Equilibrium Constant Expressions
Equilibrium expression & constant
- The equilibrium expression links the equilibrium constant, Kc, to the concentrations of reactants and products at equilibrium taking the stoichiometry of the equation into account
- So, for a given reaction:
aA + bB ⇌ cC + dD
the Kc is defined as follows:
Equilibrium expression linking the equilibrium concentration of reactants and products at equilibrium
- Solids are ignored in equilibrium expressions
- The Kc of a reaction is specific and only changes if the temperature of the reaction changes
Worked Example
Deducing equilibrium expressions
Deduce the equilibrium expression for the following reactions:
- Ag+ (aq) + Fe2+ (aq) ⇌ Ag (s) + Fe3+ (aq)
- N2 (g) + 3H2 (g) ⇌ 2NH3 (g)
- 2SO2 (g) + O2 (g) ⇌ 2SO3 (g)
Equilibrium Constant Calculations
Calculations involving Kc
- In the equilibrium expression each figure within a square bracket represents the concentration in mol dm-3
- The units of Kc therefore depend on the form of the equilibrium expression
- Some questions give the number of moles of each of the reactants and products at equilibrium together with the volume of the reaction mixture
- The concentrations of the reactants and products can then be calculated from the number of moles and total volume
Equation to calculate concentration from number of moles and volume
Worked Example
Calculating Kc of ethanoic acid
In the reaction:
CH3COOH (I) + C2H5OH (I) ⇌ CH3COOC2H5 (I) + H2O (I)
ethanoic acid ethanol ethyl ethanoate water
500 cm3 of the reaction mixture at equilibrium contained 0.235 mol of ethanoic acid and 0.035 mol of ethanol together with 0.182 mol of ethyl ethanoate and 0.182 mol of water. Use this data to calculate a value of Kc for this reaction.
Answer
Step 1: Calculate the concentrations of the reactants and products
-
- [CH3COOH (l)] =
- [C2H5OH (l)] =
- [CH3COOC2H5 (l)] =
- [H2O (l)] =
- [CH3COOH (l)] =
Step 2: Write the equilibrium constant for this reaction in terms of concentration
-
- Kc =
- Kc =
Step 3: Substitute the equilibrium concentrations into the expression
-
- Kc =
- Kc =
Step 4: Deduce the correct units for Kc
-
- Kc =
- All units cancel out
- Kc =
Therefore, Kc = 4.03
Exam Tip
Note that the smallest number of significant figures used in the question is 3, so the final answer should also be given to 3 significant figures
- Some questions give the initial and equilibrium concentrations of the reactants but not the products
- An initial, change and equilibrium table should be used to determine the equilibrium concentration of the products using the molar ratio of reactants and products in the stoichiometric equation
Worked Example
Calculating Kc of ethyl ethanoate
Ethyl ethanoate is hydrolysed by water:
CH3COOC2H5 (I) + H2O (I) ⇌ CH3COOH (I) + C2H5OH (I)
ethyl ethanoate water ethanoic acid ethanol
0.1000 mol of ethyl ethanoate are added to 0.1000 mol of water. A little acid catalyst is added and the mixture made up to 1.00 dm3. At equilibrium, 0.0654 mol of water are present.
Use this data to calculate a value of Kc for this reaction.
Answer
Step 1: Write out the balanced chemical equation with the concentrations of beneath each substance using an initial, change and equilibrium table
Step 2: Calculate the concentrations of the reactants and products
-
- [CH3COOC2H5 (l)] =
- [H2O (l)] =
- [CH3COOH (l)] =
- [C2H5OH (l)] =
- [CH3COOC2H5 (l)] =
Step 3: Write the equilibrium constant for this reaction in terms of concentration
-
- Kc =
- Kc =
Step 4: Substitute the equilibrium concentrations into the expression
-
- Kc =
- Kc =
Therefore, Kc = 0.28
Estimating the position of equilibrium
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The magnitude of Kc indicates the relative concentrations of reactants and products in the mixture
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If Kc is very large (Kc >>1) the equilibrium lies to the RHS so the reaction mixture contains mostly products
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If Kc is very small (Kc << 1) the equilibrium lies to the LHS so the reaction mixture contains mostly reactants
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If Kc is close to 1 the mixture contains a similar concentration of both reactant and products
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