C2H5 from X, that is (Mr - 43)
      • The peak at  m/z = 29 could correspond to CH3CH2+  indicating the loss of C2H3O from X, that is (Mr - 29)

IR Spectrum

      • There is a strong absorption in the range 1700-1750 cm-1 which corresponds to C=O, based on Section 26 of the Data book
      • This suggests an aldehyde or ketone is present (it cannot be an ester or carboxylic acid as only one oxygen is in the formula)

1H NMR Spectrum

      • The 1H NMR spectrum shows three protons environments
      • The peak around chemical shift 1.0 ppm could correspond to a proton on the end of a chain, -CH3
      • The peaks around chemical shift 2.2 - 2.7 ppm could correspond to a proton next to a carbonyl group RCH2CO-
      • The peak splitting is a quartet, singlet and triplet
      • A quartet and triplet in the same spectrum usually corresponds to an ethyl group, CH3CH2, following the n+1 rule
      • The singlet indicates an isolated proton environment

Putting the information together the structure of X is

21-1-3-worked-example-answer

The structure of X is butanone

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